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A conductor is made in the form of a hollow cylinder with inner and outer radii \(a\) and \(b\) respectively. It carries a current \(I\) uniformly distributed over its cross section. Derive expressions for the magnitude of the magnetic field in the regions (a) \(r < a ;\) (b) \(a < r < b ;(c) r > b\) .

Short Answer

Expert verified
(a) \( B = 0 \); (b) \( B = \frac{\mu_0 I (r^2 - a^2)}{2\pi r (b^2 - a^2)} \); (c) \( B = \frac{\mu_0 I}{2\pi r} \).

Step by step solution

01

Understanding Regions of Interest

First, identify the different regions where we need to find the magnetic field: (a) Inside the hollow region of the cylinder, where \( r < a \), (b) Inside the conductor but outside the hollow region, where \( a < r < b \), and (c) Outside the conductor, where \( r > b \).
02

Applying Ampère's Law for Region (a): \( r < a \)

In this region, the point considered is inside the hollow part of the cylinder where there is no current. Ampère's Law states that the magnetic field \( B \) is zero since no current is enclosed by this path. Hence, \( B = 0 \).
03

Calculating Magnetic Field in Region (b): \( a < r < b \)

Here, consider a circular Amperian loop of radius \( r \) such that \( a < r < b \). The current enclosed by this loop can be calculated using the formula \( I_{enc} = I \cdot \frac{\pi(r^2 - a^2)}{\pi(b^2 - a^2)} \) because the current is uniformly distributed across the cross-sectional area. Then, apply Ampère's Law; \( B \cdot 2\pi r = \mu_0 I_{enc} \) which simplifies to \( B = \frac{\mu_0 I (r^2 - a^2)}{2\pi r (b^2 - a^2)} \).
04

Applying Ampère's Law for Region (c): \( r > b \)

For \( r > b \), the entire current \( I \) is enclosed within the Amperian loop. Applying Ampère's Law gives \( B \cdot 2\pi r = \mu_0 I \), leading to \( B = \frac{\mu_0 I}{2\pi r} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ampère's Law
Ampère's Law is a fundamental principle used to calculate the magnetic field produced by a current distribution. It states that the line integral of the magnetic field around a closed path is proportional to the total current passing through the loop. The mathematical expression of this law is \( \oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I_{enc} \), where \( \mathbf{B} \) is the magnetic field, \( d\mathbf{l} \) is a differential length element on the closed path, \( \mu_0 \) is the permeability of free space, and \( I_{enc} \) is the current enclosed by the path.
Ampère's Law simplifies the process of finding the magnetic field in situations with high symmetry, like in circular or cylindrical conductors. It helps by reducing the problem to a line integral over an appropriately chosen Amperian loop. The symmetry of the problem ensures that the magnetic field has a constant magnitude over the loop, which greatly simplifies the calculations.
Current Distribution in Conductors
The distribution of current in a conductor determines how the magnetic field is generated around it. In many practical cases, especially those involving cylindrical conductors, the current is distributed uniformly across the cross-sectional area. This uniform distribution means that every part of the conductor carries an equal amount of current per unit area.
For a hollow cylindrical conductor, the current only flows in the material between its inner and outer surfaces. The total current \( I \) can be thought of as being spread over the annular area between the inner radius \( a \) and the outer radius \( b \).
This uniform spreading of current implies that the density of current, or current per unit area, is constant. Uniform current distribution assumptions simplify the application of Ampère's Law because they allow for straightforward calculation of the total current enclosed within any Amperian loop.
Hollow Cylindrical Conductors
Hollow cylindrical conductors are a common and practical structure in a variety of electrical systems. This type of conductor features a hollow space within, surrounded by a cylindrical shell where the current flows.
In the case of a hollow cylindrical conductor with inner radius \( a \) and outer radius \( b \):
  • There is no material or current in the region where the radius \( r < a \), leading to no magnetic field in this region.
  • The current flows in the annular region defined by \( a < r < b \), across which the current density is uniform due to the assumption of uniform distribution.
  • Beyond the outer surface (\( r > b \)), the magnetic effects of the whole current flowing through the conductor can be observed. The cylindrical symmetry greatly aids in calculating the magnetic fields in different regions.
Understanding these regions helps in effectively applying Ampère's Law to derive the magnetic field in various parts of the space around and within the conductor.
Magnetic Field Regions
In the context of hollow cylindrical conductors, different regions exhibit distinct magnetic field characteristics based on whether they contain or enclose part of the current. The main regions of interest include:
  • Region 1: Inside the hollow (\( r < a \)) - Here, no current is present, so by Ampère's Law, the magnetic field \( B \) is zero due to no current enclosure.
  • Region 2: Within the conducting material (\( a < r < b \)) - In this region, Ampère's Law reveals that the magnetic field depends on the current enclosed by a loop of radius \( r \). The enclosed current is a fraction of the total current \( I \), calculated based on the area ratio, resulting in a non-zero magnetic field.
  • Region 3: Outside the conductor (\( r > b \)) - Here, the entire current \( I \) is enclosed. The magnetic field behaves as if it were produced by a point-like current source at the cylinder's center, decreasing with distance as \( B = \frac{\mu_0 I}{2\pi r} \).
This clear separation into magnetic field regions helps in understanding and visualizing the behavior of magnetic fields in and around complex conductor geometries like hollow cylinders.

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Most popular questions from this chapter

A long, straight wire lies along the \(z\) -axis and carries a 4.00 -A current in the \(+z\) -direction. Find the magnetic field (magnitude and direction) produced at the following points by a \(0.500-\mathrm{mm}\) segment of the wire centered at the origin: (a) \(x=2.00 \mathrm{m}, y=0\) , \(z=0 ;(\) b) \(x=0, y=2.00 \mathrm{m}, z=0 ;(\mathrm{c}) x=2.00 \mathrm{m}, y=2.00 \mathrm{m}\) \(z=0 ;(\mathrm{d}) x=0, y=0, z=2.00 \mathrm{m}\)

A flat, round iron ring 5.00 \(\mathrm{cm}\) in diameter has a current running through it that produces a magnetic field of 75.4\(\mu \mathrm{T}\) at its center. This ring is placed in a uniform external magnetic field of 0.375 T. What is the maximum torque the external field can exert on the ring? Show how the ring should be oriented relative to the field for the torque to have its maximum value.

Two identical circular, wire loops 40.0 \(\mathrm{cm}\) in diameter each carry a current of 3.80 \(\mathrm{A}\) in the same direction. These loops are parallel to each other and are 25.0 \(\mathrm{cm}\) apart. Line ab is normal to the plane of the loops and passes through their centers. A proton is fired at 2400 \(\mathrm{km} / \mathrm{s}\) perpendicular to line \(a b\) from a point midway between the centers of the loops. Find the magnitude of the magnetic force these loops exert on the proton just after it is fired.

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Lamp Cord Wires. The wires in a household lamp cord are typically 3.0 \(\mathrm{mm}\) apart center to center and carry equal currents in opposite directions. If the cord carries current to a \(100-\mathrm{W}\) light bulb connected across a \(120-\mathrm{V}\) potential difference, what force per meter does each wire of the cord exert on the other? Is the force attractive or repulsive? Is this force large enough so it should be considered in the design of the lamp cord? (Model the lamp cord as a very long straight wire.)

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