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(a) At what speed is the momentum of a particle twice as great as the result obtained from the nonrelativistic expression \(m v ?\) Express your answer in terms of the speed of light. (b) A force is applied to a particle along its direction of motion. At what speed is the magnitude of force required to produce a given acceleration twice as great as the force required to produce the same acceleration when the particle is at rest? Express your answer in terms of the speed of light.

Short Answer

Expert verified
In both parts (a) and (b), the required speed is \( \frac{\sqrt{3}}{2}c \).

Step by step solution

01

Understanding the Concept of Relativistic Momentum

The relativistic momentum of a particle is given by \( p = \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}} \), where \( m \) is the mass of the particle, \( v \) is its velocity, and \( c \) is the speed of light. The nonrelativistic momentum is \( mv \). We want the relativistic momentum to be twice the nonrelativistic momentum: \( \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}} = 2mv \).
02

Solve for the Velocity in Part (a)

Setting up the equation \( \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}} = 2mv \) and canceling \( mv \) from both sides gives \( \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} = 2 \). Squaring both sides results in \( \frac{1}{1 - \frac{v^2}{c^2}} = 4 \). Solving for \( v^2 \) gives \( 1 - \frac{v^2}{c^2} = \frac{1}{4} \), thus \( \frac{v^2}{c^2} = \frac{3}{4} \). Therefore, the speed \( v = \frac{\sqrt{3}}{2}c \).
03

Understanding Relativistic Force for Part (b)

The relativistic force is given by \( F = \frac{ma}{\sqrt{1 - \frac{v^2}{c^2}}} \). We want the force during motion to be twice the force at rest to produce the same acceleration. Thus, \( \frac{ma}{\sqrt{1 - \frac{v^2}{c^2}}} = 2ma \).
04

Solve for the Velocity in Part (b)

Set \( \frac{ma}{\sqrt{1 - \frac{v^2}{c^2}}} = 2ma \) and cancel \( ma \) from both sides to get \( \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} = 2 \). This equation is the same as in Part (a), leading to \( v = \frac{\sqrt{3}}{2}c \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativistic Momentum
When dealing with objects moving at speeds close to the speed of light, we must use the concept of relativistic momentum instead of the classical or nonrelativistic momentum. Relativistic momentum is given by the formula \( p = \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}} \), where \( m \) is the mass of the object, \( v \) is its velocity, and \( c \) is the speed of light. This equation accounts for the fact that as an object's speed approaches that of light, its momentum increases dramatically.
This contrasts with the nonrelativistic momentum formula \( p = mv \), which only works accurately at speeds much less than the speed of light. By comparing the relativistic and nonrelativistic expressions, we see that the difference between them becomes significant at high speeds. In certain cases, we set up equations like \( \frac{mv}{\sqrt{1 - \frac{v^2}{c^2}}} = 2mv \) to explore these differences in momentum based on velocity.
Nonrelativistic Expression
The nonrelativistic expression of momentum, \( p = mv \), is derived from Newtonian physics and works well for everyday speeds encountered in human-scale activities. This expression assumes that speeds involved are quite small relative to the speed of light. At low speeds, where \( v \ll c \), the effects of relativity become negligible, making the equation \( p = mv \) applicable.
However, as speeds increase, the simplicity of \( p = mv \) starts to fail because it doesn't account for the significant increases in momentum due to relativistic effects. That's where the relativistic momentum equation becomes necessary. It accurately describes momentum at speeds that are a large fraction of the speed of light, ensuring predictions remain consistent with observations.
Speed of Light
The speed of light, denoted as \( c \), is a fundamental constant in physics with a value of approximately \( 3 \times 10^8 \) meters per second. In relativistic physics, the speed of light is not just a very large speed limit; it shapes our understanding of space, time, and energy.
In calculations involving relativistic momentum or force, the speed of light acts as a critical factor. It influences the extent to which the relativistic effects become significant. For instance, when a particle's speed approaches that of light, its momentum and the force required to accelerate it deviate substantially from nonrelativistic predictions. This is why expressions involving \( c \) help calculate when these relativistic effects are strong enough to be considered.
Relativistic Force
Relativistic force takes into account the effects of special relativity on the application of force at high velocities. When dealing with speeds close to that of light, the classical formula for force, \( F = ma \), is adjusted to \( F = \frac{ma}{\sqrt{1 - \frac{v^2}{c^2}}} \).
This modification accounts for the increase in energy and momentum that occurs as a function of velocity. At high velocities, more force is required to achieve the same acceleration compared to when a particle is at rest. Relativistic force is vital in high-speed physics, as it determines how much effort is needed to change the momentum of a fast-moving object. Understanding this concept helps explain experiments and observations in fields like particle physics, where speeds often approach that of light.

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Most popular questions from this chapter

A photon with energy \(E\) is emitted by an atom with mass \(m,\) which recoils in the opposite direction. (a) Assuming that the motion of the atom can be treated nonrelativistically, compute the recoil speed of the atom. (b) From the result of part (a), show that the recoil speed is much less than \(c\) whenever \(E\) is much less than the rest energy \(m c^{2}\) of the atom.

Space pilot Mavis zips past Stanley at a constant speed relative to him of 0.800\(c .\) Mavis and Stanley start timers at zero when the front of Mavis's ship is directly above Stanley. When Mavis reads 5.00 s on her timer, she turns on a bright light under the front of her spaceship. (a) Use the Lorentz coordinate transformation derived in Example 37.6 to calculate \(x\) and \(t\) as measured by Stanley for the event of turning on the light. (b) Use the time dilation formula, Eq. \((37.6),\) to calculate the time interval between the two events (the front of the spaceship passing overhead and turning on the light) as measured by Stanley. Compare to the value of \(t\) you calculated in part (a). (c) Multiply the time interval by Mavis's speed, both as measured by Stanley, to calculate the distance she has traveled as measured by him when the light turns on. Compare to the value of \(x\) you calculated in part (a).

A cube of metal with sides of length \(a\) sits at rest in a frame \(S\) with one edge parallel to the \(x\) -axis. Therefore, in \(S\) the cube has volume \(a^{3} .\) Frame \(S^{\prime}\) moves along the \(x\) -axis with a speed \(u\) . As measured by an observer in frame \(S^{\prime},\) what is the volume of the metal cube?

As you pilot your space utility vehicle at a constant speed toward the moon, a race pilot fies past you in her spaceracer at a constant speed of 0.800\(c\) relative to you. At the instant the spaceracer passes you, both of you start timers at zero. (a) At the instant when you measure that the spaceracer has traveled \(1.20 \times 10^{8} \mathrm{m}\) past you, what does the race pilot read on her timer? (b) When the race pilot reads the value calculated in part (a) on her timer, what does she measure to be your distance from her? (c) At the instant when the race pilot reads the value calculated in part (a) on her timer, what do you read on yours?

An extraterrestrial spaceship is moving away from the earth after an unpleasant encounter with its inhabitants. As it departs, the spaceship fires a missile toward the earth. An observer on earth measures that the spaceship is moving away with a speed of 0.600\(c .\) An observer in the spaceship measures that the missile is moving away from him at a speed of 0.800\(c .\) As measured by an observer on earth, how fast is the missile approaching the earth?

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