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Heat \(Q\) flows into a monatomic ideal gas, and the volume increases while the pressure is kept constant. What fraction of the heat energy is used to do the expansion work of the gas?

Short Answer

Expert verified
The fraction of heat energy used for work is \(\frac{2}{5}\).

Step by step solution

01

Understanding the Problem

We need to find the fraction of heat energy (\(Q\)) used to do work (\(W\)) when a monatomic ideal gas expands at constant pressure.
02

Remembering Key Formulas

For a process at constant pressure, the first law of thermodynamics states: \( Q = \Delta U + W \), where \(\Delta U\) is the change in internal energy and \(W\) is the work done by the system.
03

Determining Change in Internal Energy

For a monatomic ideal gas, the change in internal energy is \(\Delta U = \frac{3}{2}nR\Delta T\). Since pressure is constant, \(W = P\Delta V\). Also, \(W = nR\Delta T\), given that \(P\Delta V = nR\Delta T\).
04

Calculating Fraction of Heat Doing Work

The fraction of heat used for work is \( \frac{W}{Q} = \frac{nR\Delta T}{Q} \). Substitute \(Q = \Delta U + W = \frac{3}{2}nR\Delta T + nR\Delta T\).
05

Simplifying the Fraction

The total heat added is \(Q = \frac{5}{2}nR\Delta T \). Hence, the fraction of heat energy used to do work is \( \frac{W}{Q} = \frac{nR\Delta T}{\frac{5}{2}nR\Delta T} = \frac{2}{5}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Monatomic Ideal Gas
In thermodynamics, a monatomic ideal gas is a fundamental concept for understanding the behavior of gases under various conditions. These gases consist of single-atom particles, meaning their simplicity makes it easier to predict and calculate their responses to changes in temperature, pressure, and volume.
A key feature of a monatomic ideal gas is that its internal energy extit{U} depends only on its temperature and the amount of substance extit{n}. The formula relating the internal energy to temperature is given by:
  • \( U = \frac{3}{2}nRT \)
where \(R\) is the universal gas constant and \(T\) is the temperature in Kelvin. This equation highlights why monatomic gases are excellent models for studying basic thermodynamic principles. Knowing how changes in these conditions affect the gas, we can derive other important quantities, such as work done and heat absorbed.
When we apply this knowledge, it helps simplify the calculations in exercises involving monatomic ideal gases, particularly when exploring their heat and expansion characteristics.
First Law of Thermodynamics
The First Law of Thermodynamics is crucial in understanding energy transformations in any thermodynamic system, including monatomic ideal gases. This law, which is essentially the law of energy conservation, states that the energy added to the system as heat must equal the change in internal energy plus the work done by the system on its surroundings.
  • Mathematically expressed as: \( Q = \Delta U + W \)
where:
  • \(Q\) is the heat added to the system
  • \(\Delta U\) is the change in internal energy
  • \(W\) is the work done by the system
Understanding this law allows you to track how energy flows in and out of the system. It helps relate how much of the energy is retained as internal heat and how much is used to perform work, such as when gas expands at constant pressure. These principles are at the heart of comprehending the behavior of gases in thermodynamic processes.
Heat Energy
In thermodynamics, heat energy \(Q\) plays a critical role in changing the state of a substance. When heat energy is added to a monatomic ideal gas, it can either increase the gas's internal energy or perform expansion work.
  • For a process at constant pressure, the heat energy is divided between changing the internal energy and expansion work: \( Q = \frac{3}{2}nR\Delta T + nR\Delta T \)
Here, each term represents:
  • \(\frac{3}{2}nR\Delta T\) indicating the change in internal energy
  • \(nR\Delta T\) describing the work done by the system
This energy distribution reflects the very essence of thermodynamic cycles, where a portion of input energy is invested in altering the internal energy, while the rest is allocated to performing work. Understanding this balance is key to mastering concepts like efficiencies of engines and refrigerators, which rely on transforming heat energy into useful work.
Expansion Work
Expansion work is a concept in thermodynamics describing the work a system does as it expands against an external pressure. For a monatomic ideal gas expanding at constant pressure, the work done during expansion can be calculated by:
  • \( W = P\Delta V \)
  • Alternatively, equivalently as: \( W = nR\Delta T \)
These equations translate the expansion process into understandable math, showcasing how changes in volume relate to energy. In our context, the exercise determined the fraction of heat energy used to do expansion work, found by the equation:
  • \( \frac{W}{Q} = \frac{2}{5} \)
This fraction means that 40% of the heat energy supplied is used to perform work during the expansion. Recognizing how much energy is used this way gives insights into the efficiency and functioning of gas processes. It also emphasizes the importance of understanding thermodynamic principles when analyzing energy transformations in practical applications.

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Most popular questions from this chapter

Two moles of carbon monoxide (CO) start at a pressure of 1.2 atm and a volume of 30 liters. The gas is then compressed adiabatically to \(\frac{1}{3}\) this volume. Assume that the gas may be treated as ideal. What is the change in the internal energy of the gas? Does the internal energy increase or decrease? Does the temperature of the gas increase or decrease during this process? Explain.

CP A Thermodynamic Process in a Liquid. A chemical engineer is studying the properties of liquid methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) . She uses a steel cylinder with a cross-sectional area of 0.0200 \(\mathrm{m}^{2}\) and containing \(1.20 \times 10^{-2} \mathrm{m}^{3}\) of methanol. The cylinder is equipped with a tightly fitting piston that supports a load of \(3.00 \times 10^{4} \mathrm{N}\) . The temperature of the system is increased from \(20.0^{\circ} \mathrm{C}\) to \(50.0^{\circ} \mathrm{C}\) . For methanol, the coefficient of volume expansion is \(1.20 \times 10^{-3} \mathrm{K}^{-1},\) the density is \(79 \mathrm{I} \mathrm{kg} / \mathrm{m}^{3},\) and the specific heat at constant pressure is \(c_{p}=2.51 \times 10^{3} \mathrm{J} / \mathrm{kg} \cdot \mathrm{K}\) .You can ignore the expansion of the steel cylinder. Find (a) the increase in volume of the methanol; (b) the mechanical work done by the methanol against the \(3.00 \times 10^{4}\) N force; (c) the amount of heat added to the methanol; (d) the change in internal energy of the methanol. (e) Based on your results, explain whether there is any substantial difference between the specific heats \(c_{p}\) (at constant pressure) and \(c_{V}\) (at constant volume) for methanol under these conditions.

High-Altitude Research. A large research balloon containing \(2.00 \times 10^{3} \mathrm{m}^{3}\) of helium gas at 1.00 atm and a temperature of \(15.0^{\circ} \mathrm{C}\) rises rapidly from ground level to an altitude at which the atmospheric pressure is only 0.900 atm (Fig. Pl9.58. Assume the helium behaves like an ideal gas and the balloon's ascent is too rapid to permit much heat exchange with the surrounding air. (a) Calculate the volume of the gas at the higher altitude. (b) Calculate the temperature of the gas at the higher altitude. (c) What is the change in internal energy of the helium as the balloon rises to the higher altitude?

Comparing Thermodynamic Processes. In a cylinder, 1.20 mol of an ideal monatomic gas, initially at \(3.60 \times 10^{5}\) Pa and \(300 \mathrm{K},\) expands until its volume triples. Compute the work done by the gas if the expansion is (a) isothermal; (b) adiabatic; (c) isobaric. (d) Show each process in a \(p V\) -diagram. In which case is the absolute value of the work done by the greatest? Least? (e) In which case is the absolute value of the heat transfer greatest? Least? (f) In which case is the absolute value of the change in internal energy of the gas greatest? Least?

In an adiabatic process for an ideal gas, the pressure decreases. In this process does the internal energy of the gas increase or decrease? Explain your reasoning.

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