/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 You are asked to design spring b... [FREE SOLUTION] | 91Ó°ÊÓ

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You are asked to design spring bumpers for the walls of a parking garage. A freely rolling \(1200-\mathrm{kg}\) car moving at 0.65 \(\mathrm{m} / \mathrm{s}\) is to compress the spring no more than 0.070 \(\mathrm{m}\) before stopping. What should be the force constant of the spring? Assume that the spring has negligible mass.

Short Answer

Expert verified
The force constant of the spring should be approximately 103,673 N/m.

Step by step solution

01

Understanding the Problem

We need to design a spring with a specific force constant such that a car can compress the spring and come to a complete stop. The maximum compression of the spring is 0.070 m, and the car has a mass of 1200 kg moving at an initial speed of 0.65 m/s.
02

Applying the Conservation of Energy

According to the conservation of energy, the initial kinetic energy of the car will be completely converted into the potential energy stored in the spring. Therefore, \[\frac{1}{2} m v^2 = \frac{1}{2} k x^2\]where \(m\) is the mass of the car (1200 kg), \(v\) is the initial velocity (0.65 m/s), \(k\) is the spring constant, and \(x\) is the maximum compression (0.070 m).
03

Solving for the Spring Constant

We can rearrange the energy equation to solve for the spring constant \(k\):\[k = \frac{m v^2}{x^2}\]Plugging in the values:\[k = \frac{1200 \times (0.65)^2}{(0.070)^2} = \frac{1200 \times 0.4225}{0.0049}\]Solving this gives us:\[k \approx 103,673 \text{ N/m}\]
04

Conclusion

The force constant of the spring required to bring the car to a stop without exceeding the maximum compression is approximately 103,673 N/m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
In the study of physics, the conservation of energy principle is a foundational concept. It tells us that energy cannot be created or destroyed, only transformed from one form to another. In our spring bumper problem, this means the initial kinetic energy of the car is transformed entirely into potential energy stored in the spring. Understanding that energy conversion allows us to solve the problem by balancing these two forms of energy.
When a car with a mass of 1200 kg and a velocity of 0.65 m/s rolls into a spring, the spring absorbs the car's energy. The principle of conservation ensures that all the kinetic energy is converted into potential energy, with no energy loss to the environment. This direct transformation forms the basis for calculating the necessary spring constants to safely stop the car.
Kinetic Energy
Kinetic energy represents the energy of motion. For a moving object, this energy is calculated using the formula:
  • \( KE = \frac{1}{2} mv^2 \)
where \(m\) is the object's mass and \(v\) is its velocity. In this scenario, the car's kinetic energy before hitting the spring relies on its mass (1200 kg) and speed (0.65 m/s).
The kinetic energy of the car defines how much energy needs to be absorbed by the spring to bring the car to a halt. By knowing this energy, we can then decide the spring's capability to store enough potential energy and safely stop the car without damaging it or exceeding the spring's maximum compression.
Potential Energy
Potential energy is the stored energy in a system due to its position or configuration. In our case, this energy is stored within the spring once compressed by the incoming car. The equation for calculating potential energy stored in a spring is given by:
  • \( PE = \frac{1}{2} k x^2 \)
where \(k\) is the spring constant and \(x\) is the compression distance.
When the car compresses the spring, its initial kinetic energy transforms into this potential energy. The goal is to choose a spring with the correct force constant \(k\), ensuring all the car's kinetic energy can be safely stored as potential energy without exceeding the allowable compression of 0.070 m.
Spring Compression
The compression distance of a spring—the measure of how much it shortens when force is applied—is crucial for its design and safety in applications. The maximum spring compression in our problem is 0.070 m. With this constraint, we determine the spring's force constant necessary to halt the car effectively.
The relationship between spring force, compression, and the spring constant is expressed as:
  • \( F = kx \)
Where \(F\) is the force applied, \(k\) is the spring constant, and \(x\) is the compression distance. By ensuring the car's kinetic energy matches the spring's potential energy, we find \(k\) using these parameters, ensuring the car stops smoothly within the specified distance.
Physics Problem Solving
Successful physics problem solving uses systematic steps to break down complex issues into manageable parts. Here's how to tackle similar spring and energy problems:
  • **Understand the Problem**: Clearly define what you're solving for, like determining the force constant in our example.
  • **Apply Relevant Equations**: Use fundamental concepts, such as energy conservation, to form equations—like equating kinetic and potential energy here.
  • **Solve Mathematically**: Rearrange equations to isolate the variable of interest, then plug in known values to compute results.
  • **Check Plausibility**: Ensure your answer is logical and within any physical limits, such as maximum compression in this problem scenario.
Through this approach, students can develop a clear understanding and confidence in applying physics principles to real-world issues.

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Most popular questions from this chapter

You throw a \(20-\mathrm{N}\) rock vertically into the air from ground level. You observe that when it is 15.0 \(\mathrm{m}\) above the ground, it is traveling at 25.0 \(\mathrm{m} / \mathrm{s}\) upward. Use the work-energy theorem to find (a) the rock's speed just as it left the ground and (b) its maximum height.

A 75.0 kg painter climbs a ladder that is 2.75 \(\mathrm{m}\) long leaning against a vertical wall. The ladder makes an \(30.0^{\circ}\) angle with the wall. (a) How much work does gravity do on the painter? (b) Does the answer to part (a) depend on whether the painter climbs at constant speed or accelerates up the ladder?

A force in the \(+x\) -direction has magnitude \(F=b / x^{n}\) , where \(b\) and \(n\) are constants. (a) For \(n>1\) , calculate the work done on a particle by this force when the particle moves along the \(x\) -axis from \(x=x_{0}\) to infinity. (b) Show that for \(0< n< 1,\) even though \(F\) becomes zero as \(x\) becomes very large, an infinite amount of work is done by \(F\) when the particle moves from \(x=x_{0}\) to infinity.

Half of a Spring. (a) Suppose you cut a massless ideal spring in half. If the full spring had a force constant \(k\) , what is the force constant of each half, in terms of \(k ?\) (Hint: Think of the original spring as two equal halves, each producing the same force as the entire spring. Do you see why the forces must be equal? (b) If you cut the spring into three equal segments instead, what is the force constant of each one, in terms of \(k ?\)

A 5.00-kg package slides 1.50 \(\mathrm{m}\) down a long ramp that is inclined at \(12.0^{\circ}\) below the horizontal. The coefficient of kinetic friction between the package and the ramp is \(\mu_{\mathrm{k}}=0.310\) . Calculate (a) the work done on the package by friction; (b) the work done on the package by gravity, (c) the work done on the package by the normal force; (d) the total work done on the package. (e) If the package has a speed of 2.20 \(\mathrm{m} / \mathrm{s}\) at the top of the ramp, what is its speed after sliding 1.50 \(\mathrm{m}\) down the ramp?

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