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Mountain Climbing. Mountaineers often use a rope to lower them- selves down the face of a cliff (this is called rappelling). They do this with their body nearly horizontal and their feet pushing against the cliff (Fig. Pl1.45). Suppose that an 82.0 -kg climber, who is 1.90 m tall and has a center of gravity 1.1 \(\mathrm{m}\) from his feet, rappels down a vertical cliff with his body raised \(35.0^{\circ}\) above the horizontal. He holds the rope 1.40 \(\mathrm{m}\) from his feet, and it makes a \(25.0^{\circ}\) angle with the cliff face. (a) What tension does his rope need to support? (b) Find the horizontal and vertical components of the force that the cliff face exerts on the climber's feet. (c) What minimum coefficient of static friction is needed to prevent the climber's feet from slipping on the cliff face if he has one foot at a time against the cliff?

Short Answer

Expert verified
Tension: solve torque balance; forces: resolve into components; friction: balance horizontal force.

Step by step solution

01

Identify Forces and Angles

Consider the forces acting on the climber: the weight downward, the tension in the rope, and the force exerted by the cliff on his feet. List known values: climber's mass \( m = 82.0 \ kg \), gravitational acceleration \( g = 9.8 \, m/s^2 \), body angle \( \theta = 35.0^{\circ} \), rope angle \( \phi = 25.0^{\circ} \), and distances from feet to rope and center of gravity.
02

Calculate Force Components

Resolve the tension \( T \) and the climber's weight \( W = mg \) into components. The tension's horizontal component is \( T \cos \phi \) and vertical is \( T \sin \phi \). The weight has only a vertical component \( mg \).
03

Apply Torque Balance Equation

Use the principle of balance of torques about the feet. Set the torque due to the climber's weight and the torque due to tension equal: \( T \cos \phi \times 1.40 = mg \times 0.70 \). Solve for \( T \).
04

Solve for Tension in the Rope (a)

From the equation \( T \cos 25^{\circ} \times 1.40 = 82.0 \times 9.8 \times 0.70 \), solve for \( T \). This gives the tension that needs to be supported by the rope.
05

Calculate Force Exerted by the Cliff (b)

Resolve the force exerted by the cliff into horizontal \( F_{h} \) and vertical \( F_{v} \) components. Apply the equilibrium conditions: horizontal \(F_{h} = T \sin \phi \) and vertical \( F_{v} = mg - T \cos \phi \).
06

Find Minimum Coefficient of Static Friction (c)

The force of friction \( f \) must be equal to or greater than the horizontal component of the force \( F_{h} = T \sin \phi \). Use \( \mu_s \times F_{v} = F_{h} \). Solve for the minimum coefficient of static friction \( \mu_s \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torque Balance
When a climber is rappelling, they must keep their body stable. To achieve this, the forces acting around a pivot point need to be balanced. This concept is known as torque balance. Torque is a force that causes rotation. For the climber, think of their feet as the pivot point. In this scenario, we calculate torque using the formula:\[ \tau = r \cdot F \cdot \sin(\theta) \]where \(\tau\) is torque, \(r\) is the distance from the pivot, \(F\) is the force, and \(\theta\) is the angle of force application. To maintain balance, the torque from the climber's weight and the rope tension must cancel out. The weight creates a counterclockwise torque and the tension a clockwise torque. Calculating these torques involves solving the equation for their balancing values, ensuring that neither side has a rotational advantage. By organizing these torques, climbers remain stabilized horizontally during their descent.
Force Components
Breaking down forces into components is crucial for understanding how they interact. In physics, any force can be splitted into horizontal and vertical components using trigonometry. For a force \(F\) applied at an angle \(\theta\), the components are given by:
  • Horizontal: \( F_{h} = F \cos \theta \)
  • Vertical: \( F_{v} = F \sin \theta \)
This breakdown helps in calculating net forces acting in different directions. Considering our rappelling climber, we need to resolve the tension in the rope and the gravitational force acting on the climber. The rope applies both a vertical and horizontal force on the climber. Understanding these components ensures that all acting forces are properly analyzed and balanced, essential for a controlled rappel.
Static Friction
Static friction keeps objects at rest. When a climber's foot is planted against a cliff, static friction prevents it from slipping. It depends on the interaction between surfaces and is defined by: \[ f_{s} \leq \mu_s \cdot N \]where \(f_{s}\) is the force of static friction, \(\mu_s\) is the coefficient of static friction, and \(N\) is the normal force, or the perpendicular force exerted by a surface. For the climber, it's vital that static friction exceeds the horizontal force from the rope and body. Solving for \(\mu_s\) ensures knowing the minimum grip necessary. If the coefficient is not high enough, the feet could slip, risking an uncontrolled descent. With the right calculations, climbers can confidently adjust their gear to maintain safe traction against the cliff.
Rappelling Physics
Rappelling involves descending a vertical surface using a rope, relying on physics to do so safely. By positioning the body almost horizontally and using the feet to push against the cliff, several forces act upon the climber:
  • Gravitational force pulls the climber down.
  • The tension in the rope counteracts part of this pull.
  • The cliff applies a force upwards through the feet.
Key aspects of rappelling physics involve calculating how these forces interact. Correctly managing angles, forces, and tension allows the climber to maintain equilibrium. Analyzing these elements using forces components, static friction, and torque balance ensures a controlled and secure descent, highlighting the necessity of understanding fundamental physics for safety in mountaineering.

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Most popular questions from this chapter

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