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Chapter 44: Problem 22

Which of the following reactions obey the conservation of baryon number? (a) \(\mathrm{p}+\mathrm{p} \rightarrow \mathrm{p}+\mathrm{e}^{+} ;\) (b) \(\mathrm{p}+\mathrm{n} \rightarrow 2 \mathrm{e}^{+}+\mathrm{e}^{-}\) ; (c) \(\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{-}+\overline{\nu}_{\mathrm{c}} ;(\mathrm{d}) \mathrm{p}+\overline{\mathrm{p}} \rightarrow 2 \gamma\)

Short Answer

Expert verified
Reactions (c) and (d) obey the conservation of baryon number.

Step by step solution

01

Understand Baryon Number Conservation

Baryon number conservation is a fundamental principle in physics where the total baryon number before a reaction must equal the total baryon number after the reaction. Baryons, such as protons (p) and neutrons (n), have a baryon number of +1. Anti-baryons, like anti-protons (\(\overline{\mathrm{p}}\)), have a baryon number of -1. Other particles, such as electrons (\(\mathrm{e}^{-}\)), positrons (\(\mathrm{e}^{+}\)), photons (\(\gamma\)), and neutrinos, have a baryon number of 0.
02

Analyze Reaction (a)

In the reaction \(\mathrm{p}+\mathrm{p} \rightarrow \mathrm{p}+\mathrm{e}^{+}\), initially, we have two protons, each with a baryon number of +1, so the total is +2. After the reaction, there is one proton (baryon number +1) and a positron (baryon number 0), resulting in a total of +1, which does not equal the initial +2. Thus, this does not obey baryon number conservation.
03

Analyze Reaction (b)

In \(\mathrm{p}+\mathrm{n} \rightarrow 2\mathrm{e}^{+}+\mathrm{e}^{-}\), initially, a proton (+1) and a neutron (+1) give a total baryon number of +2. The final state has two positrons and an electron, each with a baryon number of 0, resulting in a total baryon number of 0. This violates the conservation of baryon number.
04

Analyze Reaction (c)

For \(\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{-}+\overline{u}_{\mathrm{c}}\), initially, the proton has a baryon number of +1. After the reaction, the neutron has a baryon number of +1, while the electron and antineutrino have baryon numbers of 0. The total remains +1, thus conserving baryon number.
05

Analyze Reaction (d)

In \(\mathrm{p}+\overline{\mathrm{p}} \rightarrow 2 \gamma\), the initial state has a proton (+1) and antiproton (-1), resulting in a total baryon number of 0. The final state, with two photons, has a total baryon number of 0 as well. Baryon number conservation is maintained in this reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Protons
Protons are subatomic particles found in the nucleus of an atom. They are positively charged and are one of the primary building blocks of matter. Here are some of their key characteristics:
  • Charge: Protons carry a positive charge of +1, which is equal in magnitude but opposite in sign to the charge of an electron.
  • Baryon Number: The baryon number of a proton is +1, which plays a crucial role in the conservation of baryon number in nuclear reactions.
  • Composition: Protons are made up of three quarks: two 'up' quarks and one 'down' quark, held together by the strong nuclear force.
When analyzing nuclear reactions, the presence of protons needs careful consideration due to their baryon number of +1. This affects the net baryon number before and after a reaction, which must be conserved according to physical laws. For example, in the exercise, reactions involving protons must be analyzed to ensure the total baryon number remains constant, as seen in reactions like \(\mathrm{p} + \overline{\mathrm{p}} \rightarrow 2 \gamma\).
Neutrons and Their Role
Neutrons, like protons, are fundamental constituents of an atom's nucleus, but they carry no electric charge. This neutrality makes them unique and essential, especially in nuclear stability and reactions.
  • Baryon Number: Neutrons have a baryon number of +1, similar to protons. It is critical in calculations involving baryon number conservation.
  • Composition: A neutron is composed of one 'up' quark and two 'down' quarks, also bound by the strong force.
  • Nuclear Reactions: Their presence or absence is significant in determining whether a reaction conserves baryon number.
In nuclear reactions, such as \(\mathrm{p} \rightarrow \mathrm{n} + \mathrm{e}^{-} + \overline{u}_{\mathrm{c}}\), neutrons are crucial as they balance the baryon number, conserving it even when other particles like electrons or neutrinos are involved. Understanding neutrons' behavior offers insights into nuclear processes and particles' interaction.
The Concept of Antiparticles
Antiparticles are the counterparts of regular particles with opposite charge and quantum numbers. When a particle meets its antiparticle, they may annihilate each other, producing energy, often in the form of photons.
  • Definition: Each particle has a corresponding antiparticle with the same mass but opposite charge and quantum numbers.
  • Baryon Number: Antiparticles of baryons, like antiprotons \( \overline{\mathrm{p}} \), possess a baryon number of -1, the opposite of their particle counterparts.
  • Reactions: In nuclear reactions like \( \mathrm{p} + \overline{\mathrm{p}} \rightarrow 2 \gamma \), the annihilation conserves baryon number because the bar totals zero.
Understanding antiparticles is essential, particularly in reactions where conservation laws are scrutinized. Their presence can offer alternative reaction pathways, ensuring that fundamental principles like baryon number conservation are observed. Comprehending these processes enriches our grasp of particle physics and the universe's symmetry.

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Most popular questions from this chapter

Deuterons in a cyclotron travel in a circle with radius Deuterons in a cyclotron travel in a circle with radius 32.0 \(\mathrm{cm}\) just before emerging from the dees. The frequency of the applied alternating voltage is 9.00 \(\mathrm{MHz}\) . Find (a) the magnetic field and (b) the kinetic energy and speed of the deuterons upon emergence.

In the LHC, each proton will be accelerated to a kinetic energy of 7.0 \(\mathrm{TeV}\) (a) In the colliding beams, what is the available energy \(E_{\mathrm{a}}\) in a collision? (b) In a fixed-target experiment in which a beam of protons is incident on a stationary proton target, what must the total energy (in TeV) of the particles in the beam be to produce the same available energy as in part (a)?

The quark content of the neutron is \(u d d .(a)\) What is the quark content of the antineutron? Explain your reasoning. (b) Is the neutron its own antiparticle? Why or why not? (c) The quarkcontent of the \(\psi\) is \(c \overline{c} .\) Is the \(\psi\) its own antiparticle? Explain your reasoning.

In which of the following reactions or decays is strangeconserved? In each case, explain your reasoning. (a) \(\mathrm{K}^{+} \rightarrow\) \(\mu^{+}+\nu_{\mu} ;(\mathrm{b}) \mathrm{n}+\mathrm{K}^{+} \rightarrow \mathrm{p}+\pi^{0} ;(\mathrm{c}) \mathrm{K}^{+}+\mathrm{K}^{-} \rightarrow \pi^{0}+\pi^{0} ;(\mathrm{d}) \mathrm{p}+\) \(\mathrm{K}^{-} \rightarrow \Lambda^{0}+\pi^{0} .\)

(a) A high-energy beam of alpha particles collides with a stationary helium gas target. What must the total energy of a beam particle be if the available energy in the collision is 16.0 GeV? (b) If the alpha particles instead interact in a colliding-beam experiment, what must the energy of each beam be to produce the same available energy?
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