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Changing Mass. An open-topped freight car with mass \(24,000 \mathrm{kg}\) is coasting without friction along a level track. It is raining very hard, and the rain is falling vertically downward. Originally, the car is empty and moving with a speed of 4.00 \(\mathrm{m} / \mathrm{s}\) . What is the speed of the car after it has collected 3000 \(\mathrm{kg}\) of rainwater?

Short Answer

Expert verified
The speed is approximately 3.56 m/s.

Step by step solution

01

Understand the Conservation of Momentum

Since the freight car is coasting without friction, we can assume no external horizontal forces act on the system. The mass is changing due to the rain but does not affect horizontal momentum directly. Hence, we can use the conservation of momentum principle. The total momentum before and after collecting the rain is the same.
02

Write the Initial Momentum Equation

The initial momentum of the freight car can be given by multiplying its mass by its velocity. Initially, the mass of the car is \(24,000 \, \text{kg}\) and velocity is \(4.00 \, \text{m/s}\). So, the initial momentum \(p_i\) is:\[ p_i = 24,000 \, \text{kg} \times 4.00 \, \text{m/s} = 96,000 \, \text{kg} \cdot \text{m/s} \]
03

Write the Final Momentum Equation

After collecting \(3,000 \, \text{kg}\) of rain, the total mass of the system is \(27,000 \, \text{kg}\). Let \(v_f\) be the final speed. The final momentum \(p_f\) is:\[ p_f = 27,000 \, \text{kg} \times v_f \]
04

Apply Conservation of Momentum

Set the initial and final momentum equal to each other, since momentum is conserved:\[ 96,000 \, \text{kg} \cdot \text{m/s} = 27,000 \, \text{kg} \times v_f \]
05

Solve for Final Velocity

From the equation:\[ v_f = \frac{96,000 \, \text{kg} \cdot \text{m/s}}{27,000 \, \text{kg}} \approx 3.56 \, \text{m/s} \]
06

Conclusion

The final speed of the freight car after collecting the rainwater is approximately \(3.56 \, \text{m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Changing Mass
In many physics problems, it is common to encounter systems where the mass is changing. This change can occur due to processes like rain filling a moving vehicle or rocket fuel being consumed. Changes in mass provide a unique challenge but also an interesting application of physical laws.
In our exercise, the mass of the freight car increases as it collects rainwater. The car's mass goes from an initial 24,000 kg to 27,000 kg after collecting 3,000 kg of rainwater. Despite this change, we observe the remarkable phenomenon that, although the mass changes, the horizontal momentum remains conserved. Therefore, understanding how this mass change affects other physical properties, like velocity, is important.
Physics Problem Solving
Solving physics problems often involves multiple steps. It requires identifying known and unknown variables, and selecting the right equations. For problems involving changing mass, the key is recognizing what remains constant. Here, it's the momentum.
Useful strategies in physics problem solving include:
  • Reading through the problem carefully to understand the scenario.
  • Identifying constants, like the conservation of momentum in this case.
  • Breaking down the problem into manageable steps.
  • Using diagrams where necessary to visualize the situation.

In the context of our freight car problem, recognizing that external horizontal forces are absent simplifies the problem, as it hints at the conservation of momentum.
Momentum Equation
Momentum is a central concept in physics and is crucial in solving our given problem. It is defined by the equation: \[ p = m imes v \]where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. Here, we leverage this equation in both initial and final states of the freight car.
Initially, the momentum \( p_i \) is:\[ p_i = 24,000 \, \text{kg} \times 4.00 \, \text{m/s} = 96,000 \, \text{kg} \, \cdot \, \text{m/s} \]After rain collection, the final momentum \( p_f \) involves the new mass:\[ p_f = 27,000 \, \text{kg} \times v_f \]
The principles of the momentum equation ensure that we properly account for changes in mass while maintaining consistency in momentum across the system.
Final Velocity Calculation
Calculating the final velocity is the ultimate goal of the freight car problem. Given the conservation of momentum, we equate the initial and final momentum to find it. Here's how it's done:Set the initial and final momenta equal, as no external horizontal forces are affecting them:\[ 96,000 \, \text{kg} \cdot \text{m/s} = 27,000 \, \text{kg} \times v_f \]
We can solve for \( v_f \) by rearranging and simplifying:\[ v_f = \frac{96,000 \, \text{kg} \cdot \text{m/s}}{27,000 \, \text{kg}} \approx 3.56 \, \text{m/s} \]
Thus, the final velocity of the freight car, after collecting all the rainwater, is approximately \(3.56 \, \text{m/s}\). This successful calculation illustrates how physics can predict changes in motion due to changing mass.

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Most popular questions from this chapter

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a \(0.400-\mathrm{kg}\) ball that is traveling horizontally at 10.0 \(\mathrm{m} / \mathrm{s}\) . Your mass is 70.0 \(\mathrm{kg}\) . (a) If you catch the ball, with what speed do you and the ball move after-ward? (b) If the ball hits you and bounces off your chest, so after-ward it is moving horizontally at 8.0 \(\mathrm{m} / \mathrm{s}\) in the opposite direction, what is your speed after the collision?

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