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A concave mirror has a radius of curvature of 34.0 \(\mathrm{cm} .\) (a) What is its focal length? (b) If the mirror is immersed in water (refractive index 1.33), what is its focal length?

Short Answer

Expert verified
(a) 17.0 cm (b) 17.0 cm

Step by step solution

01

Understand the relationship between radius of curvature and focal length

The focal length \( f \) of a mirror is related to the radius of curvature \( R \) by the equation \( f = \frac{R}{2} \). This is the mirror formula.
02

Calculate the focal length in air

Using the given radius of curvature \( R = 34.0 \; \text{cm} \), apply the formula: \( f = \frac{34.0}{2} = 17.0 \; \text{cm} \). The focal length of the mirror in air is 17.0 cm.
03

Understand the effect of medium change on focal length

For a mirror, the focal length is not dependent on the medium it is in. This is because the reflection process in mirrors does not involve any change in speed of light as it does in lenses.
04

Confirm focal length in water remains the same

Since a mirror's focal length is independent of the surrounding medium and is only dependent on its shape (radius of curvature), the focal length remains 17.0 cm even when the mirror is immersed in water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Focal Length
The focal length of a mirror is a fundamental concept in optics. It refers to the distance from the mirror's surface to its focal point, where parallel rays of light converge after being reflected. In the case of a concave mirror, the focal point lies on the same side as the object, resulting in a real and inverted image. The focal length is tied to how strongly the mirror can converge light.

A shorter focal length indicates a stronger curvature, causing light to converge more sharply towards the focal point. Conversely, a longer focal length means the mirror is less curved and converges light less sharply.

To calculate the focal length, you can use the mirror formula, where it equals half of the mirror's radius of curvature: \[ f = \frac{R}{2} \]Where:
  • \( f \) is the focal length.
  • \( R \) is the radius of curvature.
Understanding the focal length helps in predicting how a mirror will form images.
Radius of Curvature
The radius of curvature is key to understanding mirrors and their behavior. Put simply, it is the radius of the spherical surface of which the mirror forms a part. For a concave mirror, this spherical surface bulges inwards towards the source of light.

When a mirror is described as having a '34 cm radius of curvature', it essentially means if the mirror were a complete sphere, that sphere would have a radius of 34 cm. The radius determines the mirror's curvature and, by extension, how it will affect light.

The link between radius of curvature and focal length is critical: \[ f = \frac{R}{2} \]This shows that the focal length is exactly half of the radius of curvature. Hence, knowing the radius allows you to easily find the focal length, offering insight into the mirror's focusing power.
Refractive Index
While refractive index plays a big role in optics, particularly with lenses, it's less influential with mirrors. The refractive index, typically denoted by \( n \), measures how much light slows down in different media compared to a vacuum.

Though you might expect it to affect mirrors, it does not alter the focal length of a concave mirror. This is because reflections in mirrors occur on their surfaces, and the light doesn't pass through the medium.

Mirrors like the one in the problem utilize reflection rather than refraction. Therefore, even when immersed in different media—like water with \( n = 1.33\)—the refractive index does not impact the mirror’s focal length. This is a distinct characteristic of mirrors, setting them apart from lenses which depend heavily on the refractive index.
Mirror Formula
The mirror formula is an essential tool in optics for predicting how mirrors form images. Particularly for concave mirrors, this includes the relationship between focal length, object distance, and image distance.

The widely known mirror formula states:\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]Where:
  • \( f \) is the focal length.
  • \( d_o \) is the object distance, or distance from the object to the mirror.
  • \( d_i \) is the image distance, or distance from the image to the mirror.
This formula helps to determine where the image will be formed once you know the distance of the object and the focal length.

In our initial exercise, the focal length was solely determined using a simpler formula: \[ f = \frac{R}{2} \]. This mirrors formula helps in deeper explorations and complex applications, giving a comprehensive outlook on image formation.

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Most popular questions from this chapter

A photographic slide is to the left of a lens. The lens projects an image of the slide onto a wall 6.00 \(\mathrm{m}\) to the right of the slide. The image is 80.0 times the size of the slide. (a) How far is the slide from the lens? (b) Is the image erect or inverted? (c) What is the focal length of the lens? (d) Is the lens converging or diverging?

You wish to project the image of a slide on a screen 9.00 \(\mathrm{m}\) from the lens of a slide projector. (a) If the slide is placed 15.0 \(\mathrm{cm}\) from the lens, what focal length lens is required? (b) If the dimensions of the picture on a \(35-\mathrm{mm}\) color slide are 24 \(\mathrm{mm} \times 36 \mathrm{mm}\) , what is the minimum size of the projector screen required to accommodate the image?

An object to the left of a lens is imaged by the lens on a screen 30.0 \(\mathrm{cm}\) to the right of the lens. When the lens is moved 4.00 \(\mathrm{cm}\) to the right, the screen must be moved 4.00 \(\mathrm{cm}\) to the left to refocus the image. Determine the focal length of the lens.

A glass plate 3.50 \(\mathrm{cm}\) thick, with an index of refraction of 1.55 and plane parallel faces, is held with its faces horizontal and its lower face 6.00 \(\mathrm{cm}\) above a printed page. Find the position of the image of the page formed by rays making a small angle with the normal to the plate.

Three thin lenses, each with a focal length of \(40.0 \mathrm{cm},\) are aligned on a common axis; adjacent lenses are separated by 52.0 \(\mathrm{cm} .\) Find the position of the image of a small object on the axis, 80.0 \(\mathrm{cm}\) to the left of the first lens.

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