/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 A sophomore with nothing better ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A sophomore with nothing better to do adds heat to 0.350 \(\mathrm{kg}\) of ice at \(0.0^{\circ} \mathrm{C}\) until it is all melted. (a) What is the change in entropy of the water? (b) The source of heat is a very massive body at a temperature of \(25.0^{\circ} \mathrm{C}\) . What is the change in entropy of this body? (c) What is the total change in entropy of the water and the heat source?

Short Answer

Expert verified
(a) 428.1 J/K, (b) -392.0 J/K, (c) 36.1 J/K

Step by step solution

01

Determine the Heat Required to Melt the Ice

To find the heat required to melt the ice, use the formula: \( Q = mL_f \), where \( m = 0.350 \, \text{kg} \) and \( L_f = 334,000 \, \text{J/kg} \) (latent heat of fusion for ice). Calculate \( Q \) as follows:\[Q = 0.350 \, \text{kg} \times 334,000 \, \text{J/kg} = 116,900 \, \text{J}\]This amount of heat is needed to change the ice at 0°C to water at 0°C.
02

Calculate the Change in Entropy of the Water

The change in entropy for the water can be calculated using the formula: \( \Delta S_w = \frac{Q}{T_w} \), where \( Q = 116,900 \, \text{J} \) and \( T_w = 273.15 \, \text{K} \) (which is 0.0°C in Kelvin). Thus,\[\Delta S_w = \frac{116,900 \, \text{J}}{273.15 \, \text{K}} \approx 428.1 \, \text{J/K}\]This is the increase in entropy of the water after melting.
03

Calculate the Change in Entropy of the Heat Source

The change in entropy of the heat source is given by \( \Delta S_{hs} = -\frac{Q}{T_{hs}} \), where \( T_{hs} = 298.15 \, \text{K} \) (which is 25°C in Kelvin). Calculate \( \Delta S_{hs} \) as follows:\[\Delta S_{hs} = -\frac{116,900 \, \text{J}}{298.15 \, \text{K}} \approx -392.0 \, \text{J/K}\]This is the decrease in entropy of the heat source.
04

Find the Total Change in Entropy

The total change in entropy is the sum of the entropy changes of the water and the heat source:\[\Delta S_{total} = \Delta S_w + \Delta S_{hs} \approx 428.1 \, \text{J/K} - 392.0 \, \text{J/K} = 36.1 \, \text{J/K}\]This reflects the overall increase in entropy of the universe due to the process.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Latent Heat of Fusion
When we talk about changing a substance from a solid to a liquid, like ice turning into water, there's a special type of heat involved. This is called the latent heat of fusion. It is the hidden energy required to change the state of a substance without changing its temperature.
For water, the latent heat of fusion is quite high, specifically 334,000 J/kg. This means for each kilogram of ice at 0°C, 334,000 joules of heat are needed to turn it into liquid water at the same temperature.
This energy breaks the bonds holding the ice structure, allowing the molecules to move freely and form a liquid. It's crucial for accurately calculating how much energy we need during processes involving melting or freezing. Hence, in any problems related to melting, remember to use the latent heat of fusion formula:
  • \(Q = mL_f\) where \(m\) is the mass and \(L_f\) is the latent heat of fusion.
Entropy Calculation
Entropy is a measure of disorder or randomness in a system. For the melting ice problem, calculating the change in entropy involves considering the heat added to the system and the temperature at which it occurs.
When ice at 0°C melts, it absorbs heat while remaining at a constant temperature. The change in entropy (ΔS) can be calculated using the formula:
  • \( ∆S = \frac{Q}{T} \)
where \(Q\) is the heat absorbed and \(T\) is the temperature in Kelvin. In the example, ice absorbed 116,900 J of heat at 0°C, or 273.15 K.
Replacing these values gives us:
  • \( ∆S = \frac{116,900 \, ext{J}}{273.15 \, ext{K}} \approx 428.1 \, ext{J/K} \)
This positive change indicates an increase in entropy, as liquid water is more disordered than solid ice.
Thermodynamic Processes
Thermodynamic processes describe how systems exchange energy as heat and work. The transfer of heat can lead to changes in entropy, as we saw with our ice melting example.
Let's summarize various key ideas about these processes:
  • **Isothermal process:** Occurs at a constant temperature. In our problem, the ice melts at 0°C.
  • **Isobaric process:** Happens when the pressure stays constant.
  • **Adiabatic process:** Involves no heat exchange with the environment. Here, energy stays within the system, purely altering internal temperature or pressure.
  • **Isochoric process:** The volume remains constant.
While these terms define various types of thermodynamic processes, they highlight the universal importance of heat, temperature, and energy exchange in determining how substances behave under different conditions.
In our original exercise, the melting of ice represents an isothermal process, showcasing how energy is required to cause phase changes even without temperature variation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Carnot engine is operated between two heat reservoirs at temperatures of 520 \(\mathrm{K}\) and 300 \(\mathrm{K}\) . (a) If the engine receives 6.45 \(\mathrm{kJ}\) of heat energy from the reservoir at 520 \(\mathrm{K}\) in each cycle, how many joules per cycle does it discard to the reservoir at 300 \(\mathrm{K}\) ? (b) How much mechanical work is performed by the engine during each cycle? (c) What is the thermal efficiency of the engine?

A certain brand of freezer is advertised to use 730 \(\mathrm{kW} \cdot \mathrm{h}\) of energy per year. (a) Assuming the freezer operates for 5 hours each day, how much power does it require while operating? (b) If the freezer keeps its interior at a temperature of \(-5.0^{\circ} \mathrm{C}\) in a \(20.0^{\circ} \mathrm{C}\) room, what is its theoretical maximum performance coefficient? (c) What is the theoretical maximum amount of ice this freezer could make in an hour, starting with water at \(20.0^{\circ} \mathrm{C} ?\)

You design an engine that takes in \(1.50 \times 10^{4} \mathrm{J}\) of heat at 650 \(\mathrm{K}\) in each cycle and rejects heat at a temperature of 350 \(\mathrm{K}\). The engine completes 240 cycles in 1 minute. What is the theoretical maximum power output of your engine, in horsepower?

An experimental power plant at the Natural Energy Laboratory of Hawaii generates electricity from the temperature gradient of the ocean. The surface and deep-water temperatures are \(27^{\circ} \mathrm{C}\) and \(6^{\circ} \mathrm{C},\) respectively. (a) What is the maximum theoretical efficiency of this power plant? (b) If the power plant is to produce 210 \(\mathrm{kW}\) of power, at what rate must he extracted from the warm water? At what rate must heat be absorbed by the cold water? Assume the maximum theoretical efficiency. (c) The cold water that enters the plant leaves it at a temperature of \(10^{\circ} \mathrm{C}\) . What must be the flow rate of cold water through the system? Give your answer in \(\mathrm{kg} / \mathrm{h}\) and in \(\mathrm{L} / \mathrm{h}\) .

You are designing a Carnot engine that has 2 \(\mathrm{mol}\) of \(\mathrm{CO}_{2}\) as its working substance; the gas may be treated as ideal. The gas is to have a maximum temperature of \(527^{\circ} \mathrm{C}\) and a maximum pressure of 5.00 atm. With a heat input of 400 \(\mathrm{J}\) per cycle, you want 300 \(\mathrm{J}\) of useful work. (a) Find the temperature of the cold reservoir. (b) For how many cycles must this engine run to melt completely a 10.0 -kg block of ice originally at \(0.0^{\circ} \mathrm{C},\) using only the heat rejected by the engine?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.