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While a person is walking, his arms swing through approximately a \(45^{\circ}\) angle in \(\frac{1}{2}\) s. As a reasonable approximation, we can assume that the arm moves with constant speed during each swing. A typical arm is 70.0 \(\mathrm{cm}\) long, measured from the shoulder joint. (a) What is the acceleration of a \(1.0-\mathrm{g}\) drop of blood in the fingertips at the bottom of the swing? (b) Draw a free-body diagram of the drop of blood in part (a). ( c)Find the force that the blood vessel must exert on the drop of blood in part (a). Which way does this force point? (d) What force would the blood vessel exert if the arm were not swinging?

Short Answer

Expert verified
(a) The acceleration is approximately 1.73 m/s². (b) Centripetal force towards the center; weight downward. (c) The vessel exerts about 0.00173 N toward the center. (d) Without swinging, the force is 0.00981 N downward.

Step by step solution

01

Find the Linear Velocity of the Swing

To find the velocity, first convert the swing angle from degrees to radians: \[ \theta = 45^{\circ} \times \frac{\pi}{180^{\circ}} = \frac{\pi}{4} \text{ rad} \]The length of the arc (distance traveled by the hand) is:\[ s = r \theta = 0.7 \times \frac{\pi}{4} \]Given that the swing takes \( \frac{1}{2} \text{ s} \), the linear speed \(v\) is:\[ v = \frac{s}{t} \]
02

Calculate Angular Velocity

Calculate the linear speed from the arc length obtained in Step 1:\[ v = \frac{0.7 \times \frac{\pi}{4}}{0.5} \approx 1.10 \text{ m/s} \].Next, find the angular velocity \(\omega\) using the relationship:\[ \omega = \frac{v}{r} = \frac{1.10}{0.7} \approx 1.57 \text{ rad/s} \]
03

Determine Centripetal Acceleration

Centripetal acceleration \(a_c\) at the bottom of the swing is given by:\[ a_c = r \omega^2 \]Substitute the known values:\[ a_c = 0.7 \times (1.57)^2 \approx 1.73 \text{ m/s}^2 \]
04

Draw the Free-Body Diagram

Draw a circle representing the drop of blood at the bottom of the swing. Indicate the direction of the centripetal force towards the center of rotation and label the weight of the drop of blood acting downward.
05

Calculate the Required Force

To find the force exerted by the blood vessel:Using \( F = ma \), where \( m = 1 \) gram = \( 0.001 \) kg and \( a = a_c \):\[ F = 0.001 \times 1.73 \approx 0.00173 \text{ N} \]This force is directed towards the center of the circular path.
06

Force Exerted without Swinging

When the arm is not swinging, the only force acting on the drop of blood is its weight:\[ F = mg = 0.001 \times 9.81 \approx 0.00981 \text{ N} \]This force points downward, opposite the centripetal force direction during swinging.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Velocity
Linear velocity refers to the speed at which an object moves along a path. For the problem of the swinging arm, the hand travels along an arc with a constant speed. This speed is what we call linear velocity. To calculate it, we first need to determine the distance covered, which is calculated as the arc length using the formula \( s = r \theta \). The linear velocity \( v \) is then given by the formula \( v = \frac{s}{t} \).

Here, \( \theta \) is the angle in radians (which we have from converting 45 degrees to \( \frac{\pi}{4} \) radians), and \( t \) is the time it takes for the swing. With these values, we compute the linear velocity, finding it to be \( 1.10 \) m/s. This speed indicates how fast the hand moves along its path during each swing. Understanding linear velocity is crucial in calculating how forces like centripetal force act on the drop of blood at the fingertips.
Angular Velocity
Angular velocity relates to how fast an object rotates or spins around a central point. While linear velocity shows how fast something moves along a path, angular velocity \( \omega \) focuses on rotational speed, measured in radians per second. To find angular velocity, we use the relationship \( \omega = \frac{v}{r} \), where \( v \) is the linear velocity we calculated earlier, and \( r \) is the radius of the swing, the length of the arm in this case.

In this exercise, applying the values, we derive an angular velocity of approximately \( 1.57 \) rad/s. This means the arm rotates at this rate when the person walks. Knowing the angular velocity helps us understand how rapidly the hand changes its position in a circular motion. It's a vital factor when it comes to determining centripetal acceleration, which depends on the square of the angular velocity.
Free-Body Diagram
A free-body diagram is a visual tool used in physics that represents forces acting on an object. In this problem, we focus on the drop of blood at the bottom of the swing. The diagram depicts the various forces to help us understand motion dynamics.

- **Centripetal Force**: This force acts towards the center of the circular path the hand follows. It's crucial for keeping the blood drop in circular motion.
- **Weight of the Blood Drop**: Acting vertically downward due to gravity, this force depends on the blood's mass and gravity. In this context, these forces are crucial for solving how the body responds to motion. By visualizing these forces, we get insights into interactions affecting the blood drop during the swing. Free-body diagrams help analyze forces comprehensively, guiding us through calculations like force exerted by the blood vessel.
Force Calculation
Force calculation involves determining the total force exerted on an object, such as the drop of blood in this scenario. The total force combines the effects of various individual forces.

- **Force During Swinging**: When the arm swings, the blood vessel must exert a centripetal force on the drop to maintain its circular motion. Using the equation \( F = ma \), with \( m \) as mass and \( a \) as centripetal acceleration (calculated as \( a_c = r \omega^2 \)), we find the force to be approximately \( 0.00173 \) N.
- **Force Without Swinging**: If the arm is stationary, the only force acting on the blood drop is its weight, calculated using \( F = mg \). This gives us a value of \( 0.00981 \) N. This difference showcases how motion affects force interactions in circular dynamics. Calculating forces like this is essential to understanding the physics of motion and forces acting on bodies in motion.

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