/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Wave functions like the one in P... [FREE SOLUTION] | 91Ó°ÊÓ

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Wave functions like the one in Problem 40.50 can represent free particles moving with velocity \(v=p / m\) in the \(x\) -direction. Consider a beam of such particles incident on a potential-energy step \(U(x)=0,\) for \(x < 0,\) and \(U(x)=U_{0} < E,\) for \(x > 0 .\) The wave function for \(x < 0\) is \(\psi(x)=A e^{i k_{1} x}+B e^{-i k_{1} x}\) representing incident and reflected particles, and for \(x > 0\) is \(\psi(x)=C e^{i k_{2} x},\) representing transmitted particles. Use the conditions that both \(\psi\) and its first derivative must be continuous at \(x=0\) to find the constants \(B\) and \(C\) in terms of \(k_{1}, k_{2},\) and \(A .\)

Short Answer

Expert verified
\(B = \frac{k_1 - k_2}{k_1 + k_2} A\) and \(C = \frac{2k_1}{k_1 + k_2} A\).

Step by step solution

01

Understand the Problem

We are dealing with a quantum mechanical problem regarding a potential step where the wave function must be continuous at the boundary, which is at \(x = 0\). For \(x < 0\), the wave function is \(\psi(x) = A e^{i k_1 x} + B e^{-i k_1 x}\), and for \(x > 0\), it is \(\psi(x) = C e^{i k_2 x}\). We need to find constants \(B\) and \(C\) using the conditions of continuity and differentiability at the boundary.
02

Apply Continuity of the Wave Function at x=0

The wave function must be continuous at \(x = 0\). This means we set the wave functions on either side of the boundary equal at \(x = 0\): \[ \psi(0^-) = \psi(0^+) \]Substituting the expressions, we have: \[ A + B = C \]
03

Apply Continuity of the Derivative at x=0

The derivative of the wave function with respect to \(x\) must also be continuous at \(x = 0\): \[ \frac{d}{dx}\psi(0^-) = \frac{d}{dx}\psi(0^+) \]Differentiate both wave functions: \[ \frac{d}{dx}(A e^{i k_1 x} + B e^{-i k_1 x}) = ik_1 A e^{i k_1 x} - ik_1 B e^{-i k_1 x} \] \[ \frac{d}{dx}(C e^{i k_2 x}) = ik_2 C e^{i k_2 x}\]Substituting at \(x=0\): \[ ik_1 A - ik_1 B = ik_2 C \]
04

Solve for B and C

From \(A + B = C\), we have \(B = C - A\). Substitute \(B = C - A\) into the derivative continuity equation:\[ ik_1 A - ik_1 (C - A) = ik_2 C \]Simplifying gives:\[ ik_1 A - ik_1 C + ik_1 A = ik_2 C \]\[ 2ik_1 A - ik_1 C = ik_2 C \]\[ C(i(k_1 + k_2)) = 2ik_1 A \]Divide through by \(i(k_1 + k_2)\):\[ C = \frac{2k_1}{k_1 + k_2} A \]Now substitute back in \(B = C - A\):\[ B = \frac{2k_1}{k_1 + k_2} A - A \]\[ B = \left(\frac{2k_1}{k_1 + k_2} - 1\right) A \]\[ B = \frac{k_1 - k_2}{k_1 + k_2} A \]
05

Present the Solution

The values of the constants \(B\) and \(C\) in terms of \(k_1, k_2,\) and \(A\) are:\[ B = \frac{k_1 - k_2}{k_1 + k_2} A \]\[ C = \frac{2k_1}{k_1 + k_2} A \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Function Continuity
In quantum mechanics, continuity of the wave function is a key principle. At a boundary, the wave function on one side must smoothly transition to the wave function on the other side. This ensures that there is no sudden jump in the probability of finding the quantum particle, which would be unphysical. For the potential step problem, we have two regions defined by the wave functions: one for \( x < 0 \) and another for \( x > 0 \).
  • In the region \( x < 0 \), \( \psi(x) = A e^{i k_1 x} + B e^{-i k_1 x} \).
  • In the region \( x > 0 \), \( \psi(x) = C e^{i k_2 x} \).
At the boundary \( x = 0 \), the continuity condition \( \psi(0^-) = \psi(0^+) \) translates to:\[ A + B = C \]This equation shows how the wave functions from both sides must be equal exactly at the boundary. This requirement helps us solve for the variables \( B \) and \( C \) in terms of the given constants.
Potential Step
A potential step is a situation in quantum mechanics where the potential energy changes suddenly at a certain point. This kind of setup is ideal for exploring concepts such as reflection and transmission of quantum particles. In our exercise, this potential step occurs at \( x = 0 \).
  • For \( x < 0 \), the potential \( U(x) = 0 \), meaning the particle moves in a region where there is no additional potential energy.
  • For \( x > 0 \), the potential \( U(x) = U_0 < E \), introducing a step in potential energy lower than the particle's total energy \( E \).
This introduces a boundary condition that affects how the quantum particle behaves when moving between different potential regions. The potential step creates a boundary that must be crossed, causing some of the quantum particles to reflect, while others are transmitted.
Quantum Particle Reflection
Reflection in quantum mechanics is a fascinating phenomenon. When a quantum particle encounters a potential step, part of its wave function is reflected back. This is akin to a light wave reflecting off a mirror. In our scenario, the reflection is represented by the term \( B e^{-i k_1 x} \) for \( x < 0 \). The reflection coefficient \( B \) quantifies how much of the particle's wave function is reflected due to the potential step.
  • Reflection depends on the difference in potential and the particle's energy.
  • For a step with \( U_0 < E \), not all particles are reflected.
The derived expression for \( B \) is:\[ B = \frac{k_1 - k_2}{k_1 + k_2} A \]This shows how the portion of the wave function that is reflected depends on the wave numbers \( k_1 \) and \( k_2 \), and hence on the energies and momenta of the particles on either side of the step.
Quantum Particle Transmission
Transmission occurs when a quantum particle crosses a potential step. Unlike classical particles which would only pass over a barrier if they have enough energy, quantum particles have a probability of being transmitted even at lower energies, a hallmark of quantum tunneling. In this problem, the term \( C e^{i k_2 x} \) for \( x > 0 \) represents the transmitted wave function. The transmission coefficient \( C \) indicates how much of the particle is transmitted through the potential step.
  • Transmission relates to the continuity of the wave function and its derivative.
  • Even when the potential energy is less than total energy, transmission can occur.
The formula for \( C \) is:\[ C = \frac{2k_1}{k_1 + k_2} A \]This tells us how the wave function adjusting itself to the step leads to a transmitted portion, determined by the relative wave numbers. It captures the essence of quantum mechanics where particles exhibit wave-like behavior, allowing them to be both reflected and transmitted at potential boundaries.

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Most popular questions from this chapter

A particle is described by a wave function \(\psi(x)=A e^{-\alpha x^{2}}\) where \(A\) and \(\alpha\) are real, positive constants. If the value of \(\alpha\) is increased, what effect does this have on (a) the particle's uncertainty in position and (b) the particle's uncertainty in momentum? Explain your answers.

Normalization of the Wave Function. Consider a particle moving in one dimension, which we shall call the \(x\) -axis. (a) What does it mean for the wave function of this particle to be normalized? (b) Is the wave function \(\psi(x)=e^{a x},\) where \(a\) is a positive real number, normalized? Could this be a valid wave function? (c) If the particle described by the wave function \(\psi(x)=A e^{b x},\) where \(A\) and \(b\) are positive real numbers, is confined to the range \(x \geq 0\) , determine \(A\) (including its units) so that the wave function is normalized.

Consider a potential well defined as \(U(x)=\infty\) for \(x < 0, U(x)=0\) for \(0 < x < L,\) and \(U(x)=U_{0} > 0\) for \(x > L\) (Fig. \(\mathrm{P} 40.70 ) .\) Consider a particle with mass \(m\) and kinetic energy \(E < U_{0}\) that is trapped in the well. (a) The boundary condition at the infinite wall \((x=0)\) is \(\psi(0)=0 .\) What must the form of the function \(\psi(x)\) for \(0 < x < L\) be in order to satisfy both the Schrodinger equation and this boundary condition (b) The wave function must remain finite as \(x \rightarrow \infty .\) What must the form of the function \(\psi(x)\) for \(x>L\) be in order to satisfy both the Schrodinger equation and this boundary condition at infinity? (c) Impose the boundary conditions that \(\psi\) and \(d \psi / d x\) are continuous at \(x=L .\) Show that the energies of the allowed levels are obtained from solutions of the equation \(k \cot k L=-\kappa,\) where \(k=\sqrt{2 m E} / \hbar\) and \(\kappa=\sqrt{2 m\left(U_{0}-E\right) / \hbar}\)

(a) An electron with initial kinetic energy 32 eV encounters a square barrier with height 41 \(\mathrm{eV}\) and width 0.25 \(\mathrm{nm}\) . What is the probability that the electron will tunnel through the barrier? (b) A proton with the same kinetic energy encounters the same barrier. What is the probability that the proton will tunnel through the barrier?

When a hydrogen atom undergoes a transition from the \(n=2\) to the \(n=1\) level, a photon with \(\lambda=122 \mathrm{nm}\) is emitted. (a) If the atom is modeled as an electron in a one-dimensional box, what is the width of the box in order for the \(n=2\) to \(n=1\) transition to correspond to emission of a photon of this energy? (b) For a box with the width calculated in part (a), what is the ground-state energy? How does this correspond to the ground-state energy of a hydrogen atom? (c) Do you think a one-dimensional box is a good model for a hydrogen atom? Explain. (Hint: Compare the spacing between adjacent energy levels as a function of \(n . )\)

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