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Two small plastic spheres are given positive electrical charges. When they are 15.0 \(\mathrm{cm}\) apart, the repulsive force between them has magnitude 0.220 \(\mathrm{N} .\) What is the charge on each sphere (a) if the two charges are equal and (b) if one sphere has four times the charge of the other?

Short Answer

Expert verified
(a) The charge on each sphere is approximately 1.94 x 10^-8 C.

Step by step solution

01

Understanding Coulomb's Law

Coulomb's Law describes the force between two charges. The formula is \[ F = k \frac{q_1 q_2}{r^2} \] where \( F \) is the force, \( k \) is the Coulomb's constant \( 8.99 \times 10^9 \, \mathrm{N \cdot m^2/C^2} \), \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the separation distance, converted into meters.
02

Solve Part (a) - Charges are Equal

For part (a), let the charges be equal \( q_1 = q_2 = q \). Then, \[ F = k \frac{q^2}{r^2} \] Substitute \( F = 0.220 \, \mathrm{N} \) and \( r = 0.15 \, \mathrm{m} \), which gives \[ 0.220 = (8.99 \times 10^9) \frac{q^2}{0.15^2} \] Solving for \( q \), we get \[ q = \sqrt{\frac{0.220 \times 0.15^2}{8.99 \times 10^9}} \approx 1.94 \times 10^{-8} \, \mathrm{C} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Charges
Electrical charges are fundamental properties of matter, existing in two types: positive and negative. The interaction between these charges is what gives rise to electromagnetic forces. Imagine charges like tiny invisible hands that can push or pull on objects, depending on their nature.

Similar charges, like two positive or two negative charges, repel each other. It's as if they both want to occupy the same space but can't, thus pushing away from each other. Conversely, opposite charges, meaning one positive and one negative, attract each other, much like magnets with opposite poles. This intricate dance of attraction and repulsion forms the basis for many electrical phenomena we observe in our everyday lives.
  • Positive charges result from a deficiency of electrons, making other protons noticeable.
  • Negative charges arise when there are excess electrons.
  • The unit of charge is called a coulomb (C).
Understanding these basic interactions helps explain how two similarly charged plastic spheres in the exercise exhibit a repulsive force, pushing away from each other.
Repulsive Force
A repulsive force is a form of electrostatic force that acts to push two charged objects apart from one another. In the context of the exercise, when the two spheres have positive charges, they naturally repel each other. You can think of this force as a kind of invisible barrier preventing the spheres from getting closer.

This repulsion can be calculated using Coulomb's Law, which provides a quantitative measure of the force between the two charges. It's a key concept for students to understand, as it governs not just this problem, but many other interactions in physics and chemistry.
  • Repulsive forces between like charges increase as the distance between them decreases.
  • The magnitude of the force depends on both the amount of charge and the separation distance.
  • As distance increases, the repulsive force decreases exponentially, meaning small changes in distance can lead to large changes in force.
This principle is fundamental in understanding how objects charged with the same type create spaces between themselves.
Coulomb's Constant
Coulomb's constant (\( k \)) is a vital number in the realm of electrostatics. It appears in Coulomb's Law and helps quantify the strength of the electrostatic force between two charges. This constant, with a value of approximately \( 8.99 \times 10^9 \, \mathrm{N \cdot m^2/C^2} \), reflects the electrical permittivity of free space, essentially describing how electric field lines behave in a vacuum.

In simpler terms, it helps calculate how strongly two charged objects will interact with each other. It's kind of like the "weight" of an interaction, ensuring we have a consistent unit to measure these forces.
  • Coulomb's constant makes it possible to predict and measure the force accurately across different distances and charges.
  • This constant is derived from experimental data and is one of the fundamental constants in physics.
  • It bridges the gap between theoretical physics and practical, real-world measurements, making theoretical values applicable and useful.
With this constant, we can compare and understand forces not just in one set of conditions but across any scenario involving electrical charges, grounding our understanding of the electrical nature of forces.

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Most popular questions from this chapter

cp Strength of the Electric Force. Imagine two 1.0 -g bags of protons, one at the earth's north pole and the other at the south pole. (a) How many protons are in each bag? (b) Calculate the gravitational attraction and the electrical repulsion that each bag exerts on the other. (c) Are the forces in part (b) large enough for you to feel if you were holding one of the bags?

Particles in a Gold Ring. You have a pure (24 karat) gold ring with mass 17.7 \(\mathrm{g}\) . Gold has atomic mass of 197 \(\mathrm{g} / \mathrm{mol}\) and an atomic number of \(79 .\) (a) How many protons are in the ring, and what is their total positive charge? (b) If the ring carries no net charge, how many electrons are in it?

Electric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 \(\mathrm{N} / \mathrm{C}\) and directed in toward the center of the earth. (a) What magnitude and sign of charge would a \(60-\mathrm{kg}\) human have to acquire to overcome his or her weight by the force exerted by the earth's electric field? (b) What would be the force of repulsion between two people each with the charge calculated in part (a) and separated by a distance of 100 \(\mathrm{m} ?\) Is use of the earth's electric field a feasible means of flight? Why or why not?

Three point charges are arranged along the \(x\) -axis. Charge \(q_{1}=+3.00 \mu C\) is at the origin, and charge \(q_{2}=-5.00 \mu C\) is at \(x=0.200 \mathrm{m} .\) Charge \(q_{3}=-8.00 \mu \mathrm{C} .\) Where is \(q_{3}\) located if the net force on \(q_{1}\) is 7.00 \(\mathrm{N}\) in the \(-x\) -direction?

An average human weighs about 650 \(\mathrm{N} .\) If two such generic humans each carried 1.0 coulomb of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction hetween them to equal their \(650-\mathrm{N}\) weight?

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