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Wavelength of a Bullet. Calculate the de Broglie wavelength of a 5.00 -g bullet that is moving at 340 \(\mathrm{m} / \mathrm{s}\) . Will the bullet exhibit wavelike properties?

Short Answer

Expert verified
The de Broglie wavelength is \( 3.898 \times 10^{-34} \ \mathrm{m} \); the bullet will not exhibit wavelike properties.

Step by step solution

01

Understanding de Broglie Wavelength

The de Broglie wavelength of an object is calculated using the formula \( \lambda = \frac{h}{mv} \), where \( \lambda \) is the de Broglie wavelength, \( h \) is Planck's constant (\(6.626 \times 10^{-34} \ \mathrm{m}^2\mathrm{kg/s}\)), \( m \) is the mass of the object in kilograms, and \( v \) is the velocity in meters per second.
02

Convert Mass from Grams to Kilograms

The given mass of the bullet is \(5.00\) grams. We need to convert this mass into kilograms because the SI unit system is used in the de Broglie equation. Thus, \( m = 5.00 \div 1000 = 0.005 \ \mathrm{kg} \).
03

Plug Values into the de Broglie Formula

Substitute the known values into the de Broglie formula: \( \lambda = \frac{6.626 \times 10^{-34}}{0.005 \times 340} \).
04

Calculate the de Broglie Wavelength

Perform the calculation: \( \lambda = \frac{6.626 \times 10^{-34}}{1.7} = 3.898 \times 10^{-34} \ \mathrm{m} \).
05

Evaluate Wavelike Properties

Considering the calculated de Broglie wavelength, \( 3.898 \times 10^{-34} \ \mathrm{m} \), which is extremely small, the bullet will not exhibit any noticeable wavelike properties as these are significant only at subatomic scales.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum Mechanics
Quantum mechanics is a fascinating branch of physics that deals with the smallest particles in the universe. It explains how tiny things like atoms and subatomic particles behave. This branch of science is crucial for understanding actions at really small scales but often defies our everyday intuitions.
Quantum mechanics reveals that particles we think of as solid, like electrons, can also behave as waves. At its core, it suggests that energy is quantized, meaning it comes in discrete amounts. This groundbreaking theory lays the foundation for concepts like the de Broglie wavelength, used to compute the wave nature of particles.
This strange behavior isn’t noticeable in our everyday world. Conditions like the small scales of atoms make quantum mechanics essential. Yet, its principles remarkably explain a broad range of phenomena from the tiniest particles to fundamental chemistry.
Understanding quantum mechanics helps grasp why a small particle like an electron or larger objects in certain conditions behave like waves.
Wave-Particle Duality
Wave-particle duality is an intriguing concept in quantum mechanics that describes how particles such as electrons exhibit both particle-like and wave-like properties. Imagine trying to fit both categories into a single entity. This dual nature means particles can behave like waves under certain conditions and show particle-like traits at other times.
For instance, electrons can form interference patterns, a behavior typical of waves, seen in experiments like the famous double-slit experiment. At the same time, they can also collide with other particles as if they were little billiard balls, a particle-like behavior.
This duality is crucial in explaining the behavior of tiny particles but doesn’t affect everyday objects like bullets. For a macroscopic object, its wave characteristics are too small to detect, making its particle nature dominant.
Understanding wave-particle duality allows us to comprehend how objects at a microscopic scale can behave in ways that seem bizarre but are essential in the field of quantum physics.
Planck's Constant
Planck's constant, denoted by the symbol \( h \), is a fundamental quantity in quantum mechanics. It acts as a bridge between wave and particle behaviors by relating the energy of a photon to its frequency. Its value is \( 6.626 \times 10^{-34} \, \text{m}^2 \text{kg/s} \), which might seem tiny, but it is foundational in explaining why waves at atomic scales behave in such particular ways.
Named after physicist Max Planck, this constant is part of the key formula for the de Broglie wavelength calculation: \( \lambda = \frac{h}{mv} \). Here, you can see how it's used to determine the wave properties of matter.
The small value of Planck’s constant underscores why quantum effects are not observable at larger scales, like with a moving bullet. For electrons and other tiny particles, however, it provides significant insights into their behavior and energy quantization.
Understanding Planck’s constant helps to appreciate the quantization of energy levels and why quantum effects don’t show visibly around us.
Wavelike Properties
Wavelike properties refer to how particles behave similarly to waves. This concept is crucial in quantum mechanics and is much more evident at the atomic or subatomic level. In this domain, particles can exhibit interference, diffraction, and other behaviors typical of waves.
The de Broglie wavelength formula demonstrates this by providing a quantitative measure of a particle's wave aspect. However, these properties are not observable in larger, everyday objects because their de Broglie wavelengths are too small.
In the example of a moving bullet, its wavelike properties are undetectable due to its large mass and speed, which leads to an extremely minute de Broglie wavelength. Hence, while theoretically everything has wavelike properties, only very tiny particles, like electrons, show them in a noticeable way.
Understanding wavelike properties reinforces the idea that all matter exhibits wave characteristics in some form, which is fundamental to modern physics and technologies like electron microscopes.

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Most popular questions from this chapter

Zero-Point Energy. Consider a particle with mass \(m\) moving in a potential \(U=\frac{1}{2} k x^{2},\) as in a mass-spring system. The total energy of the particle is \(E=p^{2} / 2 m+\frac{1}{2} k x^{2}\) Assume that \(p\) and \(x\) are approximately related by the Heisenberg uncertainty principle, so \(p x \approx h .\) (a) Calculate the minimum possible value of the energy \(E,\) and the value of \(x\) that gives this minimum \(E .\) This lowest possible energy, which is not zero, is called the zero-point energy. (b) For the \(x\) calculated in part (a), what is the ratio of the kinetic to the potential energy of the particle?

Coherent light is passed through two narrow slits whose separation is 40.0\(\mu \mathrm{m} .\) The second-order bright fringe in the interference pattern is located at an angle of 0.0300 rad. If electrons are used instead of light, what must the kinetic energy (in electron volts) of the electrons be if they are to produce an interference pattern for which the second-order maximum is also at 0.0300 rad?

An electron moves with a speed of \(4.70 \times 10^{6} \mathrm{m} / \mathrm{s}\) . \right. What is its de Broglie wavelength? (b) A proton moves with the same speed. Determine its de Broglie wavelength.

(a) Approximately how fast should an electron move so it has a wavelength that makes it useful to measure the distance between adjacent atoms in typical crystals (about 0.10 \(\mathrm{nm} ) ?\) (b) What is the kinetic energy of the electron in part (a)? (c) What would be the energy of a photon of the same wavelength as the electron in part (b)? (d) Which would make a more effective probe of small- scale structures: electrons or photons? Why?

By extremely careful measurement, you determine the \(x\) -coordinate of a car's center of mass with an uncertainty of only 1.00\(\mu \mathrm{m} .\) The car has a mass of 1200 \(\mathrm{kg}\) . (a) What is the minimum uncertainty in the \(x\) -component of the velocity of the car's center of mass as prescribed by the Heisenberg uncertainty principle? (b) Does the uncertainty principle impose a practical limit on our ability to make simultaneous measurements of the positions and velocities of ordinary objects like cars, books, and people? Explain.

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