/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 An astronaut is inside a \(2.25 ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An astronaut is inside a \(2.25 \times 10^{6} \mathrm{kg}\) rocket that is blasting off vertically from the launch pad. You want this rocket to reach the speed of sound \((331 \mathrm{m} / \mathrm{s})\) as quickly as possible, but you also do not want the astronaut to black out. Medical tests have shown that astronauts are in danger of blacking out at an acceleration greater than 4\(g .\) (a) What is the maximum thrust the engines of the rocket can have to just barely avoid blackout? Start with a free-body diagram of the rocket. (b) What force, in terms of her weight \(w,\) does the rocket exert on the astronatt? Start with a free-body diagram of the astronaut. (c) What is the shortest time it can take the rocket to reach the speed of sound?

Short Answer

Expert verified
(a) Maximum thrust is \(1.102125 \times 10^8 \text{N}\). (b) Force on astronaut is \(5w\). (c) Shortest time is \(8.44 \text{s}\).

Step by step solution

01

Define Variables and Constants

For all calculations, define:- Gravitational acceleration, \( g = 9.81 \, \text{m/s}^2 \).- Mass of the rocket, \( m = 2.25 \times 10^6 \, \text{kg} \).- Speed of sound, \( v_s = 331 \, \text{m/s} \).- Maximum safe acceleration for the astronaut, \( a_{max} = 4g = 4 \times 9.81 \, \text{m/s}^2 \).
02

Newton's Second Law for Rocket

To find the maximum thrust, use Newton's second law:\[F_{net} = m \cdot a = T - mg\]where \( T \) is thrust, \( m \cdot g \) is gravitational force. Substitute \( a = 4g \):\[m \cdot 4g = T - mg \, \Rightarrow \, T = m \cdot 5g\]
03

Calculate Maximum Thrust

Substitute the known values:\[T = 2.25 \times 10^6 \, \text{kg} \times 5 \times 9.81 \, \text{m/s}^2\]Calculate:\[T = 1.102125 \times 10^8 \, \text{N}\]
04

Free-Body Diagram for Astronaut

Consider the rocket exerting a force on the astronaut equivalent to the astronaut's weight plus the effective force from acceleration. If \( w = m_a \cdot g \):\[F_{exerted} = m_a \cdot 5g = 5w\]
05

Determine Shortest Time to Reach Speed of Sound

From physics, \( v = a \cdot t \). Solve for \( t \) using \( a = 4g \):\[t = \frac{v_s}{4g} = \frac{331}{4 \times 9.81}\]Calculate:\[t \approx 8.44 \, \text{s}\]
06

Compile Results

Summarize the answers:(a) Maximum thrust without blacking out: \( 1.102125 \times 10^8 \, \text{N} \).(b) Force on astronaut as a multiple of weight: \( 5w \).(c) Shortest time to reach speed of sound: \( \approx 8.44 \, \text{s}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Limits
Acceleration limits are crucial when it comes to human spaceflight. Astronauts experience significant forces during launch, expressed as multiples of gravity, or "g-forces." In this case, medical research shows that astronauts risk blacking out at accelerations above four times gravity, or 4g.

Understanding these limits helps ensure astronaut safety during rapid acceleration. The human body can tolerate some significant acceleration, but above certain thresholds, the risk of loss of consciousness increases due to reduced blood flow to the brain. Reducing acceleration within safe limits is essential during a rocket's launch phase.

Thus, engineers need to design the rocket engines to produce enough thrust to achieve their mission goals without exceeding these critical limits.
Newton's Second Law
Newton's second law of motion is a fundamental concept used to understand how forces affect motion. It states that the force on an object is equal to the mass of the object multiplied by its acceleration, expressed as \( F = m \cdot a \).

In the context of a rocket, this law can calculate the net force required to produce a certain acceleration. For a rocket blasting off, the net force must not only overcome gravity but also provide the additional acceleration needed for liftoff.

To ensure the astronaut remains safe, the rocket's thrust must be precisely calculated to remain within safe acceleration limits while still providing the needed force for ascent. This ensures that the rocket achieves its desired velocity while keeping g-forces within safe boundaries for its human occupants.
Free-Body Diagram
A free-body diagram represents the forces acting on a single object, helping visualize and solve physics problems. In this rocket scenario, free-body diagrams for both the rocket and the astronaut are crucial.

For the rocket, the diagram shows two main forces: the upward thrust from the engines and the downward gravitational force, \( mg \). Calculating the net force involves subtracting gravity from thrust.

For the astronaut, the diagram helps us understand how the rocket's force translates into the astronaut's experience. Here, the force experienced is the combination of gravitational force, \( m_a \cdot g \), and the additional force due to acceleration, resulting in a total of \( 5w \) when \( w \) is their weight in normal conditions.
Maximum Thrust Calculation
Calculating maximum thrust involves ensuring that the rocket's force remains within safe acceleration limits while achieving mission objectives. This calculation uses the formula derived from Newton's second law.

Given that the astronaut's safe acceleration is 4g, we include gravitational force \( mg \) as part of the total required force. This yields the formula for maximum thrust, \( T = m \cdot 5g \). This approach ensures the rocket can accelerate to the speed of sound without exceeding safe limits.

By substituting known values like rocket mass and gravitational acceleration, the calculation gives an engine thrust of approximately \( 1.102125 \times 10^8 \, \text{N} \), which is sufficient for reaching desired speeds safely and efficiently.
Speed of Sound
The speed of sound is significant because it's a milestone for aerospace vehicles that indicates rapid velocity. It's approximately 331 m/s at sea level in air.

Reaching the speed of sound as quickly as possible is often a target in space missions, particularly during liftoff. However, reaching it must be done within acceleration limits to avoid endangering the crew's health.

Using the rocket's designed acceleration, to reach 331 m/s safely, the law \( v = a \cdot t \) helps determine the shortest time, mathematically calculated to be around 8.44 seconds, emphasizing efficient engineering and mission planning.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You observe a 1350 -kg sports car rolling along flat pavement in a straight line. The only horizontal forces acting on it are a constant rolling friction and air resistance (proportional to the square of its speed). You take the following data during a time interval of \(25 \mathrm{s} :\) When its speed is \(32 \mathrm{m} / \mathrm{s},\) the car slows down at a rate of \(-0.42 \mathrm{m} / \mathrm{s}^{2},\) and when its speed is decreased to \(24 \mathrm{m} / \mathrm{s},\) it slows down at \(-0.30 \mathrm{m} / \mathrm{s}^{2} .\) (a) Find the coefficient of rolling friction and the air drag constant \(D\) . (b) At what constant speed will this car move down an incline that makes a \(2.2^{\circ}\) angle with the horizontal? (c) How is the constant speed for an incline of angle \(\beta\) related to the terminal speed of this sports car if the car drops off a high cliff? Assume that in both cases the air resistance force is proportional to the square of the speed, and the air drag constant is the same.

A pickup truck is carrying a toolbox, but the rear gate of the truck is missing, so the box will slide out if it is set moving. The coefficients of kinetic and static friction between the box and the bed of the truck are 0.355 and 0.650 , respectively. Starting from rest, what is the shortest time this truck could accelerate uniformly to 30.0 \(\mathrm{m} / \mathrm{s}\) without causing the box to slide? Include a free-body diagram of the toolbox as part of your solution.

A 3.00 -kg box that is several hundred meters above the surface of the earth is suspended from the end of a short vertical rope of negligible mass. A time-dependent upward force is applied to the upper end of the rope, and this results in a tension in the rope of \(T(t)=(36.0 \mathrm{N} / \mathrm{s}) t .\) The box is at rest at \(t=0 .\) The only forces on the box are the tension in the rope and gravity. (a) What is the velocity of the box at ( i \(t=1.00 \mathrm{s}\) and (ii) \(t=3.00 \mathrm{s} ?\) (b) What is the maximum distance that the box descends below its initial position? (c) At what value of \(t\) does the box return to its initial position?

Two 25.0 -N weights are suspended at opposite ends of a rope that passes over a light, frictionless pulley. The pulley is attached to a chain that goes to the ceiling. (a) What is the tension in the rope? (b) What is the tension in the chain?

A box with weight \(w\) is pulled at constant speed along a level floor by a force \(\vec{\boldsymbol{F}}\) that is at an angle \(\theta\) above the horizontal. The coefficient of kinetic friction between the floor and box is \(\mu_{\mathrm{k}}\) (a) In terms of \(\theta, \mu_{\mathrm{k}},\) and \(w\) calculate \(F .\) (b) For \(w=400 \mathrm{N}\) and \(\mu_{\mathrm{k}}=0.25,\) calculate \(F\) for \(\theta\) ranging from \(0^{\circ}\) to \(90^{\circ}\) in increments of \(10^{\circ} .\) Graph \(F\) versus \(\theta\) .(c) From the general expression in part (a), calculate the value of \(\theta\) for which the value of \(F\) , required to maintain constant speed, is a minimum. (Hint: At a point where a function is minimum, what are the first and second derivatives of the function? Here \(F\) is a function of \(\theta . )\) For the special case of \(w=400 \mathrm{N}\) and \(\mu_{\mathrm{k}}=0.25\) evaluate this optimal \(\theta\) and compare your result to the graph you constructed in part (b).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.