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A bat strikes a \(0.145-\mathrm{kg}\) baseball. Just before impact, the ball is traveling horizontally to the right at 50.0 \(\mathrm{m} / \mathrm{s}\) , and it leaves the bat traveling to the left at an angle of \(30^{\circ}\) above horizontal with a speed of 65.0 \(\mathrm{m} / \mathrm{s}\) . If the ball and bat are in contact for 1.75 \(\mathrm{ms}\) , find the horizontal and vertical components of the average force on the ball.

Short Answer

Expert verified
Horizontal force: -520.0 N. Vertical force: 2691.4 N.

Step by step solution

01

Gather Known Values

We are given the mass of the baseball \(m = 0.145\,\text{kg}\), initial velocity \(v_i = 50.0\,\text{m/s}\), final velocity \(v_f = 65.0\,\text{m/s}\) at an angle of \(30^{\circ}\), and the contact time \(\Delta t = 1.75\,\text{ms} = 0.00175\,\text{s}\).
02

Decompose the Final Velocity

The final velocity can be broken into horizontal and vertical components:\[ v_{fx} = v_f \cos(30^{\circ}) \approx 56.3\,\text{m/s} \]\[ v_{fy} = v_f \sin(30^{\circ}) \approx 32.5\,\text{m/s} \]
03

Calculate Initial and Final Momentum Components

Initial momentum is only horizontal: \[ p_{ix} = m v_i = 0.145 \times 50.0 = 7.25\,\text{kg m/s} \]The initial vertical component \(p_{iy} = 0\,\text{kg m/s}\).Final momentum components:\[ p_{fx} = m v_{fx} = 0.145 \times 56.3 \approx 8.16\,\text{kg m/s} \]\[ p_{fy} = m v_{fy} = 0.145 \times 32.5 \approx 4.71\,\text{kg m/s} \]
04

Calculate Change in Momentum Components

Change in horizontal momentum:\[ \Delta p_x = p_{fx} - p_{ix} = 8.16 - 7.25 = 0.91\,\text{kg m/s} \]Change in vertical momentum:\[ \Delta p_y = p_{fy} - p_{iy} = 4.71 - 0 = 4.71\,\text{kg m/s} \]
05

Apply Impulse-Momentum Theorem

Using the formula for average force:\[ F_{avg, x} = \frac{\Delta p_x}{\Delta t} = \frac{0.91}{0.00175} \approx 520.0\,\text{N} \]\[ F_{avg, y} = \frac{\Delta p_y}{\Delta t} = \frac{4.71}{0.00175} \approx 2691.4\,\text{N} \]
06

Interpret the Results

The average horizontal force is approximately \(520.0\,\text{N}\) and the average vertical force is approximately \(2691.4\,\text{N}\). The direction for horizontal force is opposite to the ball's initial motion, and the vertical force is upwards.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Change in Momentum
The concept of 'Change in Momentum' is vital in understanding how objects react upon impact. Momentum, denoted by the symbol \( p \), is the product of an object's mass \( m \) and its velocity \( v \). In this context, when a baseball is hit by a bat, its momentum changes as the velocity changes.

Initially, the ball is traveling horizontally, giving it a horizontal momentum. Upon impact, the ball changes direction and speed, thus having both horizontal and vertical momentum components. The change in momentum (\( \Delta p \)) is calculated by subtracting the initial momentum from the final momentum for each direction.

For instance, the change in horizontal momentum \( \Delta p_x \) can be calculated using the formula \( \Delta p_x = p_{fx} - p_{ix} \). Similarly, the change in vertical momentum \( \Delta p_y = p_{fy} - p_{iy} \). By understanding these components, students gain better insight into how forces cause momentum changes during an impact.
Average Force Calculation
The average force exerted on an object during a collision can be derived using the Impulse-Momentum Theorem. This theorem states that the impulse (force applied over time) on an object is equal to its change in momentum. This can be represented by the formula \( \Delta p = F_{avg} \Delta t \), where \( F_{avg} \) is the average force, \( \Delta p \) is the change in momentum, and \( \Delta t \) is the time duration of contact.

Knowing the change in momentum from our previous calculation, you can easily find the average force by rearranging the equation to \( F_{avg} = \frac{\Delta p}{\Delta t} \).
  • The average horizontal force can be found as \( F_{avg, x} = \frac{\Delta p_x}{\Delta t} \).
  • The average vertical force as \( F_{avg, y} = \frac{\Delta p_y}{\Delta t} \).
Understanding the magnitude and direction of these forces provides insight into the physical impact experienced by the ball as it interacts with the bat.
Velocity Components
Velocity components break down a vector's direction and magnitude into two perpendicular directions. In this case, the final velocity of the baseball can be split into horizontal and vertical components using trigonometric functions, which is essential for solving many physics problems.

The horizontal component \( v_{fx} \) is calculated by taking the cosine of the angle and multiplying it by the final velocity, \( v_{fx} = v_f \cos(\theta) \). The vertical component \( v_{fy} \) uses the sine function, \( v_{fy} = v_f \sin(\theta) \).

This separation into components allows you to work with each direction independently—a crucial step when calculating changes in momentum and other forces acting on the object. This ensures that we accurately analyze movements that involve angles, such as a baseball being struck at an angle.

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Most popular questions from this chapter

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