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(a) Through what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of 0.980\(c ?\) (b) What is the kinetic energy of the electron at this speed? Express your answer in joules and in electron volts.

Short Answer

Expert verified
a) 2.06 MV potential difference. b) Kinetic energy is 3.30 x 10^-13 J or 2.056 MeV.

Step by step solution

01

Understand the Problem

We need to find the potential difference an electron must traverse to reach a speed of 0.980c, where c is the speed of light. Then, we find the kinetic energy of the electron at this speed both in joules and electron volts.
02

Use Relativistic Formula for Speed

Since the speed is close to the speed of light, the relativistic formula must be used. The relativistic kinetic energy is given by: \[ KE = \left( \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} - 1 \right) mc^2 \] where \( m \) is the rest mass of the electron and \( v \) is 0.980c. The rest mass energy \( mc^2 \) for an electron is \( 0.511 \, \text{MeV} \).
03

Calculate Relativistic Kinetic Energy

Substitute \( v = 0.980c \) into the equation: \[ \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} = \frac{1}{\sqrt{1 - 0.980^2}} \approx 5.025 \] \[ KE = (5.025 - 1) \times 0.511 \, \text{MeV} \approx 2.056 \, \text{MeV} \] Convert MeV to joules using \( 1 \, \text{MeV} = 1.602 \times 10^{-13} \, \text{J} \): \[ KE = 2.056 \, \text{MeV} \times 1.602 \times 10^{-13} \, \text{J/MeV} \approx 3.30 \times 10^{-13} \, \text{J} \]
04

Calculate Potential Difference

The potential difference \( V \) needed can be found by equating the kinetic energy gain to the energy associated with an electric field: \[ eV = KE \] \[ V = \frac{KE}{e} \] with \( e = 1.602 \times 10^{-19} \, \text{C} \). Thus, \[ V = \frac{3.30 \times 10^{-13}}{1.602 \times 10^{-19}} \approx 2.06 \times 10^6 \, \text{V} \] This is the voltage through which the electron must be accelerated.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Difference
When discussing electronic systems, understanding potential difference is key. It is the difference in electric potential between two points in a circuit. In simple terms, it can be thought of as the amount of energy needed to move a charge from one point to another. This energy is typically measured in volts. In the context of accelerating an electron, the potential difference determines how much kinetic energy the electron will gain. This is because the energy provided by an electric field to an electron is directly related to the potential difference. Hence, when an electron is subjected to a specific potential difference, it gains kinetic energy equal to the product of the electron's charge and the potential difference.
Electron Acceleration
Electron acceleration occurs when an electron is exposed to an electric field. Simply put, the electric field applies a force on the electron, causing it to accelerate. Due to its negative charge and small mass, electrons respond quickly to electric fields, gaining speed rapidly.
In physics, particularly when reaching speeds close to the speed of light, we consider relativistic effects. As electrons accelerate, they gain kinetic energy, which depends on their speed. Due to the electron's light mass and charge, significant acceleration can be achieved through relatively modest potential differences.
Speed of Light
The speed of light, denoted as "c," is a fundamental constant in physics with a value of approximately 299,792,458 meters per second. It is considered the ultimate speed limit in the universe, meaning no object with mass can reach or exceed this speed.
As particles like electrons approach the speed of light, their behavior changes. Specifically, their mass effectively increases, altering how they respond to forces. This is why relativistic equations, rather than classical ones, must be used to accurately describe their motion and energy. Understanding these changes is crucial for calculating kinetic energy at speeds approaching the speed of light.
MeV to Joules Conversion
MeV, or Mega Electron Volts, is a unit of energy commonly used in atomic and particle physics. It reflects the energy gained by a single electron when it is accelerated by a potential difference of one million volts. In calculations involving electron kinetics, converting MeV to joules is often necessary for more universal scientific applications.
The conversion between MeV and Joules is straightforward: \[1 \, \text{MeV} = 1.602 \times 10^{-13} \, \text{J}\] By using this factor, one can easily transform energy values from MeV to joules, making it possible to apply these energy calculations in different physical contexts or compare them with other measurements.

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