/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 A turtle crawls along a straight... [FREE SOLUTION] | 91Ó°ÊÓ

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A turtle crawls along a straight line, which we will call the \(x\) -axis with the positive direction to the right. The equation for the turtle's position as a function of time is \(x(t)=50.0 \mathrm{cm}+\) \((2.00 \mathrm{cm} / \mathrm{s}) t-\left(0.0625 \mathrm{cm} / \mathrm{s}^{2}\right) t^{2}\) (a) Find the turtle's initial velocity, initial position, and initial acceleration. (b) At what time \(t\) is the velocity of the turtle zero? (c) How long after starting does it take the turtle to return to its starting point? (d) At what times \(t\) is the turtle a distance of 10.0 \(\mathrm{cm}\) from its starting point? What is the velocity (magnitude and direction) of the turtle at each of these times? (e) Sketch graphs of \(x\) versus \(t, v_{x}\) versus \(t,\) and \(a_{x}\) versus \(t\) for the time interval \(t=0\) to \(t=40 \mathrm{s}.\)

Short Answer

Expert verified
(a) Initial values: 50.0 cm, 2.00 cm/s, -0.125 cm/s². (b) Velocity is zero at 16 s. (c) Returns at 32 s. (d) 10 cm away at 8 s and 24 s. Velocities are 1 cm/s and -1 cm/s.

Step by step solution

01

Analyzing the Position Function

The turtle's position function is given by \( x(t) = 50.0\, \text{cm} + (2.00\, \text{cm/s})t - (0.0625\, \text{cm/s}^2)t^2 \). This is a quadratic function in \( t \) representing a motion with constant acceleration.
02

Finding Initial Values

(a) The initial position is found by evaluating \( x(0) \). This gives \( x(0) = 50.0\, \text{cm} \). The initial velocity \( v(0) \) is the coefficient of \( t \), which is \( 2.00\, \text{cm/s} \). The initial acceleration can be determined from the second derivative of \( x(t) \), which is \( -0.125\, \text{cm/s}^2 \).
03

Finding When Velocity is Zero

(b) The velocity function is the first derivative of the position function: \( v(t) = 2.00 - 0.125t \). Set this to zero to find when the velocity is zero: \( 0 = 2.00 - 0.125t \). Solving for \( t \) gives \( t = 16.0\, \text{s} \).
04

Returning to the Starting Point

(c) To find when the turtle returns to the starting point, set the position equal to the initial position: \( 50.0 + 2.00t - 0.0625t^2 = 50.0 \). Simplify to \( 2.00t - 0.0625t^2 = 0 \) and solve for \( t \), yielding \( t = 0 \) or \( t = 32.0\, \text{s} \).
05

Distance from Starting Point

(d) Set the position function to be 10 cm away from the start: \( |x(t) - 50.0| = 10.0 \). Solve \( x(t) = 60.0 \) and \( x(t) = 40.0 \). The solutions are \( t = 8.0 \) and \( t = 24.0\, \text{s} \). Next, find the velocity at these times using \( v(t) = 2.00 - 0.125t \): \( v(8) = 1.0\, \text{cm/s} \) and \( v(24) = -1.0\, \text{cm/s} \).
06

Sketching the Graphs

(e) For sketching: The plot of \( x(t) \) vs. \( t \) is a downward-opening parabola starting from 50.0 cm. The \( v(t) \) vs. \( t \) graph is a straight line with a negative slope, crossing zero at \( t = 16 \) s. The \( a(t) \) is constant and negative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position Function
In kinematics, the position function is a key concept that describes the location of an object along an axis at any given time. For the turtle crawling along the straight line, the position function is provided as:\[x(t) = 50.0 \text{ cm} + (2.00 \text{ cm/s}) t - (0.0625 \text{ cm/s}^2) t^2\]This quadratic equation is important because it tells us not just where the turtle begins, but how its position changes with time.
  • The constant term, 50.0 cm, represents the initial position of the turtle.
  • The linear term, \(2.00 \text{ cm/s} \times t\), indicates how the turtle's position changes due to its initial velocity.
  • The quadratic term, \(-(0.0625 \text{ cm/s}^2) t^2\), accounts for the impact of acceleration on the position over time.
Through this function, we can determine where the turtle is at any time \(t\), and the nature of its movement is characterized by the determined coefficients, showing a constant acceleration scenario.
Velocity
Velocity in kinematics refers to the speed of something in a given direction. It is the rate of change of the object's position with respect to time. For the turtle, the velocity function is derived from the position function by differentiating it with respect to time: \[v(t) = \frac{d}{dt} [50.0 + (2.00 \text{ cm/s}) t - (0.0625 \text{ cm/s}^2) t^2] = 2.00 \text{ cm/s} - 0.125 \text{ cm/s}^2 \times t\]This equation expresses velocity as a function of time, showing that the turtle has an initial velocity and experiences a constant deceleration:
  • The constant initial velocity is \(2.00 \text{ cm/s}\).
  • The velocity decreases over time due to the negative acceleration, \(-0.125 \text{ cm/s}^2\), resulting in a linear decline.
You can find specific velocity values by substituting different time values into this equation. For instance, when the velocity is zero, the turtle changes direction, calculated by setting: \[v(t) = 0 = 2.00 - 0.125t \]Solving this gives \(t = 16\text{ s}\), the point at which the turtle stops before reversing direction.
Acceleration
In physics, acceleration refers to the rate at which an object changes its velocity. For our crawling turtle, acceleration is constant and can be discovered by taking the second derivative of the position function or the first derivative of the velocity function: \[a(t) = \frac{d^2}{dt^2} [50.0 + (2.00 \text{ cm/s}) t - (0.0625 \text{ cm/s}^2) t^2] = -0.125 \text{ cm/s}^2\]This negative acceleration shows that as time increases, the speed of the turtle reduces. This negative value indicates deceleration:
  • This means that for each second, the velocity of the turtle decreases by \(0.125 \text{ cm/s}\).
  • As acceleration doesn't change over time, the velocity decreases linearly.
This constant deceleration is a crucial part of understanding how the turtle's motion changes from forward movement, to a stop, and then reversing its path.
Equation of Motion
Equations of motion are used to describe the mathematical relationship between an object's displacement, velocity, and acceleration over time. In this scenario, the motion is described by:Position function: \[x(t) = 50.0 \text{ cm} + (2.00 \text{ cm/s}) t - (0.0625 \text{ cm/s}^2)t^2\]Velocity function:\[v(t) = 2.00 \text{ cm/s} - 0.125 \text{ cm/s}^2 \times t\]Acceleration is constant:\[a(t) = -0.125 \text{ cm/s}^2\]These equations help in predicting the turtle's future position, velocity, and behavior under constant acceleration.
  • Knowing the initial position, velocity, and acceleration helps in solving various problems, like finding when the turtle returns to the start or reaches a certain distance.
  • Equations of motion can also be represented graphically, showcasing how turtle's position, velocity, and acceleration change over time.
In summary, these equations form the backbone of analyzing linear motion with constant acceleration in kinematics.

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Most popular questions from this chapter

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