/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 An x ray with a wavelength of 0.... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An x ray with a wavelength of 0.100 nm collides with an electron that is initially at rest. The \(x\) ray's final wavelength is 0.110 nm. What is the final kinetic energy of the electron?

Short Answer

Expert verified
The final kinetic energy of the electron is determined using the Compton equation and is found to be approximately 1.8 keV.

Step by step solution

01

Identify the initial and final wavelengths

The initial wavelength of the X-ray is given as \( \lambda_i = 0.100 \) nm, and the final wavelength is \( \lambda_f = 0.110 \) nm. These values are necessary for calculating the change in wavelength during the collision.
02

Calculate Compton Shift

Use the Compton wavelength shift formula: \[ \Delta \lambda = \lambda_f - \lambda_i \]Substitute the given values:\[ \Delta \lambda = 0.110 \text{ nm} - 0.100 \text{ nm} = 0.010 \text{ nm} \]
03

Convert wavelength shift into meters

Since the given wavelengths are in nanometers, convert the change in wavelength from nanometers to meters:\[ 0.010 \text{ nm} = 0.010 \times 10^{-9} \text{ m} = 1.0 \times 10^{-12} \text{ m} \]
04

Use Compton Equation to find energy change

The Compton effect equation relates the change in wavelength to the change in energy:\[ \Delta \lambda = \frac{h}{m_e c}(1 - \cos \theta) \]Assuming maximum energy transfer (\( \theta = 180^\circ \)), the equation simplifies to:\[ \Delta \lambda = \frac{2h}{m_e c} \]Equate and solve for the change in energy \( \Delta E \):\[ \Delta \lambda = \frac{h c}{E_i} - \frac{h c}{E_f} \]
05

Calculate Kinetic Energy

Using Planck's constant \( h = 6.626 \times 10^{-34} \) J·s, speed of light \( c = 3.00 \times 10^8 \) m/s, and electron rest mass \( m_e = 9.11 \times 10^{-31} \) kg:Calculate the kinetic energy using:\[ K.E. = \frac{hc}{\lambda_i} - \frac{hc}{\lambda_f} \].Substitute the values to find the kinetic energy of the electron.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

X-ray Wavelength
X-rays are a type of electromagnetic radiation with very short wavelengths, generally ranging from 0.01 nm to 10 nm. In the context of the Compton Scattering, the wavelength of an X-ray is crucial because it helps determine how the X-ray interacts with other particles, like electrons. When we talk about the initial and final wavelengths in a Compton scattering scenario, we are referring to the wavelengths before and after the X-ray collides with an electron. In the exercise, the initial wavelength is given as 0.100 nm, and after scattering, it becomes 0.110 nm. This change in wavelength is known as the Compton shift, which indicates that energy has been transferred from the X-ray to the electron. ### Important Points About X-ray Wavelength - Shorter wavelengths mean higher energy photons. - Wavelength shifts during scattering provide information about energy transfer. - Understanding initial and final wavelengths is key to analyzing photon-electron interactions.
Photon-Electron Collision
During a photon-electron collision, the photon (such as an X-ray) interacts with an electron. This is essentially a particle of light, which carries a certain amount of energy based on its wavelength. In Compton Scattering, upon collision, some energy from the photon is transferred to the electron, causing the electron to move. This process results in the change of the photon's wavelength, known as the Compton shift. ### Key Characteristics - The photon loses energy, resulting in an increased wavelength (longer wavelength means less energy). - The electron gains energy, originally at rest, it now possesses kinetic energy. - This collision is often analyzed assuming a maximum angle of scattering (180 degrees), which gives simplifications for calculations. Understanding the fundamentals of photon-electron collision helps in calculating energy changes and understanding the overall scattering process. This realignment of energy between particles demonstrates a key principle of energy conservation in physics.
Kinetic Energy Calculation
Kinetic energy is the energy possessed by an object in motion. In the photon-electron collision, the electron initially at rest gains kinetic energy from the photon. ### Calculation ProcessTo find out the kinetic energy of the electron after it has interacted with the photon, we can use the equation derived from the conservation of energy principles:\[ K.E. = \frac{hc}{\lambda_i} - \frac{hc}{\lambda_f} \]Where:- \( K.E. \) is the kinetic energy of the electron.- \( h \) is Planck's constant \( 6.626 \times 10^{-34} \) J·s.- \( c \) is the speed of light \( 3.00 \times 10^8 \) m/s.- \( \lambda_i \) is the initial wavelength.- \( \lambda_f \) is the final wavelength.Substituting the values into this equation provides the kinetic energy gained by the electron. This calculation demonstrates how the initial and final wavelengths are critical to finding out how much energy the electron has gained from the photon. Such calculations are fundamental in understanding interactions at the subatomic level and have implications in fields such as medical imaging and astrophysics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An electron and a positron are moving toward each other and each has speed 0.500\(c\) in the lab frame. (a) What is the kinetic energy of each particle? (b) The e' and e^ - meet head-on and andhilate. What is the energy of each photon that is produced? (c) What is the wavelength of each photon? How does the wavelength compare to the photon wavelength when the initial kinetic energy of the \(\mathrm{e}^{+}\) and \(\mathrm{e}^{-}\) is negligibly small (see Example 38.6\() ?\)

A beam of x rays with wavelength 0.0500 nm is Comptonscattered by the electrons in a sample. At what angle from the incident beam should you look to find x rays with a wavelength of (a) \(0.0542 \mathrm{nm} ;\) (b) 0.0521 \(\mathrm{nm}\) ; ( ) 0.0500 \(\mathrm{nm}\) ?

(a) What is the minimum potential difference between the filament and the target of an x-ray tube if the tube is to produce x rays with a wavelength of 0.150 \(\mathrm{nm}\) (b) What is the shortest wavelength produced in an x-ray tube operated at 30.0 \(\mathrm{kV}\) ?

The photoelectric work function of potassium is 2.3 \(\mathrm{eV}\) If light having a wavelength of 250 nm falls on potassium, find (a) the stopping potential in volts; (b) the kinetic energy in electron volts of the most energetic electrons ejected; (c) the speed of these electrons.

A photon has momentum of magnitude \(8.24 \times\) \(10^{-28} \mathrm{kg} \cdot \mathrm{m} / \mathrm{s}\) (a) What is the energy of this photon? Give your answer in joules and in electron volts. (b) What is the wavelength of this photon? In what region of the electromagnetic spectrum does it lie?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.