/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Centrifuge. An advertisement cla... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Centrifuge. An advertisement claims that a centrifuge takes up only 0.127 \(\mathrm{m}\) of bench space but can produce a radial acceleration of 3000 \(\mathrm{g}\) at 5000 rev/min. Calculate the required radius of the centrifuge. Is the claim realistic?

Short Answer

Expert verified
The required radius is 0.107 meters, and the claim is realistic.

Step by step solution

01

Understand the Problem

We need to determine the radius of a centrifuge based on the given parameters: radial acceleration of 3000 g, speed of 5000 revolutions per minute (rev/min), and bench space of 0.127 meters.
02

Convert RPM to Rad/s

First, convert the rotational speed from revolutions per minute to radians per second. The conversion factor is \(2\pi/60\). \[ \omega = 5000 \times \frac{2\pi}{60} \approx 523.6 \, \text{rad/s} \]
03

Convert Acceleration to m/s²

Convert 3000 g to meters per second squared, where 1 g is equal to 9.81 m/s².\[ a = 3000 \times 9.81 \approx 29430 \, \text{m/s}^2 \]
04

Use the Radial Acceleration Formula

The formula for radial (centripetal) acceleration is \(a = \omega^2 r\). Rearrange this to solve for the radius \(r\): \[ r = \frac{a}{\omega^2} \]Substitute the values:\[ r = \frac{29430}{523.6^2} \approx 0.107 \, \text{m} \]
05

Assess the Realism of the Claim

The calculated radius is approximately 0.107 meters. The centrifuge claims to use only 0.127 meters of bench space, which is larger than the calculated radius. Therefore, the claim seems realistic because the radius fits within the bench space.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centrifuge Mechanics
A centrifuge is a device that uses the principles of centrifugal force to separate components of different densities in a mixture. The main parts of a centrifuge include a rotor, which holds the samples, and a motor that rotates the rotor at high speeds. The process is fundamental in fields like biology and chemistry, where it enables the separation of cellular components or the clarification of liquids.

The effectiveness of a centrifuge is determined by its ability to produce high-speed rotational motion. This creates a force that pushes heavier particles outward, aiding their separation from lighter components. During this action, it is crucial to balance the samples evenly across the rotor to avoid unwanted vibrations and potential sample loss or damage. The force exerted by the centrifuge is often expressed as a multiple of gravitational acceleration (g), indicating how much stronger the centrifugal force is compared to gravity.

Key factors to consider in centrifuge mechanics include:
  • Rotational speed: Measured in revolutions per minute (rpm), this determines how fast the rotor spins and impacts the centrifugal force generated.
  • Radius of rotation: The distance from the center of rotation to the sample, which directly influences the radial acceleration.
  • Motor power: Ensures the centrifuge can reach and maintain high speeds needed for effective separation.
Rotational Motion
When we talk about rotational motion in the context of centrifuges, we refer to the circular motion that the centrifuge's rotor undergoes as it spins. This type of motion is fundamental to understanding how a centrifuge operates and how it generates radial acceleration.

Rotational motion involves several important quantities:
  • Angular velocity (\(\omega\)): This is how fast something spins about a central point, measured in radians per second (rad/s). In our problem, the centrifuge spins at 5000 revolutions per minute, which we converted into radians per second.
  • Angular displacement: The angle through which a point or line has been rotated in a specified sense about a specified axis.
  • Moment of inertia: The resistance of a physical object to any change in its state of rotation; a crucial factor in determining how quickly a centrifuge can accelerate to operating speed.
An understanding of these aspects of rotational motion helps in calculating the radial acceleration and ensuring that the centrifuge can perform as required in practical applications.
Radial Acceleration
Radial acceleration, also known as centripetal acceleration, is a key concept in the operation of a centrifuge. This type of acceleration is directed towards the center of the circular path and is responsible for the centripetal force that keeps an object moving in a circular motion.

The formula for radial acceleration is given by \[ a = \omega^2 r \]where \( \omega \) is the angular velocity and \( r \) is the radius of the rotation.

In our exercise, radial acceleration was given as 3000 times gravitational acceleration (g), which highlights the intense force exerted by the centrifuge. By translating this into meters per second squared, we calculated the necessary rotational force that the centrifuge needs to exert to achieve this high level of separation efficiency. This conversion from g to meters per second squared is essential for understanding and designing centrifuge applications in engineering and scientific contexts.

By examining radial acceleration, engineers ensure that centrifuge designs can withstand the forces involved and that materials within the centrifuge are subjected to the right amount of force for effective separation of components. Thorough knowledge of radial acceleration is crucial for safely operating these powerful devices.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A compound disk of outside diameter 140.0 \(\mathrm{cm}\) is made up of a uniform solid disk of radius 50.0 \(\mathrm{cm}\) and area density 3.00 \(\mathrm{g} / \mathrm{cm}^{2}\) surrounded by a concentric ring of inner radius 50.0 \(\mathrm{cm}\) , outer radius \(70.0 \mathrm{cm},\) and area density 2.00 \(\mathrm{g} / \mathrm{cm}^{2} .\) Find the moment of inertia of this object about an axis perpendicular to the plane of the object and passing through its center.

Engineers are designing a system by which a falling mass \(m\) imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire wrapped around the rim of the drum (Fig. 9.34\()\) . There is no appreciable friction in the axle of the drum, and everything starts from rest. This system is being tested on earth, but it is to be used on Mars, where the acceleration due to gravity is 3.71 \(\mathrm{m} / \mathrm{s}^{2} .\) In the earth tests, when \(m\) is set to 15.0 \(\mathrm{kg}\) and allowed to fall through \(5.00 \mathrm{m},\) it gives 250.0 \(\mathrm{J}\) of kinetic energy to the drum. (a) If the system is operated on Mars, through what distance would the \(15.0-0\) mass have to fall to give the same amount of kinetic energy to the drum? (b) How fast would the 15.0 \(\mathrm{kg}\) mass be moving on Mars just as the drum gained 250.0 \(\mathrm{J}\) of kinetic energy?

A circular saw blade 0.200 \(\mathrm{m}\) in diameter starts from rest. In 6.00 \(\mathrm{s}\) it accelerates with constant angular acceleration to an angular velocity of 140 \(\mathrm{rad} / \mathrm{s}\) . Find the angular acceleration and the angle through which the blade has turned.

About what axis will a uniform, balsa-wood sphere have the same moment of inertia as does a thin-walled, hollow, lead sphere of the same mass and radius, with the axis along a diameter?

The angle \(\theta\) through which a disk drive turns is given by \(\theta(t)=a+b t-c t^{3},\) where \(a, b,\) and \(c\) are constants \(t\) is in seconds, and \(\theta\) is in radians. When \(t=0, \theta=\pi / 4\) rad and the angular velocity is \(2.00 \mathrm{rad} / \mathrm{s},\) and when \(t=1.50 \mathrm{s},\) the angular acceleration is 1.25 \(\mathrm{rad} / \mathrm{s}^{2}\) , (a) Find \(a, b,\) and \(c,\) including their units. b) What is the angular acceleration when \(\theta=\pi / 4\) rad? (c) What are \(\theta\) and the angular velocity when the angular acceleration is 3.50 \(\mathrm{rad} / \mathrm{s}^{2} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.