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Force of a Baseball Swing. A baseball has mass 0.145 \(\mathrm{kg}\) , (a) If the velocity of a pitched ball has a magnitude of 45.0 \(\mathrm{m} / \mathrm{s}\) and the batted ball's velocity is 55.0 \(\mathrm{m} / \mathrm{s}\) in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. (b) If the ball remains in contact with the bat for 2.00 \(\mathrm{ms}\) , find the magnitude of the average force applied by the bat.

Short Answer

Expert verified
(a) Change in momentum and impulse are 14.5 N·s; (b) Average force is 7,250 N.

Step by step solution

01

Identify Known Variables

We know the mass of the baseball, \(m = 0.145 \, \text{kg}\). The initial velocity of the pitched ball, \(v_i = 45.0 \, \text{m/s}\), and the final velocity of the batted ball, \(v_f = -55.0 \, \text{m/s}\), since it moves in the opposite direction.
02

Calculate Change in Momentum

Momentum \((p)\) is given by \(p = mv\). The change in momentum \((\Delta p)\) is the final momentum minus the initial momentum: \[ \Delta p = m \cdot v_f - m \cdot v_i = 0.145 \times (-55.0) - 0.145 \times 45.0 \]. Calculate \(\Delta p\) to find the magnitude.
03

Calculate Impulse

Impulse \((J)\) is equal to the change in momentum, thus \(J = \Delta p\). From Step 2, we substitute \(\Delta p\) to find \(J\).
04

Calculate Average Force

The impulse can also be expressed as \(J = F_{avg} \times \Delta t\), where \(F_{avg}\) is the average force and \(\Delta t = 2.00 \, \text{ms} = 2.00 \times 10^{-3} \, \text{s}\). Rearrange this to solve for \(F_{avg}\): \[ F_{avg} = \frac{J}{\Delta t} \]. Substitute \(J\) from Step 3 to find \(F_{avg}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impulse
Impulse is a crucial concept in physics that explains how the force applied over time results in a change in momentum of an object. In simpler terms, it's what allows an object, like a baseball, to change its direction and speed when hit by a bat. When we talk about impulse, we are essentially discussing the integral of force (how much and for how long it is applied). Mathematically, impulse \( J \) is given by the equation:\[ J = ext{Force} imes ext{Time} \]In the context of the baseball scenario, the bat applies a force to the ball over a brief time span of 2.00 milliseconds. This force changes the ball's momentum, moving it in the opposite direction. Due to its relation with momentum, impulse can also be expressed as the change in momentum:\[ J = \Delta p \]Here, the impulse delivered is directly tied to how much the ball's velocity changes. Understanding impulse helps in predicting how the ball will behave after being struck, in both speed and direction.
Average Force
The concept of average force is key for understanding how forces applied over a time period affect an object. In this baseball example, we need to determine the average force that the bat delivers to the ball during contact.Average force \( F_{avg} \) can be calculated using the formula derived from the impulse equation:\[ F_{avg} = \frac{J}{\Delta t} \]Where:
  • \( J \) is the impulse (or change in momentum),
  • \( \Delta t \) is the time duration of contact, which is \( 2.00 \times 10^{-3} \) seconds in this case.
By knowing the parameters, you can substitute the values to find \( F_{avg} \). This value will give you insight into how strongly the bat impacted the ball during their interaction.
Velocity Change
Velocity change is a pivotal aspect in calculating momentum and impulse. In our baseball scenario, velocity change helps determine how much the ball's speed and direction alter after contact with the bat.Initially, the ball is pitched towards the batter at \( 45.0 \, \text{m/s} \). After striking the bat, its direction reverses and accelerates to \( -55.0 \, \text{m/s} \). Notice that the reversal of direction is significant in calculation because a change in velocity is considered with sign.To calculate the change in velocity, \( \Delta v \), you subtract the initial velocity \( v_i \) from the final velocity \( v_f \):\[ \Delta v = v_f - v_i = -55.0 \, \text{m/s} - 45.0 \, \text{m/s} \]This calculation gives a vital number that illustrates the full extent of speed and directional transformation that occurs, which then feeds into our understanding of momentum changes and, consequently, impulse.

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Most popular questions from this chapter

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