/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 A small rocket burns 0.0500 \(\m... [FREE SOLUTION] | 91Ó°ÊÓ

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A small rocket burns 0.0500 \(\mathrm{kg}\) of fuel per second, ejecting it as a gas with a velocity relative to the rocket of magnitude 1600 \(\mathrm{m} / \mathrm{s}\) . (a) What is the thrust of the rocket? (b) Would the rocket operate in outer space where there is no atmosphere? If so, how would you steer it? Could you brake it?

Short Answer

Expert verified
(a) The thrust is 80 Newtons. (b) Yes, it operates in space; steer by thrust vectoring, brake with retro rockets.

Step by step solution

01

Understand the Concept of Thrust

Thrust is the force exerted by the ejection of gas at high speed from the rocket. It can be calculated using the equation: \( F = \dot{m} \cdot v_e \), where \( F \) is the thrust, \( \dot{m} \) is the rate of mass flow (mass of fuel burnt per second), and \( v_e \) is the ejection velocity of the gas.
02

Substitute Values into Thrust Equation

Given in the problem: \( \dot{m} = 0.0500 \, \text{kg/s} \) and \( v_e = 1600 \, \text{m/s} \). Substitute these values into the thrust equation: \( F = 0.0500 \, \text{kg/s} \times 1600 \, \text{m/s} \).
03

Calculate the Thrust

Multiply the mass flow rate by the ejection velocity: \( F = 0.0500 \, \text{kg/s} \times 1600 \, \text{m/s} = 80 \, \text{N} \). The thrust of the rocket is 80 Newtons.
04

Consider Operation in Outer Space

Rockets do not rely on atmospheric air, as they carry both fuel and the oxidizer. Thus, it operates effectively in outer space. Rockets use the principle of conservation of momentum to operate, which does not depend on air, so it will operate in space.
05

Understand Rocket Steering and Braking

Steering can be achieved using controlled thrust vectoring or by using gimbaled nozzles, gyroscopes, or reaction wheels to change direction. Braking can be accomplished by reversing the thrust or using other systems like retro-rockets to decelerate the rocket.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rocket Propulsion
Rocket propulsion is a fascinating way to generate motion, specifically through the expulsion of gas at high speed. This process starts when a rocket burns fuel, creating gases that are ejected backwards at an incredible speed. Consequently, this ejection generates a forward thrust, pushing the rocket into motion.

The key formula to calculate thrust is given by: \[ F = \dot{m} \cdot v_e \]where:
  • \( F \) is the thrust in Newtons.
  • \( \dot{m} \) is the mass flow rate or the mass of fuel burned per second (in kg/s).
  • \( v_e \) is the ejection velocity of the gases (in m/s).
This relationship outlines the direct proportionality between how fast the mass is ejected and the resulting thrust, conveying a simple yet powerful principle of rocket propulsion. By understanding this formula, you get a glimpse into the power behind the rocket engines.
Conservation of Momentum
One pivotal concept in understanding how rockets operate is the principle of conservation of momentum. We commonly refer to momentum as the "quantity of motion" possessed by an object, and it is conserved in isolated systems.

When a rocket launches, it leverages this principle effectively. As gases are expelled from the rocket in one direction, the rocket gains an equal and opposite momentum, propelling it forward. This is because in a closed system without any external forces, the total momentum remains constant. Consequently, by ejecting mass at high speeds, a rocket can achieve great acceleration and change its velocity in space.

This conservation is crucial since it allows rockets to function in the vacuum of space with no air resistance or gravitational forces acting like on Earth.
Outer Space Rocket Operation
Operating rockets in outer space is an intriguing task, given the absence of atmospheres like those on Earth. However, rockets are brilliant machines that don’t require air to function. They carry all necessary resources, including fuel and oxidizers, to collapse chemical energy into thrust.

By using the stored components, rockets can ignite fuel to push themselves forward, even in the vacuum of space. The absence of external forces like air resistance allows them to travel efficiently and effectively across vast distances. Notably, since rockets don’t require external mediums, they rely purely on the thrust produced from the chemical reactions within to propel through the void of space.
Steering and Braking of Rockets
Guiding and controlling a rocket’s course is an engineering feat. Steering is critical, achieved primarily by modifying the direction of the thrust. This can be done through a technique called thrust vectoring, where the direction of the exhaust gases is controlled, altering the rocket's path.

Technologies such as gimbaled nozzles enable this by physically moving the nozzle to change the exhaust direction. Other sophisticated systems like gyroscopes and reaction wheels also assist in stabilizing and steering the spacecraft.

Braking or decelerating a rocket in space is equally crucial. Rockets use retro-rockets, a different kind of propulsion system, to slow down or stop. By firing these in the direction of travel, it counters the forward motion, effectively reducing the rocket's velocity. Alternatively, reversing the main thrusters can achieve similar results, but requires careful management to ensure control.

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Most popular questions from this chapter

Suppose the first stage of a two stage rocket has total mass \(12,000 \mathrm{kg}\) , of which 9000 \(\mathrm{kg}\) is fuel. The total mass of the second stage is \(1000 \mathrm{kg},\) of which 700 \(\mathrm{kg}\) is fuel. Assume that the relative speed \(\boldsymbol{U}_{\mathbf{e x}}\) of ejected material is constant, and ignore any effect of gravity. (The effect of gravity is small during the firing period if the rate of fuel consumption is large) (a) Suppose the entire fuel supply carried by the two-stage rocket is utilized in a single-stage rocket with the same total mass of \(13,000 \mathrm{kg}\) . In terms of \(v_{e x}\) what is the speed of the rocket, starting from rest, when its fuel is exhausted? (b) For the two-stage rocket, what is the speed when the fuel of the first stage is exhausted if the first stage carries the second stage with it to this point? This speed then becomes the initial speed of the second stage. At this point, the second stage separates from the first stage.(c) What is the final speed of the second stage? (d) What value of \(v_{\mathrm{ex}}\) is required to give the second stage of the rocket a speed of 7.00 \(\mathrm{km} / \mathrm{s}\) ?

On a frictionless, horizontal air table, puck \(A\) (with mass 0.250 \(\mathrm{kg}\) is moving toward puck \(B\) (with mass 0.350 \(\mathrm{kg}\) ), which is initially at rest. After the collision, puck \(A\) has a velocity of 0.120 \(\mathrm{m} / \mathrm{s}\) to the left, and puck \(B\) has a velocity of 0.650 \(\mathrm{m} / \mathrm{s}\) to the right. (a) What was the speed of puck \(A\) before the collision? (b) Calculate the change in the total kinetic energy of the system that occurs during the collision.

Two fun-loving otters are sliding toward each other on a muddy (and hence frictionless) horizontal surface. One of them, of mass 7.50 \(\mathrm{kg}\) , is shiding to the left at 5.00 \(\mathrm{m} / \mathrm{s}\) , while the other, of mass 5.75 \(\mathrm{kg}\) , is slipping to the right at 6.00 \(\mathrm{m} / \mathrm{s}\) . They hold fast to each other after they collide. (a) Find the magnitude and direction of the velocity of these free-spirited otters right after they collide. (b) How much mechanical energy dissipates during this play?

Two vehicles are approaching an intersection. One is a 2500 -kg pickup traveling at 14.0 \(\mathrm{m} / \mathrm{s}\) from east to west (the \(-x\) -direction), and the other is a \(1500-\mathrm{kg}\) sedan going from south to north (the 1 y-direction at 23.0 \(\mathrm{m} / \mathrm{s} )\) (a) Find the \(x\) - and \(y-\) components of the net momentum of this system. (b) What are the magnitude and direction of the net momentum?

A 1200 -kg station wagon is moving along a straight highway at 12.0 \(\mathrm{m} / \mathrm{s}\) . Another car, with mass 1800 \(\mathrm{kg}\) and speed 20.0 \(\mathrm{m} / \mathrm{s}\) , has its center of mass 40.0 \(\mathrm{m}\) ahead of the center of mass of the station wagon (Fig. 8.39\() .\) (a) Find the position of the center of mass of the system consisting of the two automobiles. (b) Find the magnitude of the total momentum of the system from the given data. (o) Find the speed of the center of mass of the system. (d) Find the total momentum of the system, using the speed of the center of mass. Compare your result with that of part (b).

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