Chapter 42: Problem 28
Pure germanium has a band gap of 0.67 ev. The Fermienergy is in the middle of the gap. (a) For temperatures of 250 \(\mathrm{K}\) ,\(300 \mathrm{K},\) and 350 \(\mathrm{K}\) , calculate the probability \(f(E)\) that a state at the bottom of the conduction band is occupied. (b) For each temperature in part (a), calculate the probability that a state at the top of the valence band is empty.
Short Answer
Step by step solution
Understanding Fermi-Dirac Distribution
Determine Fermi Energy
Calculate Occupancy Probability at Conduction Band
Compute for 250 K
Compute for 300 K
Compute for 350 K
Calculate Empty Probability at Valence Band
Compute for 250 K (Valence)
Compute for 300 K (Valence)
Compute for 350 K (Valence)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Semiconductors
Band Gap
- Conductors: negligible or zero band gap
- Semiconductors: moderate band gap (e.g., Germanium has a 0.67 eV band gap)
- Insulators: large band gap, making electron transition difficult