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The fundamental frequency of a pipe that is open at both ends is 594 \(\mathrm{Hz}\) (a) How long is this pipe? If one end is now closed, find (b) the wavelength and (c) the frequency of the new fundamental.

Short Answer

Expert verified
(a) 0.288 m; (b) 1.152 m; (c) 297.4 Hz.

Step by step solution

01

Understand the properties of a pipe open at both ends

For a pipe open at both ends, the fundamental frequency corresponds to the first harmonic, where the length of the pipe is equal to half the wavelength, \( L = \frac{\lambda}{2} \). We know the speed of sound \( v \) in air is approximately \( 343 \text{ m/s} \).
02

Calculate the wavelength of the fundamental frequency

Use the formula for wave speed: \( v = f \lambda \), where \( f = 594 \text{ Hz} \) is the fundamental frequency.\[\lambda = \frac{v}{f} = \frac{343 \text{ m/s}}{594 \text{ Hz}} \approx 0.577 \text{ m}.\]
03

Calculate the length of the open pipe

The length of the pipe \( L \) relates to the wavelength by \( \lambda = 2L \) for the fundamental frequency.\[L = \frac{\lambda}{2} = \frac{0.577 \text{ m}}{2} \approx 0.288 \text{ m}.\]
04

Understand the properties of a pipe closed at one end

For a pipe closed at one end, the fundamental frequency corresponds to one-quarter of the wavelength fitting inside the pipe \( L = \frac{\lambda'}{4} \).
05

Calculate the new wavelength for the closed pipe

The length of the closed pipe \( L \) remains the same, so:\[L = \frac{\lambda'}{4} \Rightarrow \lambda' = 4L = 4 \times 0.288 \text{ m} = 1.152 \text{ m}.\]
06

Calculate the new fundamental frequency for the closed pipe

Use the formula for wave speed again: \( v = f' \lambda' \), and solve for \( f' \).\[f' = \frac{v}{\lambda'} = \frac{343 \text{ m/s}}{1.152 \text{ m}} \approx 297.4 \text{ Hz}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

open and closed pipes
In acoustics, pipes are used to study sound waves and musical harmonics. Pipes can be categorized into two types: open pipes and closed pipes. Open pipes are open at both ends, while closed pipes have one end open and the other closed. This difference affects the sound wave behavior inside the pipe.

For open pipes, the fundamental frequency corresponds to the first harmonic. At this frequency, the length of the pipe equals half of the wavelength of the sound wave. This means that both ends of the pipe act as antinodes, with a node in the middle. The formula used here is \( L = \frac{\lambda}{2} \).

On the other hand, closed pipes have different characteristics. The fundamental frequency here gives us a quarter wavelength fitting into the length of the pipe, \( L = \frac{\lambda'}{4} \). One end acts as a node (at the closed end) and the other as an antinode (at the open end). This results in a different pattern of standing waves, impacting the frequency and harmonics produced.
speed of sound
The speed of sound is crucial in determining the frequency and wavelength of sound waves traveling through a medium. In air, under normal conditions, the speed of sound is approximately 343 meters per second (m/s). This varies slightly with factors such as temperature, humidity, and air pressure.

Understanding the speed of sound is important for calculating wave properties. The relationship between speed \( v \), frequency \( f \), and wavelength \( \lambda \) is expressed with the equation \( v = f \lambda \). This simple formula allows us to find the wavelength of sound waves when the frequency is known, and vice versa.

For example, if the fundamental frequency of a pipe is known, and we have the speed of sound, we can easily calculate the wavelength, thereby giving insights into the physical dimensions and properties of the pipe.
harmonics in acoustics
Harmonics play a significant role in acoustics, affecting the sounds musical instruments produce. They are related to the natural frequencies at which an object vibrates. In the context of pipes, harmonics are achieved by creating standing waves within the pipe.

The fundamental frequency is the lowest frequency produced, often called the first harmonic. The second harmonic is the next frequency, with higher multiples of the fundamental frequency termed as overtones. The presence of overtones and their specific frequencies give musical instruments their unique timbre.

For an open pipe, harmonics are integer multiples of the fundamental frequency, meaning the second harmonic would be twice the fundamental frequency, the third harmonic three times, and so on. However, for closed pipes, the harmonics are only odd multiples of the fundamental, as the wave patterns differ due to the closed end.
  • This difference in harmonic series between open and closed pipes contributes to the distinctive sound qualities of woodwinds and brass instruments, which act as resonating air columns.

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Most popular questions from this chapter

A bat flies toward a wall, emitting a steady sound of frequency 1.70 \(\mathrm{kHz}\) . This bat hears its own sound plus the sound reflected by the wall. How fast should the bat fly in order to hear a beat frequency of 10.0 \(\mathrm{Hz}\) ?

Two organ pipes, open at one end but closed at the other, are each 1.14 m long. One is now lengthened by 2.00 \(\mathrm{cm} .\) Find the frequency of the beat they produce when playing together in their fundamental.

A long tube contains air at a pressure of 1.00 atm and a temperature of \(77.0^{\circ} \mathrm{C}\) . The tube is open at one end and closed at the other by a movable piston. A tuning fork near the open end is vibrating with a frequency of 500 \(\mathrm{Hz}\) . Resonance is produced when the piston is at distances \(18.0,55.5,\) and 93.0 \(\mathrm{cm}\) from the open end. (a) From these measurements, what is the speed of sound in air at \(77.0^{\circ} \mathrm{C} ?\) (b) From the result of part (a), what is the value of \(\gamma ?\) (c) These data show that a displacement antinode is slightly outside of the open end of the tube. How far outside is it?

Moving Source vs. Moving Listener. (a) A sound source producing \(1.00-\mathrm{kHz}\) waves moves toward a stationary listener at one-half the speed of sound. What frequency will the listener hear? (b) Suppose instead that the source is stationary and the listener moves toward the source at one- half the speed of sound. What frequency does the listener hear'? How does your answer compare to that in part (a)? Explain on physical grounds why the two answers differ.

Ep A New Musical Instrument. You have designed a new musical instrument of very simple construction. Your design consists of a metal tube with length \(L\) and diameter \(L / 10 .\) You have stretched a string of mass per unit length \(\mu\) across the open end of the tube. The other end of the tube is closed. To produce the musical effect you're looking for, you want the frequency of the third-harmonic standing wave on the string to be the same as the fundamental frequency for sound waves in the air column in the tube. The speed of sound waves in this air column is \(v_{\mathrm{s}}\) . (a) What must be the tension of the string to produce the desired effect? (b) What happens to the sound produced by the instrument if the tension is changed to twice the value calculated in part (a)? (c) For the tension calculated in part (a), what other harmonics of the string, if any, are in resonance with standing waves in the air column?

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