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BIO A person exposed to fast neutrons receives a radiation dose of 200 rem on part of his hand, affecting 25 g of tissue. The RBE of these neutrons is 10. (a) How many rad did he receive? (b) How many joules of energy did this person receive? (c) Suppose the person received the same rad dosage, but from beta rays with an RBE of 1.0 instead of neutrons. How many rem would he have received?

Short Answer

Expert verified
(a) 20 rad, (b) 0.005 Joules, (c) 20 rem with beta rays.

Step by step solution

01

Calculate Rad from Rems

To convert rems to rads, divide the rem value by the Relative Biological Effectiveness (RBE). The formula is \( \text{Rad} = \frac{\text{Rem}}{\text{RBE}} \). Here, \( \text{Rem} = 200 \) and \( \text{RBE} = 10 \).\[ \text{Rad} = \frac{200}{10} = 20 \, \text{rad} \]
02

Convert Rad to Joules

1 rad is equivalent to 0.01 joules per kilogram. To find the energy in joules (\( E \)), use the formula:\[ E = \text{Rad} \times \text{mass in kg} \times 0.01 \, \text{J/kg} \]First, convert 25 g to kg: 25 g = 0.025 kg.\[ E = 20 \, \text{rad} \times 0.025 \, \text{kg} \times 0.01 \, \text{J/kg} = 0.005 \, \text{Joules} \]
03

Calculate Rem from Beta Rays Exposure

Using the same rad dosage from beta rays with RBE of 1, the rem value (biological dose) is calculated by multiplying the rad dosage by the RBE:\( \text{Rem} = \text{Rad} \times \text{RBE} \)\[ \text{Rem}_{\beta} = 20 \, \text{rad} \times 1 = 20 \, \text{rem} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Relative Biological Effectiveness (RBE)
In radiation dose measurement, the Relative Biological Effectiveness (RBE) is a crucial concept. It helps us compare the biological damage caused by different types of radiation. RBE is essentially a measure of how much more, or less, damaging a specific type of radiation is compared to a standard, usually x-rays or gamma rays.
To put it simply, RBE adjusts the absorbed dose to reflect the biological potency of the radiation. If radiation has a high RBE, it means it's more effective at causing biological damage, even with a smaller absorbed dose. For instance, if fast neutrons have an RBE of 10, as in the given exercise, it means they are ten times more effective in causing biological damage than the reference radiation.
Understanding RBE is important:
  • It helps in comparing different radiation therapies in medical treatments.
  • It allows for better safety protocols in environments with radiation exposure.
  • It aids in accurately assessing the risk and damage in case of accidental exposure.
RBE plays a significant role in ensuring the calculated dose reflects the actual biological impact on living tissues.
Converting Rad to Joules
Radiation doses are often expressed in units called rads. A 'rad' (Radiation Absorbed Dose) measures the amount of radiation energy absorbed per unit mass of tissue. Understanding the conversion from rads to joules is useful for quantifying the energy aspect of radiation dose.
To convert rad to joules, we use the relationship: **1 rad = 0.01 joules per kilogram**. This conversion helps determine the actual energy absorbed by the tissue. In the exercise, 25 g of tissue was exposed so this mass needs to be converted to kilograms (25 g = 0.025 kg) before using it in the formula:
\[ E = ext{Rad} \times ext{mass in kg} \times 0.01 \, ext{J/kg}\]
For example, with 20 rad absorbed, the energy in joules is:
  • First convert grams to kilograms (25 g = 0.025 kg)
  • Apply the formula: 20 rad \( \times 0.025 \, \text{kg} \times 0.01 \, \text{J/kg} \)
  • This results in an absorbed energy of 0.005 joules.
This process highlights how a small amount of absorbed radiation can translate into an equally small energy deposit into tissue.
Examining Beta Radiation
Beta radiation is a type of radiation consisting of high-energy, high-speed electrons or positrons. Its biological effects, like other radiation types, depend significantly on its energy and the RBE value. In the context of the given problem, the RBE for beta radiation is 1.
This implies that, in terms of biological damage, 1 rad of beta radiation equals 1 rem, since its biological effectiveness is similar to reference radiation like x-rays. This characteristic of beta radiation makes it easier to handle and calculate compared to more biologically potent forms like neutrons or alpha particles.
Beta radiation is noteworthy because:
  • It is commonly encountered in medical & industrial applications, and environmental radiation.
  • Its lower RBE makes it less damaging per unit absorbed compared to other radiation types like neutrons.
  • Its applications range from treating certain health conditions (like some cancer types) to use in lab experiments.
Understanding beta radiation, and how it differs from other types of radiation in terms of RBE, is essential for accurate radiation dose assessment, especially in scenarios where mixed radiation types are present.

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Most popular questions from this chapter

As a health physicist, you are being consulted about a spill in a radiochemistry lab. The isotope spilled was 500\(\mu C\) of \(^{131} \mathrm{Ba}\), which has a half-life of 12 days. (a) What mass of \(^{131} \mathrm{Ba}\) was spilled? (b) Your recommendation is to clear the lab until the radiation level has fallen 1.00\(\mu\) Ci. How long will the lab have to be closed?

We Are Stardust. In 1952 spectral lines of the element technetium- 99\(\left(^{99} \mathrm{Tc}\right)\) were discovered in a red giant star. Red giants are very old stars, often around 10 billion years old, and near the end of their lives. Technetium has \(no\) stable isotopes, and the half-life of \(^{99} \mathrm{Tc}\) is \(200,000\) years. (a) For how many half-lives has the \(^{99} \mathrm{Tc}\) been in the red-giant star if its age is 10 billion years? (b) What fraction of the original \(^{99} \mathrm{Tc}\) would be left at the end of that time? This discovery was extremely important because it provided convincing evidence for the theory (now essentially known to be true) that most of the atoms heavier than hydrogen and helium were made inside of stars by thermonuclear fusion and other nuclear processes. If the \(^{99} \mathrm{Tc}\) had been part of the star since it was born, the amount remaining after 10 billion years would have been so minute that it would not have been detectable. This knowledge is what led the late astronomer Carl Sagan to proclaim that "we are stardust."

Use conservation of mass-energy to show that the energy released in alpha decay is positive whenever the mass of the original neutral atom is greater than the sum of the masses of the final neutral atom and the neutral \(^{4}\) He atom. (Hint: Let the parent nucleus have atomic number \(Z\) and nucleon number \(A .\) First write the reaction in terms of the nuclei and particles involved, and then add \(Z\) electron masses to both sides of the reaction and allot them as needed to arrive at neutral atoms.)

In the 1986 disaster at the Chernobyl reactor in the Soviet Union (now Ukraine), about \(\frac{1}{8}\) of the \(^{137} \mathrm{Cs}\) present in the reactor was released. The isotope \(^{137} \mathrm{Cs}\) has a half-life for \(\beta\) decay of 30.07 \(\mathrm{y}\) and decays with the emission of a total of 1.17 \(\mathrm{MeV}\) of energy per decay. Of this, 0.51 \(\mathrm{MeV}\) goes to the emitted electron and the remaining 0.66 \(\mathrm{MeV}\) to a \(\gamma\) ray. The radioactive \(^{137} \mathrm{Cs}\) is absorbed by plants, which are eaten by livestock and humans. How many \(^{137} \mathrm{Cs}\) atoms would need to be present in each kilogram of body tissue if an equivalent dose for one week is 3.5 \(\mathrm{Sv}\) ? Assume that all of the energy from the decay is deposited in that 1.0 \(\mathrm{kg}\) of tissue and that the RBE of the electrons is 1.5.

Hydrogen atoms are placed in an external \(1.65-\mathrm{T}\) magnetic field. (a) The protons can make transitions between states where the nuclear spin component is parallel and antiparallel to the field by absorbing or emitting a photon. Which state has lower energy: the state with the nuclear spin component parallel or antiparallel to the field? What are the frequency and wavelength of the photon? In which region of the electromagnetic spectrum does it lie? (b) The electrons can make transitions between states where the electron spin component is parallel and antiparallel to the field by absorbing or emitting a photon. Which state has lower energy: the state with the electron spin component parallel or antiparallel to the field? What are the frequency and wavelength of the photon? In which region of the electromagnetic spectrum does it lie?

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