/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 The weight of a king's solid cro... [FREE SOLUTION] | 91Ó°ÊÓ

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The weight of a king's solid crown is w. When the crown is suspended by a light rope and completely immersed in water, the tension in the rope (the crown's apparent weight) is (a) Prove that the crown's relative density (specific gravity) is 1\(/(1-f)\) . Discuss the meaning of the limits as \(f\) approaches 0 and \(1 .\) (b) If the crown is solid gold and weighs 12.9 \(\mathrm{N}\) in air, what is its apparent weight when completely immersed in water? (c) Repeat part (b) if the crown is solid lead with a very thin gold plating, but still has a weight in air of 12.9 \(\mathrm{N}\) .

Short Answer

Expert verified
The apparent weight of the gold crown in water is approximately 12.27 N, and the lead crown is about 11.79 N.

Step by step solution

01

Understanding the Problem

We are given that a crown weighs 'w' in air and when immersed in water, it has an apparent weight. We need to prove the formula for relative density and discuss limits. Additionally, we calculate the apparent weights for given materials.
02

Apply Archimedes’ Principle

According to Archimedes' principle, the buoyant force acting on a submerged object is equal to the weight of the fluid displaced by it. When the crown is immersed, the apparent weight is equal to the actual weight minus the buoyant force. Let the crown's actual weight be 'w' and its apparent weight be 'w_a'. Then, we can write:\[ w_a = w - F_b \]where \( F_b \) is the buoyant force.
03

Relate Buoyant Force to Fluid Density

The buoyant force, \( F_b \), can be expressed in terms of the density of the fluid \( \rho_f \), the volume of the crown \( V \), and gravity \( g \):\[ F_b = \rho_f V g \]Rewriting the apparent weight equation gives:\[ w_a = w - \rho_f V g \]
04

Define Relative Density

The relative density (specific gravity) of the crown, \( \rho_c \), is the ratio of its density to that of the fluid. Rearranging the equation for \( w_a \) and using \( w = \rho_c V g \), we solve:\( w_a = \rho_c V g - \rho_f V g = V g (\rho_c - \rho_f) \)Thus,\[ \frac{w_a}{w} = \frac{\rho_c - \rho_f}{\rho_c} \]
05

Solve for Relative Density

To find \( \rho_c \):\[ \frac{w - w_a}{w} = 1 - \frac{w_a}{w} = \frac{\rho_f}{\rho_c} \]Thus, \[ \rho_c = \frac{\rho_f}{1 - \frac{w_a}{w}} \].Assuming water has \( f \) as the fraction of the crown's weight supported by buoyancy, relative density becomes:\[ \rho_c = \frac{1}{1-f} \]
06

Discussing Limits

When \( f \to 0 \), the crown displaces no water, implying very high density, theoretically infinite. When \( f \to 1 \), the crown is neutrally buoyant, having the same density as water with \( \rho_c = 1 \).
07

Given Crown Weights in Real Substances

We know the crown is entirely made of gold and weighs 12.9 N in air, and that gold's density is approximately 19,300 kg/m³. For gold in water:\[ w_a = 12.9 - \left( \frac{12.9}{19.3} \right) \times g\]Calculating:\[ w_a \approx 12.9 \times \left(1 - \frac{1}{19.3}\right) \approx 12.27 \, \mathrm{N} \]
08

Recalculate for Lead Crown

For the lead crown with gold plating (same total weight in air, 12.9 N, density of lead is \( 11340 \, \mathrm{kg/m^3} \)), compute the apparent weight:\[ w_a = 12.9 \times \left(1 - \frac{1}{11.34}\right) \] This gives:\[ w_a \approx 11.79 \, \mathrm{N} \]
09

Conclusion

For a gold crown, apparent weight is approximately 12.27 N. For a lead crown with gold plating, it's about 11.79 N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyant Force
When an object is submerged in a fluid, it experiences an upward force known as the buoyant force. This force is a result of the pressure exerted by the fluid, acting more on the bottom surface than on the top surface of the object. The difference in pressure results in the net upward buoyant force.

According to Archimedes' Principle, the buoyant force (\( F_b \)) is equal to the weight of the fluid displaced by the object. This can be calculated using the formula:\[ F_b = \rho_f V g \]where:
  • \( \rho_f \) is the fluid's density,
  • \( V \) is the volume of the displaced fluid (equal to the object's submerged volume),
  • \( g \) is the acceleration due to gravity.

This principle helps us understand why objects feel lighter when they are submerged in liquid. The weight that appears to have been "lost" in the liquid is exactly the weight of the liquid displaced by the object. This apparent weight can be expressed mathematically as:\[ w_a = w - F_b \]where:
  • \( w \) is the actual weight of the object.
  • \( w_a \) is the apparent weight while submerged in the fluid.
Specific Gravity
Specific gravity, often referred to as relative density, is the ratio of the density of a substance to the density of a reference substance, typically water when discussing liquids and solids. It's a dimensionless quantity, providing a simple way to describe the density of an object in relation to water.

The specific gravity (\( SG \)) can be calculated using:\[ SG = \frac{\rho}{\rho_{water}} \]where:
  • \( \rho \) is the density of the object.
  • \( \rho_{water} \) is the density of water, typically \( 1000 \, \mathrm{kg/m^3} \)under standard conditions.

In the context of the crown problem, understanding specific gravity helps us connect the apparent loss of weight when submerged to the displacement of water. The exercise presents the formula:\[ \rho_c = \frac{1}{1-f} \]where \( f \) is the fraction of the object's weight supported by buoyancy. If \( f = 0 \), the crown feels as though it doesn’t lose any weight in water, suggesting a much higher density than water. Conversely, when \( f = 1 \), the object is fully supported by buoyancy and behaves neutrally like water itself, exhibiting a specific gravity of 1.
Relative Density
Relative density is another term for specific gravity but highlights its usage in comparing the density of one material to another. It's especially useful in practical contexts where knowing the absolute density is less important than understanding how one material behaves compared to another, like water.

To directly relate relative density (\( \rho_{relative} \)) to the buoyant forces discussed earlier, use:\[ \rho_{relative} = \frac{\rho}{\rho_{fluid}} \]Thus, when the submerged object's density is known, it becomes straightforward to determine the relative density. Using the derived formula:\[ \rho_c = \frac{1}{1-f} \]helps to simplify the calculation of density in experimental setups, as it directly relates to how much of the object's weight in water is supported by buoyancy.

Understanding the implications of relative density:
  • When relative density is greater than 1, objects sink because they are denser than the reference fluid.
  • When it equals 1, objects are neutrally buoyant, neither rising nor sinking.
  • When less than 1, objects float because they are less dense than the fluid.
This concept is crucial across various scientific disciplines, including material science and hydrodynamics, as it provides insights into material properties and behavior in different media.

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