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A shot putter releases the shot some distance above the level ground with a velocity of \(12.0 \mathrm{m} / \mathrm{s}, 51.0^{\circ}\) above the horizontal. The shot hits the ground 2.08 s later. You can ignore air resistance. (a) What are the components of the shot's acceleration while in flight? (b) What are the components of the shot's velocity at the beginning and at the end of its trajectory? (c) How far did she throw the shot horizontally? (d) Why does the expression for \(R\) in Example 3.8 not give the correct answer for part \((\mathrm{c}) ?\) (e) How high was the shot above the ground when she released it? \((\mathrm{f})\) Draw \(x-t\) , \(y-t, v_{x}-t,\) and \(v_{y}-t\) graphs for the motion.

Short Answer

Expert verified
(a) \(a_x = 0, a_y = -9.8\,\mathrm{m/s^2}\), (b) \(v_{0x} = 7.56\,\mathrm{m/s}, v_{0y} = 9.28\,\mathrm{m/s}\), (c) \(\approx 15.7\,\mathrm{m}\), (d) Inappropriate due to height difference, (e) \(\approx 4.24\,\mathrm{m}\).

Step by step solution

01

Components of Acceleration (a)

The only force acting on the shot is gravity, which acts downward. Therefore, the acceleration in the horizontal direction is \(a_x = 0\, \mathrm{m/s^2}\) and the acceleration in the vertical direction is \(a_y = -9.8\, \mathrm{m/s^2}\).
02

Initial Velocity Components (b)

Determine the horizontal and vertical components of the initial velocity using trigonometry. The initial velocity \(v_0 = 12.0\, \mathrm{m/s}\) and the angle of projection \(\theta = 51.0^\circ\). The horizontal component \(v_{0x} = v_0 \cos 51.0^\circ\) and the vertical component \(v_{0y} = v_0 \sin 51.0^\circ\).
03

Components of Velocity at t = 2.08 s (b)

The horizontal velocity remains constant: \(v_{x} = v_{0x}\). For the vertical velocity at \(t = 2.08\, \mathrm{s}: v_{y} = v_{0y} + a_y \cdot t = v_{0y} - 9.8\, \mathrm{m/s^2} \times 2.08\).
04

Calculate Horizontal Range (c)

The horizontal distance \(R\) is the horizontal velocity \(v_{0x}\) times the total time \(t = 2.08\, \mathrm{s}.\) So, \(R = v_{0x} \times t\).
05

Expression for R in Example 3.8 (d)

In Example 3.8, an expression for the range assumes the projectile is launched from ground level with the same initial and final height. In this case, the initial and final vertical positions are different, which affects the range.
06

Initial Height Calculation (e)

Using the vertical motion equation: \( y = v_{0y} \cdot t + \frac{1}{2} \cdot a_y \cdot t^2\) with the final height being 0, solve for the initial height \(y_0\).
07

Graphs of Motion (f)

The \(x-t\) graph is a straight line with a constant slope \(v_{0x}\). The \(y-t\) graph is a parabola opening downward with the vertex at the peak height. The \(v_x-t\) graph is a horizontal line with value \(v_{0x}\). The \(v_y-t\) graph is a straight line with a negative slope, starting at \(v_{0y}\) and ending when it hits the ground.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Understanding kinematics is crucial when studying projectile motion. The term 'kinematics' refers to analyzing the motion of objects without considering the forces that cause the motion. It focuses on several key variables such as displacement, velocity, and acceleration, which help in describing the specific movement of an object.
Kinematics can be broken down into horizontal and vertical components, especially in projectile motion, where an object often moves in a parabolic path. This helps in simplifying the equations and understanding the trajectory better by examining how the horizontal and vertical motions unfold independently of one another.
For instance, in projectile motion, the horizontal motion can be described by a constant velocity due to the absence of horizontal forces (ignoring air resistance), while the vertical motion is affected by gravity, resulting in a constant acceleration downwards.
Velocity Components
Velocity components are an essential part of analyzing projectile motion. When an object is launched at an angle, as in the case of a shot putter launching a shot, the initial velocity separates into two parts: a horizontal and a vertical component.
  • The horizontal component of velocity ( \(v_{0x}\)) can be calculated using the formula: \( v_{0x} = v_0 \cos \theta \), where \( v_0 \) is the initial velocity and \( \theta \) is the angle of launch.
  • The vertical component ( \(v_{0y}\)) is determined similarly: \( v_{0y} = v_0 \sin \theta \).
Once determined, the horizontal velocity remains unchanged throughout the projectile's motion (in the absence of air resistance).
However, the vertical velocity changes due to the acceleration caused by gravity. Understanding these components allows for the accurate prediction of the projectile's path.
Acceleration due to Gravity
Gravity plays a pivotal role in projectile motion by influencing the vertical motion of the object. When discussing the acceleration of a projectile, gravity is the primary force at work. For any object on Earth, the acceleration due to gravity is approximately \( -9.8 \, \mathrm{m/s^2} \).
This negative sign indicates that the force is directed downward. In the context of projectile motion, this constant acceleration affects only the vertical component of the object's velocity. As a result, while the object is in flight, the downward speed increases over time, reaching its maximum just before the object hits the ground.
Despite having no effect on the horizontal velocity, gravity's consistent pull ensures that projectile motions follow a predictable parabolic trajectory. This feature simplifies calculations and makes predicting motion more feasible in educational scenarios.
Trigonometry in Physics
Trigonometry is a powerful tool used in physics, especially for problems involving projectile motion. It allows for the decomposition of vectors into perpendicular components, which simplifies calculations.
In the context of projectile motion, trigonometry helps split the initial velocity into two components:
  • The horizontal component ( \(v_{0x} = v_0 \cos \theta\) ), which tells us how fast the object moves along the horizontal axis.
  • The vertical component ( \(v_{0y} = v_0 \sin \theta\) ), which describes how the velocity is divided along the vertical axis.
These components are crucial to solving many physics problems because they allow us to calculate separate motions along the two directions. This method aids in determining variables such as the maximum height, time of flight, and horizontal range.
Thus, trigonometry simplifies the complexity of analyzing two-dimensional motion by breaking it into more manageable one-dimensional problems.

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Most popular questions from this chapter

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