/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 A \(10.0-\mathrm{kg}\) box is pu... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(10.0-\mathrm{kg}\) box is pulled by a horizontal wire in a circle on a rough horizontal surface for which the coefficient of kinetic friction is 0.250 . Calculate the work done by friction during one complete circular trip if the radius is (a) 2.00 \(\mathrm{m}\) and (b) 4.00 \(\mathrm{m}\) . (c) On the basis of the results you just obtained, would you say that friction is a conservative or nonconservative force? Explain.

Short Answer

Expert verified
(a) 307.97 J; (b) 615.94 J; (c) Friction is nonconservative.

Step by step solution

01

Identify Given Data

We have a box with mass \( m = 10.0 \, \text{kg} \) and a coefficient of kinetic friction \( \mu_k = 0.250 \). We are to calculate the work done by friction for two different radii: \( r = 2.00 \, \text{m} \) and \( r = 4.00 \, \text{m} \).
02

Calculate Normal Force

The normal force \( N \) for an object on a horizontal surface is equal to its weight, which is calculated as \( N = m \cdot g \). Here, \( g \approx 9.8 \, \text{m/s}^2 \), so \( N = 10.0 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 98 \, \text{N} \).
03

Calculate Frictional Force

The frictional force \( f_k \) is given by \( f_k = \mu_k \cdot N \). Substituting the values, we get \( f_k = 0.250 \cdot 98 \, \text{N} = 24.5 \, \text{N} \).
04

Calculate Distance Traveled

For one complete circle, the distance traveled is the circumference \( C \) of the circle, calculated as \( C = 2 \pi r \). First for \( r = 2.00 \, \text{m} \), \( C = 2 \pi \times 2.00 \approx 12.57 \, \text{m} \), and then for \( r = 4.00 \, \text{m} \), \( C = 2 \pi \times 4.00 \approx 25.13 \, \text{m} \).
05

Calculate Work Done by Friction (a)

The work done by friction \( W_f \) over a distance \( C \) is \( W_f = f_k \cdot C \). For \( r = 2.00 \, \text{m} \), \( W_f = 24.5 \, \text{N} \times 12.57 \, \text{m} = 307.97 \, \text{J} \).
06

Calculate Work Done by Friction (b)

For \( r = 4.00 \, \text{m} \), \( W_f = 24.5 \, \text{N} \times 25.13 \, \text{m} = 615.94 \, \text{J} \).
07

Interpret Results for Friction (c)

Since the work done by friction depends on the path (circumference), it varies with the radius of the circle. This indicates that friction is a nonconservative force because the work done depends on the path taken.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
In everyday life, friction is the force that opposes motion between two surfaces in contact. Kinetic friction specifically refers to this resistance when surfaces slide against each other while already in motion.
Here we focus on the scenario where a box moves along a rough horizontal surface due to a pulling force.

This frictional force depends on two main factors:
  • The normal force, which is the force perpendicular to the surfaces, often due to the weight of the object involved.
  • The coefficient of kinetic friction, a dimensionless number that expresses the degree of interaction between the surfaces.
To calculate it, multiply the coefficient of kinetic friction (\( \mu_k \)) by the normal force (\( N \)).
In this scenario, with a coefficient of 0.250, the frictional force becomes:\[ f_k = \mu_k \cdot N = 0.250 \times 98 \approx 24.5 \, \text{N} \]This force acts in the opposite direction of motion, thus doing negative work on the box, which results in a decrease in mechanical energy throughout the motion.
Nonconservative Forces
The concept of nonconservative forces is closely associated with energy dissipation. Such forces, unlike conservative forces, do not store energy.
They convert mechanical energy into other energy forms, such as thermal energy, hence why they are path-dependent—work done varies based on the path taken.
Friction is a classic example. The exercise shows how friction performs differing amounts of work for paths with differing radii:
  • Smaller radius \( ( r = 2.00 \, \text{m} )\): The work done is \( 307.97 \, \text{J} \).
  • Larger radius \( ( r = 4.00 \, \text{m} )\): The work done increases to \( 615.94 \, \text{J} \).
This change in work due to varying paths highlights the path-dependency trait of nonconservative forces.
Unlike gravitational or spring forces, kinetic friction doesn't conserve mechanical energy, thus classifying it as a nonconservative force.
Circular Motion
In circular motion, an object moves along a path that forms a circle. Here, the box moves in a circle on a flat surface.
It’s pertinent to consider forces like tension or friction which significantly impact motion properties.

When discussing distance in circular motion, we refer to the circumference of the circle, calculated with:\[ C = 2 \pi r \]This formula gives us the total path length for a complete circle.
In this exercise, varying radii grant us different path lengths:
  • For a circle with radius \( r = 2.00 \, \text{m}, \) the path length approximates 12.57 \, \text{m}.
  • For radius \( r = 4.00 \, \text{m}, \) the path becomes a longer 25.13 \, \text{m}.
The force exerting control here is kinetic friction, as it continuously acts on the box, counteracting the tangential component of its movement
and ultimately influencing the complete journey by its nonconservative nature.

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