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You need to extend a 2.50-inch-diameter pipe, but you have only a 1.00-inch- diameter pipe on hand. You make a fitting to connect these pipes end to end. If the water is flowing at 6.00 cm s in the wide pipe, how fast will it be flowing through the narrow one?

Short Answer

Expert verified
The water flows at approximately 37.5 cm/s in the narrow pipe.

Step by step solution

01

Understand the Problem

We need to determine the velocity of water when it flows from a larger pipe (2.50-inch diameter) to a narrower pipe (1.00-inch diameter). The initial velocity in the larger pipe is given as 6.00 cm/s.
02

Convert Units

Convert the given diameters from inches to centimeters to be consistent with the velocity units. 1) The diameter of the wide pipe is 2.50 inches. - Since 1 inch equals 2.54 cm, the diameter in centimeters is: \( 2.50 \times 2.54 = 6.35 \text{ cm} \)2) The diameter of the narrow pipe is 1.00 inch:- The diameter in centimeters is: \( 1.00 \times 2.54 = 2.54 \text{ cm} \)
03

Calculate Cross-Sectional Areas

Find the cross-sectional areas of both pipes using the formula for the area of a circle, \( A = \pi r^2 \).1) For the wide pipe, the radius is half of 6.35 cm, so:\[ A_1 = \pi \left(\frac{6.35}{2}\right)^2 \approx 31.67 \text{ cm}^2 \]2) For the narrow pipe, the radius is half of 2.54 cm, so:\[ A_2 = \pi \left(\frac{2.54}{2}\right)^2 \approx 5.07 \text{ cm}^2 \]
04

Apply the Continuity Equation

Use the continuity equation which states that the product of the cross-sectional area and velocity remains constant for an incompressible fluid. \[ A_1 \times v_1 = A_2 \times v_2 \]Given that \( v_1 = 6.00 \text{ cm/s} \), we solve for \( v_2 \).
05

Solve for Velocity in Narrow Pipe

Substitute the known values into the continuity equation:\[ 31.67 \times 6.00 = 5.07 \times v_2 \]Rearrange and solve for \( v_2 \):\[ v_2 = \frac{31.67 \times 6.00}{5.07} \approx 37.5 \text{ cm/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuity in Fluid Dynamics: The Continuity Equation
The continuity equation is a fundamental concept in fluid dynamics, ensuring that fluid mass is conserved as it flows through a system. When dealing with incompressible fluids, like water, the equation relates the flow rate of the fluid in different sections of a pipe or channel. The principle behind the continuity equation is simple: whatever enters one section, must exit another, unless added or removed. This is mathematically expressed as:\[A_1 \times v_1 = A_2 \times v_2\]Where:- \(A_1\) and \(A_2\) are the cross-sectional areas of the wide and narrow pipes, respectively.- \(v_1\) and \(v_2\) are the fluid velocities in the wide and narrow pipes, respectively.This equation allows us to determine unknowns such as velocity changes when fluid transitions between different areas. If the cross-sectional area decreases, the fluid velocity increases to maintain flow rate continuity, assuming no leaks.
Calculating Cross-Sectional Area in Pipes
Calculating the cross-sectional area of a pipe is essential for understanding flow within it. To determine the area, we use the formula for the area of a circle, as the pipes in this exercise are cylindrical.The formula is:\[A = \pi r^2\]Where:- \(A\) is the area.- \(\pi\) is a constant approximately equal to 3.14159.- \(r\) is the radius of the pipe.The process involves first converting the diameter of the pipe into the radius by dividing it by two. With the radius, we apply the formula to find the area. For example, given a wide pipe with a diameter of 6.35 cm, the radius would be 3.175 cm. Plugging this into our formula, the cross-sectional area becomes approximately 31.67 cm². By calculating the areas of both wide and narrow pipes, we can utilize the continuity equation to solve for unknowns like fluid velocity.
Unit Conversion in Physics: Inches to Centimeters
In physics, when working with problems involving different types of measurement units, it's critical to perform unit conversions to ensure calculations are accurate and meaningful. A common conversion in fluid dynamics involves changing measurements from inches to centimeters.Why is this important? Because calculations typically require inputs in consistent units, especially in fluid equations, which often use metric units like centimeters and meters.To convert inches to centimeters, use the conversion factor:- 1 inch = 2.54 centimetersMultiplying the measurement in inches by 2.54 gives the dimension in centimeters. For instance, a 2.50-inch diameter pipe converted to centimeters is calculated as:\[2.50 \times 2.54 = 6.35 \text{ cm}\]Such conversions allow for smooth integration into formulae and ensure the results align with standard scientific practice.

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Most popular questions from this chapter

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