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An aircraft engine takes in 9000 \(\mathrm{J}\) of heat and discards 6400 \(\mathrm{J}\) each cycle. (a) What is the mechanical work output of the engine during one cycle? (b) What is the thermal efficiency of the engine?

Short Answer

Expert verified
(a) 2600 J, (b) 28.89%

Step by step solution

01

Determine Work Output

The work output in a thermodynamic cycle can be found using the formula: \( W = Q_{in} - Q_{out} \), where \( W \) is the work done, \( Q_{in} \) is the heat taken in, and \( Q_{out} \) is the heat discarded. Given \( Q_{in} = 9000 \, \mathrm{J} \) and \( Q_{out} = 6400 \, \mathrm{J} \), substitute these values into the formula:\[W = 9000 \, \mathrm{J} - 6400 \, \mathrm{J} = 2600 \, \mathrm{J}\]Thus, the work output is \( 2600 \, \mathrm{J} \).
02

Calculate Thermal Efficiency

The thermal efficiency \( \eta \) of an engine is calculated using the formula: \( \eta = \frac{W}{Q_{in}} \), where \( W \) is the work output and \( Q_{in} \) is the heat input. From the previous step, \( W = 2600 \, \mathrm{J} \) and \( Q_{in} = 9000 \, \mathrm{J} \). Plug these values into the efficiency formula:\[\eta = \frac{2600 \, \mathrm{J}}{9000 \, \mathrm{J}} = 0.2889\]Convert this value to percentage by multiplying by 100:\[\eta = 0.2889 \times 100 \approx 28.89\%\]The thermal efficiency of the engine is approximately \( 28.89\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work Output
In thermodynamics, the concept of work output is pivotal in understanding how energy is converted within a system. To grasp this idea, it's important to know that when an engine undergoes a cycle, it absorbs a certain amount of heat, known as the heat input, and discards some waste heat. The work output is essentially the energy that is converted into useful mechanical work from the absorbed heat.
Using the formula:
  • \( W = Q_{in} - Q_{out} \)
you can determine the work output, \( W \). Here, \( Q_{in} \) is the heat added to the system, and \( Q_{out} \) is the heat energy expelled or discarded. In the context of an aircraft engine, if it takes in 9000 Joules and discards 6400 Joules each cycle, the work output amounts to \( 2600 \, \mathrm{J} \) since:
  • \( W = 9000 \, \mathrm{J} - 6400 \, \mathrm{J} = 2600 \, \mathrm{J} \)
The work output measures the net energy that has been transformed into mechanical work, which is critical for assessing the performance and efficiency of an engine.
Heat Input
Heat input is a fundamental concept in thermodynamics. It refers to the total heat energy taken in by a system during a cycle. For an engine, this heat is converted into work and some of it is lost as waste heat. Understanding how much energy an engine can convert is critical for enhancing performance.
In practice, this concept is best seen in engines or machines where heat energy from fuel combustion is used to do work. For example, in a typical thermodynamic cycle of an aircraft engine, 9000 Joules (\(Q_{in}\) ) of heat could be introduced to the system. This energy becomes the potential to generate work before any losses that occur due to expelling waste heat.
  • Heat input is crucial for determining how much mechanical energy can be harvested.
  • The value of heat input directly impacts the work output and overall efficiency.
Thus, maximizing heat input for conversion to work, while minimizing waste heat, is a key focus in engine design.
Thermal Efficiency
Thermal efficiency is a measure of how well an engine converts heat input into useful work. It is essentially a ratio comparing the work output of a system to the heat input. The formula for calculating thermal efficiency, \( \eta \), is:
  • \( \eta = \frac{W}{Q_{in}} \)
Where \( W \) is the work output and \( Q_{in} \) is the heat input. In our aircraft engine example, with a work output of 2600 Joules and heat input of 9000 Joules, the thermal efficiency is:
  • \( \eta = \frac{2600 \, \mathrm{J}}{9000 \, \mathrm{J}} = 0.2889 \)
Converted to a percentage, this is approximately \( 28.89\% \).
Thermal efficiency is a critical factor in engine performance analysis because it indicates the percentage of input energy effectively converted to work.
  • If an engine has higher thermal efficiency, it means less energy is wasted as heat.
  • Engineers aim to design systems with high thermal efficiency to improve performance and reduce fuel costs.
However, due to inherent losses in the cycle, achieving 100% efficiency is impossible according to the second law of thermodynamics.

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Most popular questions from this chapter

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