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The spectrum of the sodium atom is detected in the light from a distant galaxy. (a) If the \(590.0-\) nm line is redshifted to \(658.5 \mathrm{nm},\) at what speed is the galaxy receding from the earth? (b) Use the Hubble law to calculate the distance of the galaxy from the earth.

Short Answer

Expert verified
The galaxy is receding at approximately \(3.483 \times 10^7\, m/s\) and is about \(497.57\, Mpc\) away.

Step by step solution

01

Understand Redshift and the Doppler Effect

Redshift occurs when the wavelength of light from an object is stretched due to the object moving away from the observer. The formula for redshift, based on the Doppler effect for light, is given by \( z = \frac{\lambda' - \lambda}{\lambda} \), where \( \lambda' \) is the observed wavelength, \( \lambda \) is the emitted wavelength, and \( z \) is the redshift.
02

Calculate Redshift (z)

Use the redshift formula: \( z = \frac{658.5 \text{ nm} - 590.0 \text{ nm}}{590.0 \text{ nm}} \). Plug in the values: \[ z = \frac{658.5 - 590.0}{590.0} = \frac{68.5}{590.0} \approx 0.1161 \]
03

Relate Redshift to Recession Velocity

For small redshifts, the recessional velocity \( v \) can be related to redshift by the formula \( v = zc \), where \( c = 3.00 \times 10^8 \text{ m/s} \) is the speed of light. This approximation holds when \( z \) is significantly less than one.
04

Calculate Recession Velocity

Substitute the redshift into the velocity formula: \[ v = 0.1161 \times 3.00 \times 10^8 \text{ m/s} \]Calculate to find:\[ v \approx 3.483 \times 10^7 \text{ m/s} \]
05

Define Hubble's Law

Hubble's Law states that the velocity \( v \) of a galaxy moving away from the observer is proportional to its distance \( d \) from the observer, expressed as \( v = H_0 d \), where \( H_0 \) is the Hubble constant. Commonly accepted estimates for \( H_0 \) are around \( 70 \text{ km/s/Mpc} \).
06

Convert Velocity to Consistent Units

The velocity from Step 4 is in m/s, so convert it to km/s to match the Hubble constant, which is given in km/s/Mpc: \[ v = 3.483 \times 10^7 \text{ m/s} = 3.483 \times 10^4 \text{ km/s} \]
07

Find the Galaxy Distance Using Hubble's Law

Using the converted velocity and Hubble's constant, solve for distance \( d \) using \( d = \frac{v}{H_0} \). Assume \( H_0 = 70 \text{ km/s/Mpc} \):\[ d = \frac{3.483 \times 10^4 \text{ km/s}}{70 \text{ km/s/Mpc}} \approx 497.57 \text{ Mpc} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Doppler effect
The Doppler effect is a phenomenon observed when there is a change in frequency or wavelength of a wave in relation to an observer moving relative to the source of the sound or light. This effect is commonly associated with sound waves, like the change in pitch of a siren as an ambulance drives past.

For light waves, the Doppler effect can result in redshift or blueshift. Redshift occurs when light from an object moving away from the observer stretches out, leading to an increase in wavelength and a shift toward the red end of the spectrum. Conversely, blueshift happens when light from an object approaching an observer compresses, leading to a decrease in wavelength and a shift toward the blue end of the spectrum.
Hubble's Law
Hubble's Law is a fundamental concept in cosmology that describes the expansion of the universe. This law states that the velocity at which a galaxy recedes from an observer is directly proportional to its distance from the observer. The formula for Hubble's Law is expressed as:
  • \( v = H_0 d \)
Where:
  • \( v \) is the recession velocity of the galaxy.
  • \( H_0 \) is the Hubble constant, which is a measure of the rate of cosmic expansion.
  • \( d \) represents the distance between the galaxy and the observer.
The value of the Hubble constant is crucial for calculating cosmic distances and understanding the size, age, and eventual fate of the universe. Typical estimates for \( H_0 \) hover around 70 km/s/Mpc.
recession velocity
Recession velocity is the speed at which a galaxy or celestial body moves away from the observer. In the context of cosmology, it is often inferred from redshift measurements using the Doppler effect.

For galaxies with relatively small redshifts, the relationship between recession velocity and redshift can be approximated using:
  • \( v = zc \)
Where:
  • \( v \) represents the recession velocity.
  • \( z \) is the redshift, which is a measure of how much the light has been stretched.
  • \( c \) is the constant speed of light \( (3.00 \times 10^8 \text{ m/s}) \).
Understanding recession velocity is essential for studying the universe's expansion and measuring distances to remote galaxies.
galaxy distance measurement
Measuring the distance to galaxies is a crucial component of understanding the universe's structure and scale. One of the primary methods is using Hubble's Law. By determining the recession velocity of a distant galaxy through its redshift, astrophysicists can use this velocity along with the Hubble constant to calculate the galaxy's distance.

The formula is given by:
  • \( d = \frac{v}{H_0} \)
Where:
  • \( d \) is the distance to the galaxy.
  • \( v \) is the recession velocity derived from redshift measurements.
  • \( H_0 \) is the Hubble constant.
This approach allows astronomers to map the universe and examine galactic positions, movements, and the large-scale structure of the cosmos. With ongoing advances in technology and methodology, determining these vast distances continues to improve, offering deeper insights into the universe's history and evolution.

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Most popular questions from this chapter

One proposed proton decay is \(\mathrm{p}^{+} \rightarrow \mathrm{e}^{+}+\pi^{0}\) which violates both baryon and lepton number conservation, so the proton lifetime is expected to be very long. Suppose the proton half-life were \(1.0 \times 10^{18} \mathrm{y}\) . (a) Calculate the energy deposited per kilogram of body tissue (in rad) due to the decay of the protons in your body in one year. Model your body as consisting entirely of water. Only the two protons in the hydrogen atoms in each \(\mathrm{H}_{2} \mathrm{O}\) molecule would decay in the manner shown; do you see why? Assume that the \(\pi^{0}\) decays to two \(\gamma\) rays, that the positron annihilates with an electron, and that all the energy produced in the primary decay and these secondary decays remains in your body (b) Calculate the equivalent dose (in rem) assuming an RBE of 1.0 for all the radiation products, and compare with the 0.1 rem due to the natural background and the 5.0 -rem guidelinefor industrial workers. Based on your calculation, can the proton lifetime be as short as \(1.0 \times 10^{18} \mathrm{y} ?\)

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