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A solenoid is designed to produce a magnetic field of 0.0270 T at its center. It has radius 1.40 \(\mathrm{cm}\) and length \(40.0 \mathrm{cm},\) and the wire can carry a maximum current of 12.0 A. (a) What minimum number of turns per unit length must the solenoid have? (b) What total length of wire is required?

Short Answer

Expert verified
(a) 1790 turns/m; (b) 62.9 meters

Step by step solution

01

Understanding the formula for the magnetic field

The magnetic field \( B \) at the center of a solenoid is given by the formula \( B = \mu_0 n I \), where \( \mu_0 \) is the permeability of free space \( (\mu_0 = 4\pi \times 10^{-7} \, \text{T·m/A}) \), \( n \) is the number of turns per unit length, and \( I \) is the current.
02

Solve for the minimum number of turns per unit length (n)

Rearrange the formula to solve for \( n \): \[ n = \frac{B}{\mu_0 I} \]. Substitute the given values: \( B = 0.0270 \, \text{T} \), \( I = 12.0 \, \text{A} \), and \( \mu_0 = 4\pi \times 10^{-7} \, \text{T·m/A} \). \[ n = \frac{0.0270}{4\pi \times 10^{-7} \times 12.0} \approx 1789.6 \, \text{turns/m} \].
03

Understanding total length of wire needed

The total length of wire \( L_w \) can be calculated by multiplying the number of turns per unit length \( n \) by the length of the solenoid \( L \), and the circumference of each turn, assuming no spacing between turns. The circumference \( C \) is \( 2\pi R \), where \( R = 1.40 \, \text{cm} = 0.0140 \, \text{m} \).
04

Calculate total length of wire (L_w)

First, calculate the number of turns \( N \) : \( N = n \times L = 1789.6 \, \text{turns/m} \times 0.40 \, \text{m} = 715.84 \, \text{turns} \). Then calculate the total wire length: \[ L_w = N \times (2\pi R) = 715.84 \times 2\pi \times 0.0140 \approx 62.9 \, \text{meters} \].
05

Conclusion

The minimum number of turns per unit length required is approximately 1790 turns/m, and the total length of wire needed is approximately 62.9 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Turns Per Unit Length
The concept of turns per unit length in a solenoid is essential for determining the magnetic field strength. A solenoid is essentially a coil of wire, and its ability to generate a magnetic field depends on how tightly the wire is coiled.
  • Definition: The term "turns per unit length," denoted as \( n \), refers to how many loops or turns of wire are present in a given length of the solenoid, measured in turns per meter (turns/m).
  • Importance: More turns within a specified length result in a stronger magnetic field, assuming a constant current flows through the wire.
Given the formula for the magnetic field of a solenoid, \( B = \mu_0 n I \), it's clear that \( n \) directly influences the magnetic field strength \( B \). Here, solving for \( n \) when given a specific magnetic field, current, and the permeability of free space allows us to design a solenoid to meet specific field requirements.For example, using the formula \[ n = \frac{B}{\mu_0 I} \] with "\( B = 0.0270 \text{ T} \), " and "\( I = 12.0 \text{ A} \)," results in "1789.6 turns/m," ensuring the desired magnetic field is achieved.
Permeability of Free Space
Permeability of free space, denoted as \( \mu_0 \), is a fundamental physical constant critical in understanding how magnetic fields behave in a vacuum. This constant helps relate the magnetic field inside a solenoid to the current through the wire and the number of coil turns.
  • Definition: It represents the ability of a vacuum to support a magnetic field and is a constant value given by \( \mu_0 = 4\pi \times 10^{-7} \text{ T·m/A} \).
  • Role in Solenoids: This parameter influences the magnetic field strength inside a solenoid. Higher permeability indicates an easier formation of magnetic fields.
Understanding this concept allows us to connect theoretical magnetic scenarios, such as those occurring in a vacuum, to practical real-world applications. In the context of solenoids, \( \mu_0 \) helps quantify how efficiently the current and coil configuration transform into a magnetic field.
Wire Length Calculation
Calculating the total length of wire needed to form a solenoid involves understanding both the number of turns the solenoid needs and the physical dimensions of each turn. This ensures the solenoid is constructed to meet required specifications for its magnetic field.
  • Key components: You need the number of turns \( N \), which is found using the product of turns per unit length \( n \) and the solenoid's length \( L \).
  • Turn Circumference: Each turn has a perimeter defined by the solenoid's radius \( R \): \( C = 2\pi R \).
Given these calculations: "\( N = n \times L = 1789.6 \text{ turns/m} \times 0.40 \text{ m} = 715.84 \text{ turns} \)," and "\[ L_w = N \times (2\pi R) = 715.84 \times 2\pi \times 0.0140 \approx 62.9 \text{ meters} \]," you ensure the wire length is precise for constructing the solenoid effectively. This precise measurement allows for efficient material use and ensures the solenoid will perform as designed.

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Most popular questions from this chapter

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