/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 A flask contains a mixture of ne... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A flask contains a mixture of neon (Ne), krypton (Kr), and radon (Rn) gases. Compare (a) the average kinetic energies of the three types of atoms and (b) the root-mean-square speeds. (Hint: The periodic table in Appendix D shows the molar mass (in g/mol) of each element under the chemical symbol for that element.)

Short Answer

Expert verified
(a) All gases have the same average kinetic energy; (b) Ne > Kr > Rn for root-mean-square speeds.

Step by step solution

01

Understanding Average Kinetic Energy

The average kinetic energy (\( KE_{avg} \)) of gases can be given by the formula \( KE_{avg} = \frac{3}{2} k_B T \), where \( k_B \) is the Boltzmann constant and \( T \) is the absolute temperature. Since all gases in the flask are at the same temperature, \( KE_{avg} \) is the same for neon, krypton, and radon.
02

Calculate Root-Mean-Square Speed

The root-mean-square (rms) speed (\( v_{rms} \)) of a gas is given by \( v_{rms} = \sqrt{\frac{3RT}{M}} \), where \( R \) is the ideal gas constant, \( T \) is the absolute temperature, and \( M \) is the molar mass in kg/mol. The molar masses from the periodic table are: Ne = 20.18 g/mol, Kr = 83.8 g/mol, Rn = 222 g/mol, which we convert to kg/mol (e.g. Ne: 20.18 g/mol = 0.02018 kg/mol).
03

Comparing Root-Mean-Square Speeds

Since \( v_{rms} \) is inversely proportional to the square root of the molar mass, we expect neon to have the highest \( v_{rms} \) (due to its lowest molar mass), followed by krypton, and finally radon which will have the lowest root-mean-square speed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Kinetic Energy
The concept of average kinetic energy is fundamental in understanding the behavior of gases. It provides insight into the energy each particle within a gas possesses due to its motion. The average kinetic energy of a gas is expressed using the formula \( KE_{avg} = \frac{3}{2} k_B T \), where \( k_B \) is the Boltzmann constant and \( T \) represents the absolute temperature in Kelvin.
This formula reveals an important aspect: the average kinetic energy is dependent solely on the temperature of the gas and is independent of the type of gas (or identity of the particle).
  • Because all gases in the flask share the same temperature, the average kinetic energy is identical for neon, krypton, and radon. This highlights the principle that temperature is a measure of the average kinetic energy of particles.
  • No matter what the gas composition, as long as they are maintained at the same temperature, their average kinetic energies will be the same.
Understanding this concept helps solidify the idea that kinetic energy is strictly linked to temperature, not the mass or type of gas involved.
Root-Mean-Square Speed
Root-mean-square speed is a concept that transforms the understanding of kinetic energy into motion by calculating how fast gas particles are moving. The root-mean-square (rms) speed is derived from the formula \( v_{rms} = \sqrt{\frac{3RT}{M}} \), where \( R \) is the ideal gas constant, \( T \) is the absolute temperature, and \( M \) is the molar mass of the gas in kg/mol.
Here is how rms speed is interpreted:
  • Since \( v_{rms} \) is inversely proportional to the square root of the molar mass of the gas, lighter gases will move faster compared to heavier gases at the same temperature.
  • Using the periodic table, one can convert the molar mass from grams per mole to kilograms per mole for accurate calculations (e.g., Ne: 20.18 g/mol = 0.02018 kg/mol).
This means in the given scenario, neon, having the smallest molar mass, would have the highest rms speed, followed by krypton, and radon with the largest molar mass, would have the slowest movement.
Molar Mass
Molar mass is an essential factor in calculating various properties of a gas, such as root-mean-square speed. It is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). For scientific calculations involving kinetic theory, it's often converted to kilograms per mole (kg/mol).
In the context of kinetic theory and particle motion:
  • Molar mass directly affects the root-mean-square speed of gas particles; lighter gases (such as neon which is 20.18 g/mol) move faster than heavier gases (such as krypton at 83.80 g/mol and radon at 222 g/mol) at a given temperature.
  • This inverse relationship between molar mass and speed emphasizes the impact of atomic weight on motion: heavier atoms require more energy to attain the same speed as lighter ones.
Knowing the molar mass allows predictions about the comparative speeds of different gases, which aids in understanding how gas mixtures behave under various conditions. The periodic table is a valuable tool in these calculations, offering the necessary molar mass data for each element.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains 0.110 \(\mathrm{m}^{3}\) of air at a pressure of 0.355 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.390 \(\mathrm{m}^{3} .\) If the temperature remains constant, what is the final value of the pressure?

A balloon whose volume is 750 \(\mathrm{m}^{3}\) is to be filled with hydrogen at atmospheric pressure \(\left(1.01 \times 10^{5} \mathrm{Pa}\right) .\) (a) If the hydrogen is stored in cylinders with volumes of 1.90 \(\mathrm{m}^{3}\) at a gauge pressure of \(1.20 \times 10^{6} \mathrm{Pa},\) how many cylinders are required? Assume that the temperature of the hydrogen remains constant. (b) What is the total weight (in addition to the weight of the gas) that can be supported by the balloon if the gas in the balloon and the surrounding air are both at \(15.0^{\circ} \mathrm{C}\) ? The molar mass of hydrogen \(\left(\mathrm{H}_{2}\right)\) is 2.02 \(\mathrm{g} / \mathrm{mol}\) . The density of air at \(15.0^{\circ} \mathrm{C}\) and atmospheric pressure is 1.23 \(\mathrm{kg} / \mathrm{m}^{3} .\) See Chapter 12 for a discussion of buoyancy. (c) What weight could be supported if the balloon were filled with helium (molar mass 4.00 \(\mathrm{g} / \mathrm{mol}\) ) instead of hydrogen, again at \(15.0^{\circ} \mathrm{C}\) ?

How Close Together Are Gas Molecules? Consider an ideal gas at \(27^{\circ} \mathrm{C}\) and 1.00 atm pressure. To get some idea how close these molecules are to each other, on the average, imagine them to be uniformly spaced, with each molecule at the center of a small cube. (a) What is the length of an edge of each cube if adjacent cubes touch but do not overlap? (b) How does this distance compare with the diameter of a typical molecule? (c) How does their separation compare with the spacing of atoms in solids, which typically are about 0.3 \(\mathrm{nm}\) apart?

The size of an oxygen molecule is about 2.0 \(\times 10^{-10} \mathrm{m}\) Make a rough estimate of the pressure at which the finite volume of the molecules should cause noticeable deviations from ideal-gas behavior at ordinary temperatures \((T=300 \mathrm{K})\) .

A person at rest inhales 0.50 \(\mathrm{L}\) of air with each breath at a pressure of 1.00 atm and a temperature of \(20.0^{\circ} \mathrm{C}\) . The inhaled air is 21.0\(\%\) oxygen. (a) How many oxygen molecules does this person inhale with each breath? (b) Suppose this person is now resting at an elevation of 2000 \(\mathrm{m}\) but the temperature is still \(20.0^{\circ} \mathrm{C}\) . Assuming that the oxygen percentage and volume per inhalation are the same as stated above, how many oxygen molecules does this person now inhale with each breath? (c) Given that the body still requires the same number of oxygen molecules per second as at sea level to maintain its functions, explain why some people report "shortness of breath" at high elevations.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.