/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Two coils are wound around the s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two coils are wound around the same cylindrical form, like the coils in Example \(30.1 .\) When the current in the first coil is decreasing at a rate of \(-0.242 \mathrm{A} / \mathrm{s}\) , the induced emf in the second coil has magnitude 1.65 \(\times 10^{-3} \mathrm{V}\) . (a) What is the mutual inductance of the pair of coils? (b) If the second coil has 25 turns, what is the flux through each turn when the current in the first coil equals 1.20 \(\mathrm{A} ?\) (c) If the current in the second coil increases at a rate of \(0.360 \mathrm{A} / \mathrm{s},\) what is the magnitude of the induced emf in the first coil?

Short Answer

Expert verified
(a) 6.82 mH; (b) 3.28 x 10^-4 Wb; (c) 2.46 x 10^-3 V.

Step by step solution

01

Calculate Mutual Inductance

Use the formula for mutual inductance: \[ \varepsilon_2 = -M \frac{dI_1}{dt} \] Where \( \varepsilon_2 \) is the induced emf in the second coil and \( \frac{dI_1}{dt} \) is the rate of change of current in the first coil. Rearrange the formula to find:\[ M = \frac{\varepsilon_2}{-\frac{dI_1}{dt}} \]Substitute the known values: \( \varepsilon_2 = 1.65 \times 10^{-3} \) V and \( \frac{dI_1}{dt} = -0.242 \) A/s.So, \( M = \frac{1.65 \times 10^{-3}}{0.242} = 6.82 \times 10^{-3} \) H.
02

Calculate Magnetic Flux

The relationship between mutual inductance and magnetic flux is given by:\[ M = N \frac{\Phi}{I_1} \]Solve for \( \Phi \):\[ \Phi = \frac{M I_1}{N} \]Given \( N = 25 \) turns, \( I_1 = 1.20 \) A, and \( M = 6.82 \times 10^{-3} \) H, substitute these values:\[ \Phi = \frac{6.82 \times 10^{-3} \times 1.20}{25} = 3.28 \times 10^{-4} \] Wb (Weber).
03

Calculate Induced EMF in First Coil

For the second coil's change in current, the formula for induced emf in the first coil is similar:\[ \varepsilon_1 = -M \frac{dI_2}{dt} \]Where \( \varepsilon_1 \) is the induced emf in the first coil, and \( \frac{dI_2}{dt} = 0.360 \) A/s is the rate of change of current in the second coil.Substitute \( M = 6.82 \times 10^{-3} \) H:\[ \varepsilon_1 = -6.82 \times 10^{-3} \times 0.360 = -2.46 \times 10^{-3} \] V.The magnitude is \( 2.46 \times 10^{-3} \) V.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Induced EMF
Electromotive force, or EMF, is a crucial concept in understanding how electric circuits operate. When we talk about **induced EMF**, we are referring to the voltage generated in a circuit due to a changing magnetic field. This generation of EMF comes from electromagnetic induction, a principle established by Faraday's law.

In the context of coils, when the current flowing through one coil changes, it affects the magnetic field around it. This changing magnetic field can induce an EMF in a second coil placed nearby, even if they are not directly connected. This is the fundamental principle behind transformers and various electrical devices.

The induced EMF can be calculated with the formula:
  • \( \varepsilon = -M \frac{dI}{dt} \)
Here, \( M \) represents the mutual inductance between the coils, \( \frac{dI}{dt} \) is the rate of change of current, and the negative sign signifies Lenz's Rule, indicating that the induced EMF acts to oppose the change in current. Understanding this concept helps us comprehend how energy can be transferred wirelessly over a distance between coils.
Magnetic Flux
Magnetic flux is the measure of the magnetic field passing through a given area. It helps us quantify how strong a magnetic field is and how effectively it can influence the environment, especially in electromagnetic induction.

For a coil, the magnetic flux (denoted by \( \Phi \)) is significant because it directly links to how much voltage can be induced when the magnetic field changes. In a practical scenario like in the exercise, knowing the rate at which a magnetic field changes and how many turns the coil has (number of wire loops), can help calculate the total magnetic flux through these turns.

The relationship between mutual inductance and magnetic flux through one coil due to another is expressed as:
  • \( \Phi = \frac{M \times I}{N} \)
Here, \( M \) is the mutual inductance, \( I \) is the current, and \( N \) is the number of turns in the coil. This formula allows us to determine how the magnetic field interacts with the material and geometry of the coil. By determining \( \Phi \), students can understand how coils couple in devices like transformers and generators.
Rate of Change of Current
The rate of change of current is a simple yet impactful concept in electromagnetic induction. It describes how fast the current in a wire is increasing or decreasing over time. This rate is essential because a change in current affects the magnetic field around the wire, and thus influences any nearby conductive materials.

Consider two coils wrapped closely together; when the current in one coil changes rapidly, it causes a significant change in the surrounding magnetic field. This change induces an electromotive force (EMF) in the second coil, demonstrating the principle of electromagnetic induction.

The induced EMF is dependent on the rate at which the current changes, as seen in the formula:
  • \( \varepsilon = -M \frac{dI}{dt} \)
Where \( M \) is the mutual inductance, and \( \frac{dI}{dt} \) is the rate of change of current. This equation shows a direct relationship between how quickly the current in one coil changes and the resultant EMF in the other coil.

In practical applications, controlling the rate at which current changes is crucial for efficient energy transfer in systems like transformers or inductive chargers, making it a vital concept for electrical engineers and students alike.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An inductor used in a dc power supply has an inductance of 12.0 \(\mathrm{H}\) and a resistance of 180\(\Omega .\) It carries a current of 0.300 \(\mathrm{A}\) . (a) What is the energy stored in the magnetic field? (b) At what rate is thermal energy developed in the inductor? (c) Does your answer to part (b) mean that the magnetic-field energy is decreasing with time? Explain.

A \(18.0-\mu \mathrm{F}\) capacitor is placed across a 22.5 \(\mathrm{V}\) batter for several seconds and is then connected across a \(12.0-\mathrm{mH}\) inductor that has no appreciable resistance. (a) After the capacitor and inductor are connected together, find the maximum current in the circuit. When the current is a maximum, what is the charge on the capacitor? (b) How long after the capacitor and inductor are connected together does it take for the capacitor to be completely discharged for the first time? For the second time? (c) Sketch graphs of the charge on the capacitor plates and the current through the inductor as functions of time.

A 7.50 -nF capacitor is charged up to 12.0 \(\mathrm{V}\) , then disconnected from the power supply and connected in series through a coil. The period of oscillation of the circuit is then measured to be \(8.60 \times 10^{-5}\) s. Calculate: (a) the inductance of the coil; (b) the maximum charge on the capacitor; (c) the total energy of the circuit; \((\mathrm{d})\) the maximum current in the circuit.

A 10.0 -cm-long solenoid of diameter 0.400 \(\mathrm{cm}\) is wound uniformly with 800 turns. A second coil with 50 turns is wound around the solenoid at its center. What is the mutual inductance of the combination of the two coils?

A coil has 400 turns and self-inductance 4.80 \(\mathrm{mH}\) The current in the coil varies with time according to \(i=(680 \mathrm{mA}) \cos (\pi t / 0.0250 \mathrm{s})\) . (a) What is the maximum emf induced in the coil? (b) What is the maximum average flux through each turn of the coil? (c) At \(t=0.0180\) s, what is the magnitude of the induced emf?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.