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Young's experiment is performed with light from excited helium atoms \((\lambda=502 \mathrm{nm}) .\) Fringes are measured carefully on a screen 1.20 \(\mathrm{m}\) away from the double slit, and the center of the 20 \(\mathrm{th}\) fringe (not counting the central bright fringe) is found to be 10.6 \(\mathrm{mm}\) from the center of the central bright fringe. What is the separation of the two slits?

Short Answer

Expert verified
The separation of the slits is approximately 1.137 mm.

Step by step solution

01

Identify the relevant formula

In Young's double-slit experiment, the distance between the slits, the distance to the screen, and the wavelength determine the position of the fringes. The formula to find the position of a bright fringe is given by \( x = \frac{m \cdot \lambda \cdot L}{d} \), where \( m \) is the fringe order, \( \lambda \) is the wavelength, \( L \) is the distance to the screen, and \( d \) is the separation between the slits.
02

Rearrange the equation to solve for slit separation

The goal is to find the separation of the slits, \( d \). Rearranging the formula gives: \( d = \frac{m \cdot \lambda \cdot L}{x} \). Substitute the given values into this equation.
03

Substitute the known values

Substitute \( m = 20 \), \( \lambda = 502 \times 10^{-9} \text{ m} \), \( L = 1.20 \text{ m} \), and \( x = 10.6 \times 10^{-3} \text{ m} \) into the rearranged equation: \( d = \frac{20 \cdot 502 \times 10^{-9} \cdot 1.20}{10.6 \times 10^{-3}} \).
04

Calculate the slit separation

Perform the calculation: \( d = \frac{20 \cdot 502 \cdot 1.20 \times 10^{-9}}{10.6 \times 10^{-3}} \approx 0.001137 \text{ m} \) or 1.137 mm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fringe Pattern
In Young's double-slit experiment, a fringe pattern is the series of light and dark bands seen on a screen. These bands are created due to the interference of light waves that overlap after passing through two closely spaced slits.

When light waves meet, they either reinforce each other in a process called constructive interference, leading to the bright bands, or they cancel each other out, known as destructive interference, resulting in dark bands.
  • The bright bands are called "bright fringes." These correspond to points where the path length difference between the two waves is an integer multiple of the light's wavelength.
  • The dark bands are "dark fringes", occurring where the path length difference equals half a wavelength, plus any integer multiple of the whole wavelength.
Understanding the fringe pattern is crucial when analyzing optical experiments, as it directly relates to the wave nature of light. The position and spacing of these fringes provide vital information regarding the experimental conditions in Young's setup.
Wavelength of Light
The wavelength of light is a key factor in determining the position of fringes in the double-slit experiment. It is the distance between two consecutive peaks of a light wave and is usually expressed in nanometers (m").

In the original exercise, light from helium atoms with a wavelength of 502 m"); is used, which plays a critical role in the mathematical relationship that affects fringe positions. The formula for fringe position in Young's experiment is given by:
x = \( \frac{m \cdot \lambda \cdot L}{d} \) where:
  • \(x\) is the distance from the central fringe
  • \(m\) is the fringe order
  • \(\lambda\) is the light's wavelength
  • \(L\) is the distance to the screen
  • \(d\) is the slit separation


As seen in this formula, the fringe position is directly proportional to the wavelength, meaning any increase or decrease in wavelength shifts the positions of the fringes.
Slit Separation
Slit separation refers to the distance between the two slits in Young's experiment. It is a crucial variable that affects the interference pattern observed on the screen. Understanding slit separation helps us comprehend how closely the two light sources need to be for interference patterns to form.

The equation used to derive the slit separation is based on the relationship between fringe position and experimental parameters:
d = \( \frac{m \cdot \lambda \cdot L}{x} \)
Where \(d\) represents slit separation.

This mathematical relationship can be explored further:
  • If slit separation \(d\) is decreased, the fringes spread further apart on the viewing screen.
  • A larger slit separation means more often the light waves interfere, resulting in closer fringes on the screen.


For students, calculating slit separation from experimental data is a common task that solidifies understanding of wave interaction principles.
Optical Interference
Optical interference is a fundamental concept in understanding the behavior of light waves, demonstrated vividly in Young's double-slit experiment. It occurs when two or more waves overlap in a medium, either amplifying or diminishing one another, depending on their phase relationship.

In contexts like the double-slit experiment, the two incoming waves either produce a bright (constructive interference) or a dark (destructive interference) fringe.
  • Constructive interference happens when the crests and troughs of two waves align perfectly, reinforcing the wave's amplitude.
  • Destructive interference occurs when a crest meets a trough, canceling the wave's effect.


This concept is not only critical for understanding the pattern of light and dark bands but also has applications across various fields like optics, acoustics, and engineering. It underlies the functionality of many everyday technologies, from noise-canceling headphones to laser devices.

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Most popular questions from this chapter

A plastic film with index of refraction 1.85 is put on the surface of a car window to increase the reflectivity and thus to keep the interior of the car cooler. The window glass has index of refraction \(1.52 .\) (a) What minimum thickness is required if light with wavelength 550 \(\mathrm{nm}\) in air reflected from the two sides of the film is to interfere constructively? (b) It is found to be difficult to manufacture and install coatings as thin as calculated in part (a). What is the next greatest thickness for which there will also be constructive interference?

Coherent light with wavelength 450 nm falls on a double slit. On a screen 1.80 \(\mathrm{m}\) away, the distance between dark fringes is 4.20 \(\mathrm{mm} .\) What is the separation of the slits?

One round face of a 3.25 -m, solid, cylindrical plastic pipe is covered with a thin black coating that completely blocks light. The opposite face is covered with a fluorescent coating that glows when it is struck by light. Two straight, thin, parallel scratches, 0.225 \(\mathrm{mm}\) apart, are made in the center of the black face. When laser light of wavelength 632.8 \(\mathrm{nm}\) shines through the slits perpendicular to the black face, you find that the central bright fringe on the opposite face is 5.82 \(\mathrm{mm}\) wide, measured between the dark fringes that border it on either side. What is the index of refraction of the plastic?

Light with wavelength 648 \(\mathrm{nm}\) in air is incident perpendicularly from air on a film 8.76\(\mu \mathrm{m}\) thick and with refractive index \(1.35 .\) Part of the light is reflected from the first surface of the film, and part enters the film and is reflected back at the second surface, where the film is again in contact with air. (a) How many waves are contained along the path of this second part of the light in its round trip through the film? (b) What is the phase difference between these two parts of the light as they leave the film?

A uniform thin film of material of refractive index 1.40 coats a glass plate of refractive index \(1.55 .\) This film has the proper thickness to cancel normally incident light of wavelength 525 nm that strikes the film surface from air, but it is somewhat greater than the minimum thickness to achieve this cancellation. As time goes by, the film wears away at a steady rate of 4.20 \(\mathrm{nm}\) per year. What is the minimum number of years before the reflected light of this wavelength is now enhanced instead of cancelled?

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