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A toroidal solenoid has 2900 closely wound turns, cross-sectional area \(0.450 \mathrm{cm}^{2},\) mean radius \(9.00 \mathrm{cm},\) and resistance \(R=2.80 \Omega .\) The variation of the magnetic field across the cross section of the solenoid can be neglected. What is the amplitude of the current in the solenoid if it is connected to an ac source that has voltage amplitude 24.0 \(\mathrm{V}\) and frequency 365 \(\mathrm{Hz}\) ?

Short Answer

Expert verified
The amplitude of the current in the solenoid is approximately 8.50 A.

Step by step solution

01

Understand the AC Circuit

In an AC circuit with a solenoid, the impedance is a combination of resistance (R) and inductive reactance (X_L). The formula for the impedance (Z) in an RL circuit is: \[ Z = \sqrt{R^2 + X_L^2} \] where \[ X_L = 2\pi f L \] and \( f \) is the frequency of the AC source, and \( L \) is the inductance of the solenoid.
02

Calculate the Inductance of the Solenoid

The inductance \( L \) of a toroidal solenoid can be calculated using the formula: \[ L = \frac{\mu_0 N^2 A}{2\pi r} \] where \( \mu_0 \) is the permeability of free space \( (4\pi \times 10^{-7} \, \text{Tm/A}) \), \( N \) is the number of turns, \( A \) is the cross-sectional area, and \( r \) is the mean radius.Given: \( N = 2900 \), \( A = 0.450 \times 10^{-4} \, \text{m}^2 \), \( r = 0.09 \, \text{m} \).Substituting the values, we calculate the inductance \( L \).
03

Calculate Inductive Reactance

Using the inductance calculated in Step 2, find the inductive reactance \( X_L \) using: \[ X_L = 2\pi f L \] where \( f = 365 \, \text{Hz} \).
04

Calculate the Impedance

Substitute the resistance \( R = 2.80 \, \Omega \) and the inductive reactance \( X_L \) from Step 3 into the impedance formula: \[ Z = \sqrt{R^2 + X_L^2} \] to calculate the total impedance \( Z \).
05

Calculate Current Amplitude

Use Ohm's Law for AC circuits to find the amplitude of the current \( I \): \[ I = \frac{V}{Z} \] where \( V = 24.0 \, \text{V} \) is the voltage amplitude.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

AC Circuits
An AC circuit is one where the current alternates direction and magnitude. This is common in household electrical systems, which typically have a sinusoidal wave form. An AC source supplies alternating voltage and current, meaning its value changes over time. The frequency of this change is measured in Hertz (Hz), which is the number of cycles per second.
In an AC circuit involving a solenoid, like the toroidal solenoid in our problem, we need to consider more than just the resistance. Because the electric field is constantly changing, it affects the magnetic field in the solenoid. It induces an additional property called inductive reactance, which opposes the change in current and adds to the total impedance of the circuit.
Inductance Calculation
Inductance is a property of an electrical conductor that opposes the change in current. In a toroidal solenoid, the inductance can be calculated using specific parameters. The formula
\[ L = \frac{\mu_0 N^2 A}{2\pi r} \]
lets us calculate inductance, where:
  • \( \mu_0 \) is the permeability of free space.
  • \( N \) is the number of turns.
  • \( A \) is the cross-sectional area.
  • \( r \) is the mean radius.
In the given exercise,
  • \( N = 2900 \)
  • \( A = 0.450 \times 10^{-4} \, \text{m}^2 \)
  • \( r = 0.09 \, \text{m} \)
Substituting the values, we can find the inductance \( L \) of the solenoid, which is crucial for determining how the circuit responds to an AC electrical source.
Impedance in RL Circuit
When dealing with an RL (Resistor-Inductor) circuit in the context of AC circuits, total impedance must be calculated. The impedance, represented by \( Z \), is a combination of the resistance \( R \) and the inductive reactance \( X_L \). The formula to find impedance in such a circuit is:
\[ Z = \sqrt{R^2 + X_L^2} \]
Here, the resistance \( R \) was given as \( 2.80 \, \Omega \), and the inductive reactance \( X_L \) can be determined using the formula \( X_L = 2\pi f L \).
It is essential as impedance impacts how much current will flow through the circuit for a given voltage. By combining \( R \) and \( X_L \) using the formula, the complete opposition to current within the circuit can be understood, which directly influences the current flowing through.
Inductive Reactance
Inductive reactance is a crucial factor in AC circuits, especially those containing inductors like our toroidal solenoid. Inductive reactance \( X_L \) specifically measures how much the inductor opposes the AC current's change. It is dependent on the frequency of the AC battery and the inductor's inductance.
The formula \( X_L = 2\pi f L \) helps calculate the inductive reactance, where \( f \) is the frequency of the AC source and \( L \) is the inductance. In the problem, the frequency \( f \) is given as \( 365 \, \text{Hz} \).
By calculating \( X_L \), we understand how the inductor affects the circuit by resisting the change in current. This is why even a circuit with low resistance can have significant impedance if the inductive reactance is high, affecting the circuit's current flow.

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Most popular questions from this chapter

In an \(L-R-C\) series circuit, \(R=300 \Omega, L=0.400 \mathrm{H},\) and \(C=6.00 \times 10^{-8} \mathrm{F} .\) When the ac source operates at the resonance frequency of the circuit, the current amplitude is 0.500 \(\mathrm{A}\) . (a) What is the voltage amplitude of the source? (b) What is the amplitude of the voltage across the resistor, across the inductor, and across the capacitor? (c) What is the average power supplied by the source?

In an \(L-R-C\) series circuit, the rms voltage across the resistor is \(30.0 \mathrm{V},\) across the capacitor it is \(90.0 \mathrm{V},\) and across the inductor it is 50.0 \(\mathrm{V} .\) What is the rms voltage of the source?

An inductor, a capacitor, and a resistor are all connected in series across an ac source. If the resistance, inductance, and capacitance are all doubled, by what factor does each of the following quantities change? Indicate whether they increase or decrease: (a) the resonance angular frequency; (b) the inductive reactance; (c) the capacitive reactance. (d) Does the impedance double?

A series ac circuit contains a \(250-\Omega\) resistor, a 15 -m \(\mathrm{H}\) inductor, a \(3.5-\mu \mathrm{F}\) capacitor, and an ac power source of voltage amplitude 45 \(\mathrm{V}\) operating at an angular frequency of 360 \(\mathrm{rad} / \mathrm{s}\) , (a) What is the power factor of this circuit? (b) Find the average power delivered to the entire circuit. (c) What is the average power delivered to the resistor, to the capacitor, and to the inductor?

A \(150-\Omega\) resistor is connected in series with a \(0.250-\mathrm{H}\) inductor and an ac source. The voltage across the resistor is \(v_{R}=(3.80 \mathrm{V}) \cos [(720 \mathrm{rad} / \mathrm{s}) t]\) . ( a) Derive an expression for the circuit current. (b) Determine the inductive reactance of the inductor. (c) Derive an expression for the voltage \(v_{L}\) across the inductor.

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