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In an experiment, two protons are shot directly toward each other, each moving at half the speed of light relative to the laboratory. (a) What speed does one proton measure for the other proton? (b) What would be the answer to part (a) if we used only nonrelativistic Newtonian mechanics? (c) What is the kinetic energy of each proton as measured by (i) an observer at rest in the laboratory and (ii) an observer riding along with one of the protons? (d) What would be the answers to part (c) if we used only nonrelativistic Newtonian mechanics?

Short Answer

Expert verified
(a) \(\frac{4c}{5}\). (b) \(c\). Lab KE: \((\frac{2}{\sqrt{3}} - 1)mc^2\), Classically \(\frac{1}{8}mc^2\). Moving frame: \(\frac{2}{3} mc^2\), Classically \(\frac{1}{2} mc^2\).

Step by step solution

01

Relativistic Addition of Velocities

To find the speed of one proton as measured by the other, we need to use the relativistic velocity addition formula. Given that each proton is moving at speed \(u = \frac{c}{2}\) towards each other, the velocity of one proton as seen by the other, \(v\), is given by: \[ v = \frac{u + u}{1 + \frac{u^2}{c^2}} = \frac{c/2 + c/2}{1 + (c/2)^2/c^2} \] Simplifying this, we get: \[ v = \frac{c}{1 + 1/4} = \frac{c}{5/4} = \frac{4c}{5} \] Thus, the speed is \(\frac{4c}{5}\).
02

Classical Addition of Velocities

Using nonrelativistic (Newtonian) mechanics, the speeds would simply add arithmetically. Since each proton moves at half the speed of light relative to the laboratory, the speed of one proton relative to the other would be: \[ v = c/2 + c/2 = c \] Thus, in classical mechanics, the speed is \(c\).
03

Kinetic Energy in the Laboratory Frame

In the laboratory frame, the kinetic energy \( K \) of each proton moving at \(u = \frac{c}{2}\) is calculated using the relativistic formula: \[ K = \left( \frac{1}{\sqrt{1 - \frac{u^2}{c^2}}} - 1 \right) mc^2 \] Substitute \( u = \frac{c}{2} \) to find: \[ K = \left( \frac{1}{\sqrt{1 - \frac{1}{4}}} - 1 \right) mc^2 = \left( \frac{1}{\sqrt{3/4}} - 1 \right) mc^2 = \left( \frac{2}{\sqrt{3}} - 1 \right) mc^2 \] This is the kinetic energy as seen by an observer stationary in the laboratory.
04

Kinetic Energy in the Co-Moving Frame

For an observer moving along with one of the protons, the other proton appears to be moving at \(\frac{4c}{5}\). The kinetic energy \( K \) is then: \[ K = \left( \frac{1}{\sqrt{1 - \left( \frac{4}{5} \right)^2}} - 1 \right) mc^2 \] \[ K = \left( \frac{1}{\sqrt{1 - \frac{16}{25}}} - 1 \right) mc^2 = \left( \frac{1}{\sqrt{9/25}} - 1 \right) mc^2 = \left( \frac{5}{3} - 1 \right) mc^2 \] \[ K = \frac{2}{3} mc^2 \] This is the kinetic energy observed from the co-moving frame.
05

Classical Kinetic Energy

Using classical mechanics for the laboratory frame, the kinetic energy \( K \) can be approximated by the formula: \[ K = \frac{1}{2} mv^2 \] With \( v = \frac{c}{2} \), we have: \[ K = \frac{1}{2} m \left( \frac{c}{2} \right)^2 = \frac{1}{8} mc^2 \] For the co-moving frame where velocity is \(v = c\), the classical kinetic energy would be: \[ K = \frac{1}{2} m c^2 \]
06

Compiling Final Answers

Let's summarize our findings: (a) Using relativistic mechanics, the speed is \(\frac{4c}{5}\). Using classical mechanics, the speed is \(c\). (b) The kinetic energy observed in the lab is \((\frac{2}{\sqrt{3}} - 1)mc^2\) relativistically and \(\frac{1}{8}mc^2\) classically. In the co-moving frame, the relativistic energy is \(\frac{2}{3} mc^2\) and classically \(\frac{1}{2} mc^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativistic Velocity Addition
When dealing with objects moving at significant fractions of the speed of light, such as protons in this exercise, classical physics doesn't give accurate results. This is where "Relativistic Velocity Addition" comes into play. The formula used is: \[ v = \frac{u + u}{1 + \frac{u^2}{c^2}} \] where \( u \) is the speed of each proton relative to the laboratory, and \( c \) is the speed of light. This formula shows that velocities don't simply add up in a straightforward manner when approaching light speed, due to effects predicted by Einstein’s Theory of Relativity. Instead of obtaining \( c \) as the relative speed, the result for these protons is actually \( \frac{4c}{5} \). This prediction corrects the exaggerated results that classical physics would suggest.
This concept is essential for understanding interactions at high velocities where the effects of relativity cannot be ignored.
Kinetic Energy
The concept of "Kinetic Energy" describes an object's energy due to its motion. In relativistic mechanics, kinetic energy is calculated differently than in classical mechanics. For protons moving at high speeds as in this exercise, the relativistic kinetic energy \( K \) is given by:\[ K = \left( \frac{1}{\sqrt{1 - \frac{u^2}{c^2}}} - 1 \right) mc^2 \] where \( m \) is the rest mass of the proton, and \( u \) is its speed.
Important Observations:
  • Relativistic kinetic energy considers the effects of velocity nearing the speed of light, which makes it significantly different from the classical case.
  • In this exercise, calculating kinetic energy in the laboratory frame for \( u = \frac{c}{2} \) results in \( K \approx 0.317 mc^2 \), which shows how energy increases sharply with speed under relativistic conditions.
Understanding this distinction is crucial for calculating energy in high-speed particle experiments.
Laboratory Frame
The "Laboratory Frame" refers to the reference point from which all observations are made in the context of an experiment. It is often considered a stationary frame from which measurements of velocity, kinetic energy, and other physical quantities are made. In this exercise: - Observers are in the laboratory frame watching protons approaching each other at high speeds. - The laboratory frame affects how different quantities are perceived, such as the speed and kinetic energy of protons.
Key Points:
  • The laboratory frame is a common point of reference to compare various calculations, especially in multi-body systems.
  • It allows one to distinguish between measurements made in the laboratory versus those made in a moving system, like the co-moving frame of a proton.
Choosing the correct frame of reference is critical for analyses in both classical and relativistic contexts.
Classical Mechanics
"Classical Mechanics" is the branch of physics that deals with the motion of objects and is often used for everyday speeds, far less than the speed of light. In contrast to relativistic mechanics, velocities are simply additive:\[ v = u_1 + u_2 \] where \( u_1 \) and \( u_2 \) are velocities in one direction. For our protons, this would incorrectly suggest a combined speed approaching \( c \) when, in fact, relativistic effects must be considered.
Key Differences:
  • Classical mechanics assumes that mass and energy are also separate and unrelated concepts, while relativistic physics shows their interchangeability.
  • It holds up well at low speeds but fails to predict outcomes accurately as speed approaches that of light, where results deviate from those predicted by classical equations.
Understanding where classical mechanics falls short provides a good basis for why relativistic mechanics is essential in high-speed scenarios.

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Most popular questions from this chapter

What is the speed of a particle whose kinetic energy is equal to (a) its rest energy and (b) five times its rest energy?

Albert in Wonderland. Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 20.0 \(\mathrm{m}\) from each other. Being very skilled players, they play without a net. The tennis ball has mass 0.0580 \(\mathrm{kg} .\) You can ignore gravity and assume that the ball travels parallel to the ground as it travels between the two players. Unless otherwise specified, all measurements are made by the two men. (a) Lorentz serves the ball at 80.0 \(\mathrm{m} / \mathrm{s} .\) What is the ball's kinetic energy? (b) Einstein slams a return at \(1.80 \times 10^{8} \mathrm{m} / \mathrm{s}\) . What is the ball's kinetic energy? (c) During Einstein's return of the ball in part (a), a white rabbit runs beside the court in the direction from Einstein to Lorentz. The rabbit has a speed of \(2.20 \times 10^{8} \mathrm{m} / \mathrm{s}\) relative to the two men. What is the speed of the rabbit relative to the ball? (d) What does the rabbit measure as the distance from Einstein to Lorentz? (e) How much time does it take for the rabbit to run \(20.0 \mathrm{m},\) according to the players? (f) The white rabbit carries a pocket watch. He uses this watch to measure the time (as he sees it) for the distance from Einstein to Lorentz to pass by under him. What time does he measure?

A rocket ship flies past the earth at 85.0\(\%\) of the speed of light. Inside, an astronaut who is undergoing a physical examination is having his height measured while he is lying down parallel to the direction the rocket ship is moving. (a) If his height is measured to be 2.00 \(\mathrm{m}\) by his doctor inside the ship, what height would a person watching this from earth measure for his height? (b) If the earth-based person had measured \(2.00 \mathrm{m},\) what would the doctor in the spaceship have measured for the astronaut's height? Is this a reasonable height? (c) Suppose the astronaut in part (a) gets upafter the examination and stands with his body perpendicular to the direction of motion. What would the doctor in the rocket and the observer on earth measure for his height now?

In certain radioactive beta decay processes, the beta particle (an electron) leaves the atomic nucleus with a speed of 99.95\(\%\) the speed of light relative to the decaying nucleus. If this nucleus is moving at 75.00\(\%\) the speed of light in the laboratory reference frame, find the speed of the emitted electron relative to the laboratory reference frame if the electron is emitted (a) in the same direction that the nucleus is moving and (b) in the opposite direction from the nucleus's velocity. (c) In each case in parts (a) and (b), find (b), find the kinetic energy of the electron as measured in (i) the laboratory frame and (ii) the reference frame of the decaying nucleus.

As measured by an observer on the earth, a spacecraft runway on earth has a length of 3600 \(\mathrm{m} .\) (a) What is the length of the runway as measured by a pilot of a spacecraft flying past at a speed of \(4.00 \times 10^{7} \mathrm{m} / \mathrm{s}\) relative to the earth? (b) An observer on earth measures the time interval from when the spacecraft is directly over one end of the runway until it is directly over the other end. What result does she get? (c) The pilot of the spacecraft measures the time it takes him to travel from one end of the runway to the other end. What value does he get?

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