/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 A 1125 -kg car and a 2250 -kg pi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 1125 -kg car and a 2250 -kg pickup truck approach a curve on the expressway that has a radius of 225 \(\mathrm{m}\) . (a) At what angle should the highway engineer bank this curve so that vehicles traveling at 65.0 \(\mathrm{mi} / \mathrm{h}\) can safely round it regardless of the condition of their tires? Should the heavy truck go slower than the lighter car? (b) As the car and truck round the curve at find the normal force on each one due to the highway surface.

Short Answer

Expert verified
(a) Bank angle: 21.0°, the truck doesn't need to slow down. (b) Car's normal force: 11875.45 N, Truck's normal force: 23750.9 N.

Step by step solution

01

Convert Speed to Meters per Second

First, we need to convert the speed from miles per hour to meters per second. The conversion factor is: \( \frac{1609.34 \text{ meters}}{1 \text{ mile}} \) and \( \frac{1 \text{ hour}}{3600 \text{ seconds}} \). Using this, \[65 \text{ mi/h} \times \frac{1609.34 \text{ m}}{1 \text{ mi}} \times \frac{1 \text{ h}}{3600 \text{ s}} = 29.06 \text{ m/s}.\]
02

Find the Banking Angle

To find the angle at which the highway should be banked, use the formula: \\[\tan(\theta) = \frac{v^2}{rg}, \\]where \(v = 29.06 \, \text{m/s}\), \(r = 225 \, \text{m}\), and \(g = 9.81 \, \text{m/s}^2\). Solving for \(\theta\): \[\tan(\theta) = \frac{29.06^2}{225 \times 9.81} \= \frac{844.8}{2207.25} \= 0.3828.\]Thus, \(\theta = \tan^{-1}(0.3828) = 21.0^\circ\).
03

Evaluate if Truck Should Go Slower

Since the banking angle ensures that both vehicles can round the curve without relying on friction, the truck does not need to go slower than the car for stability around the curve.
04

Calculate Normal Force for the Car

The normal force \(F_n\) for the car is given by the formula \( F_n = \frac{mg}{\cos(\theta)} \.\) For the car, \(m = 1125 \, \text{kg}, \, g = 9.81 \, \text{m/s}^2\), and \(\theta = 21.0^\circ\). Compute \( F_n\): \[F_{n, \text{car}} = \frac{1125 \times 9.81}{\cos(21.0^\circ)} = 11875.45 \, \text{N}.\]
05

Calculate Normal Force for the Truck

Similarly, the normal force \(F_n\) for the truck is given by the same formula. For the truck, \(m = 2250 \, \text{kg}\). Compute \( F_n\): \[F_{n, \text{truck}} = \frac{2250 \times 9.81}{\cos(21.0^\circ)} = 23750.9 \, \text{N}.\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Force
In physics, the normal force is a contact force that acts perpendicular to the surface of contact. When a car drives around a banked curve, the normal force is crucial because it helps keep the vehicle on the path without slipping. The normal force counteracts the gravitational force acting downwards.

To calculate the normal force (\[ F_n \]) on a banked curve, the formula used is \[ F_n = \frac{mg}{\cos(\theta)} \], where \( m \) is the mass of the vehicle, \( g \) is the acceleration due to gravity, and \( \theta \) is the banking angle.

For example:
  • For a car with a mass of 1125 kg on a curve with a banking angle of 21.0°, the normal force needs to be calculated to ensure safe navigation around the curve.

  • The heavier the vehicle, like a 2250 kg truck, the larger the normal force must be to support it as it rounds the curve.

Understanding normal force is essential because, if miscalculated, a vehicle could skid off the curve due to lack of sufficient support.
Circular Motion
Circular motion describes an object moving along a curved path. In the context of banked curves, vehicles experience circular motion as they round the curve, and the centripetal force keeps them on the curved path.

For circular motion at a constant speed, the centripetal force required is provided by the combination of the normal force and the gravitational force acting on the car. The centripetal force formula is \( F_c = \frac{mv^2}{r} \), where \( m \) is the mass, \( v \) is the velocity, and \( r \) is the radius of the curve.

Banked curves help vehicles take turns at higher speeds because:
  • The incline of the curve naturally provides a component of force that pushes the vehicle inward, contributing to the centripetal force without relying on friction.

  • This design allows vehicles to maintain a stable path, even at elevated speeds, ideal for scenarios where tire-road friction could be minimal, such as when roads are wet.

Understanding circular motion is fundamental to designing safe road curves and contributes to the safe travel of vehicles at designed speeds.
Banking Angle
The banking angle of a curve refers to the angle at which the road is inclined relative to the horizontal plane. This angle plays a crucial role in helping vehicles navigate curves safely.

To determine the optimal banking angle, highway engineers use the formula \[ \tan(\theta) = \frac{v^2}{rg} \], where \( v \) is the speed of the vehicle, \( r \) is the radius of the curve, and \( g \), is the acceleration due to gravity.

A curve with the correct banking angle:
  • Allows cars to round it without the need for lateral friction, solely relying on gravitational and normal forces for stability.

  • Ensures that both lighter vehicles, like cars, and heavier ones, like trucks, can manage the turn at specified speeds without losing traction.

Optimally banking a curve minimizes the risk of skidding and helps maintain uniform traffic flow, enhancing safety and efficiency on highways.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are part of a design team for future exploration of the planet Mars, where \(g=3.7 \mathrm{m} / \mathrm{s}^{2} .\) An explorer is to step out of a survey vehicle traveling horizontally at 33 \(\mathrm{m} / \mathrm{s}\) when it is 1200 \(\mathrm{m}\) above the surface and then freely for 20 \(\mathrm{s}\) . At that time, a portable advanced propulsion system (PAPS) is to exert a constant force that will decrease the explorer's speed to zero at the instant she touches the surface. The total mass (explorer, suit, equipment, and PAPS) is 150 \(\mathrm{kg} .\) Assume the change in mass of the PAPS to be negligible. Find the horizontal and vertical components of the force the PAPS must exert, and for what interval of time the PAPS must exert it. You can ignore air resistance.

A small button placed on a horizontal rotating platform with diameter 0.320 \(\mathrm{m}\) will revolve with the platform when it is brought up to a speed of 40.0 rev/min, provided the button is no more than 0.150 \(\mathrm{m}\) from the axis. (a) What is the coefficient of static friction between the button and the platform? (b) How far from the axis can the button be placed, without slipping, if the platform rotates at 60.0 \(\mathrm{rev} / \mathrm{min}\) ?

A physics major is working to pay his college tuition by performing in a traveling carnival. He rides a motorcycle inside a hollow, transparent plastic sphere. After gaining sufficient speed, he travels in a vertical circle with a radius of 13.0 \(\mathrm{m} .\) The physics major has mass \(70.0 \mathrm{kg},\) and his motorcycle has mass 40.0 \(\mathrm{kg}\) . (a) What minimum speed must he have at the top of the circle if the tires of the motorcycle are not to lose contact with the sphere? (b) At the bottom of the circle, his speed is twice the value calculated in part (a). What is the magnitude of the normal force exerted on the motorcycle by the sphere at this point?

Two blocks with masses 4.00 \(\mathrm{kg}\) and 8.00 \(\mathrm{kg}\) are connected by a string and slide down a \(30.0^{\circ}\) inclined plane (Fig. \(\mathrm{P5.98).~The~}\) coefficient of kinetic friction between the \(4.00-\) kg block and the plane is \(0.25 ;\) that between the 8.00 -kg block and the plane is 0.35 (a) Calculate the acceleration of each block. (b) Calculate the tension in the string. (c) What happens if the positions of the blocks are reversed, so the \(4.00-\mathrm{kg}\) block is above the 8.00 -kg block?

One December identical twins Jena and Jackie are playing on a large merry-go- round (a disk mounted parallel to the ground, on a vertical axle through its center) in their school playground in northern Minnesota. Each twin has mass 30.0 \(\mathrm{kg}\) . The icy coating on the merry-go-round surface makes it frictionless. The merry-go-round revolves at a constant rate as the twins ride on it. Jena, sitting 1.80 \(\mathrm{m}\) from the center of the merry-go-round, must hold on to one of the metal posts attached to the merry-go-round with a horizontal force of 60.0 \(\mathrm{N}\) to keep from sliding off. Jackie is sitting at the edge, 3.60 \(\mathrm{m}\) from the center. (a) With what horizontal force must Jackie hold on to keep from falling off? (b) If Jackie falls off, what will be her horizontal velocity when she becomes airborne?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.