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Two uniform spheres, each with mass \(M\) and radius \(R\) touch each other. What is the magnitude of their gravitational force of attraction?

Short Answer

Expert verified
The gravitational force is \( F = \frac{G M^2}{4R^2} \).

Step by step solution

01

Understand the Gravitational Force Formula

The gravitational force between two point masses is given by the formula: \[ F = \frac{G m_1 m_2}{r^2} \] where \( F \) is the gravitational force, \( G \) is the gravitational constant, \( m_1 \) and \( m_2 \) are the masses of the two objects, and \( r \) is the distance between the centers of the two masses.
02

Identify the Given Values

In this problem, each sphere has a mass \( M \), and because they touch each other, the distance \( r \) between their centers is equal to \( 2R \), which is the sum of their radii.
03

Substitute Values into the Gravitational Force Formula

Substituting the given values into the gravitational force formula, we have:\[ F = \frac{G \cdot M \cdot M}{(2R)^2} \] This becomes: \[ F = \frac{G M^2}{4R^2} \]
04

Calculate the Gravitational Force

The expression \( F = \frac{G M^2}{4R^2} \) gives the gravitational force of attraction between the two spheres.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Spheres
Understanding the concept of uniform spheres is essential when discussing gravitational force. A uniform sphere is an object that has a symmetrical shape with all its mass evenly distributed throughout its volume. This means that the center of mass is located precisely at the geometric center of the sphere. This property simplifies our calculations related to gravitational interactions because we can treat the entire sphere as if all its mass were concentrated at its center.
In the context of gravitational force, assuming uniformity in spheres allows us to use the gravitational force formula effectively. Also, it simplifies our understanding of how gravitational attraction occurs between spherical objects, like planets or smaller spheres, in a void of space.
Uniform spheres are a fundamental assumption in many physics problems because they allow us to replace complex real-world shapes with simple calculations.
Gravitational Constant
The gravitational constant, denoted as \( G \), is a crucial factor in calculating gravitational forces. It is a constant value that applies universally, making it integral for understanding gravitational attraction between masses.
The value of \( G \) is approximately \( 6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \), and it represents the strength of gravity in classical physics. The presence of \( G \) in the gravitational force formula indicates that regardless of the individual properties of the objects (like mass or distance), gravity's effects are predictable and consistent.
When tackling problems involving gravitational force, \( G \) ensures that we can account for the cosmic-scale attraction phenomena between celestial bodies, as well as small-scale interactions. This consistency is a cornerstone of Newtonian physics.
Gravitational Force Formula
The gravitational force formula is the backbone of many calculations related to gravitational attraction. Mathematically, it is expressed as \( F = \frac{G m_1 m_2}{r^2} \), where:\[ F \] is the gravitational force between two masses,
\( G \) is the gravitational constant,
\( m_1 \) and \( m_2 \) are the masses of the interacting bodies,
\( r \) is the distance between the centers of these masses.
The formula indicates that gravitational force increases with greater mass, but decreases as the distance between the two objects increases. This is because the force is inversely proportional to the square of the distance, meaning a larger separation results in a weaker force.
By substituting known values into this formula, we can determine the gravitational force in various contexts, from touching spheres to distant celestial bodies.
Distance Between Centers
The distance between the centers of mass of two objects plays a pivotal role in calculating gravitational force. For uniform spheres touching each other, this distance is simply the sum of their radii, as they span from one center to another directly through their touching surfaces.
This factor of distance, represented as \( r \), in the gravitational force formula \( F = \frac{G m_1 m_2}{r^2} \), shows that even slight increases in separation can significantly decrease the force of attraction. It is because the force is inversely proportional to the square of the distance — doubling the distance would quarter the force.
In the given exercise, because the spheres have a radius \( R \), when they touch, the center-to-center distance is \( 2R \). This straightforward calculation allows easy computation when using the gravitational force formula.

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Most popular questions from this chapter

An \(8.00-\mathrm{kg}\) point mass and a 15.0 -kg point mass are held in place 50.0 \(\mathrm{cm}\) apart. A particle of mass \(m\) is released from a point between the two masses 20.0 \(\mathrm{cm}\) from the \(8.00-\mathrm{kg}\) mass along the line connecting the two fixed masses. Find the magnitude and direction of the acceleration of the particle.

Binary Star-Different Masses. Two stars, with masses \(M_{1}\) and \(M_{2},\) are in circular orbits around their center of mass. The star with mass \(M_{1}\) has an orbit of radius \(R_{1} ;\) the star with mass \(M_{2}\) has an orbit of radius \(R_{2} .\) (a) Show that the ratio of the orbital radii of the two stars equals the reciprocal of the ratio of their masses - that is, \(R_{1} / R_{2}=M_{2} / M_{1}\) . (b) Explain why the two stars have the same orbital period, and show that the period \(T\) is given by \(T=2 \pi\left(R_{1}+R_{2}\right)^{3 / 2} / \sqrt{G\left(M_{1}+M_{2}\right)}\) . (c) The two stars in a certain binary star system move in circular orbits. The first star, Alpha, has an orbital speed of 36.0 \(\mathrm{km} / \mathrm{s}\) . The second star, Beta, has an orbital speed of 12.0 \(\mathrm{km} / \mathrm{s}\) . The orbital period is 137 \(\mathrm{d}\) . What are the masses of each of the two stars? (d) One of the best candidates for a black hole is found in the binary system called A \(0620-0090 .\) The two objects in the binary system are an orange star, V616 Monocerotis, and a compact object believed to be a black hole (see Fig. 13.27\() .\) The orbital period of \(\mathrm{A} 0620-0090\) is 7.75 hours, the mass of V616 Monocerotis is estimated to be 0.67 times the mass of the sun, and the mass of the black hole is estimated to be 3.8 times the mass of the sun. Assuming that the orbits are circular, find the radius of each object's orbit and the orbital speed of each object. Compare these answers to the orbital radius and orbital speed of the earth in its orbit around the sun.

There are two equations from which a change in the gravitational potential energy \(U\) of the system of a mass \(m\) and the earth can be calculated. One is \(U=m g y(\) Eq. 7.2\() .\) The other is \(U=-G m_{\mathrm{E}} m / r(\mathrm{Eq} .13 .9) .\) As shown in Section \(13.3,\) the first equation is correct only if the gravitational force is a constant over the change in height \(\Delta y .\) The second is always correct. Actually, the gravitational force is never exactly constant over any change in height, but if the variation is small, we can ignore it. Consider the difference in \(U\) between a mass at the earth's surface and a distance \(h\) above it using both equations, and find the value of \(h\) for which Eq. \((7.2)\) is in error by 1\(\% .\) Express this value of \(h\) as a fraction of the earth's radius, and also obtain a numerical value for it.

Submarines on Europa. Some scientists are eager to send a remote-controlled submarine to Jupiter's moon Europa to search for life in its oceans below an icy crust. Europa's mass has been measured to be \(4.8 \times 10^{22}\) kg, its diameter is \(3138 \mathrm{km},\) and it has no appreciable atmosphere. Assume that the layer of ice at the surface is not thick enough to exert substantial force on the water. If the windows of the submarine you are designing are 25.0 \(\mathrm{cm}\) square and can stand a maximum inward force of 9750 N per window, what is the greatest depth to which this submarine can safely dive?

Calculate the earth's gravity force on a 75 -kg astronaut who is repairing the Hubble Space Telescope 600 \(\mathrm{km}\) above the earth's surface, and then compare this value with his weight at the earth's surface. In view of your result, explain why we say astronauts are weightless when they orbit the earth in a satellite such as a space shuttle. Is it because the gravitational pull of the earth is negligibly small?

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