/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 A tandem (two-person) bicycle te... [FREE SOLUTION] | 91Ó°ÊÓ

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A tandem (two-person) bicycle team must overcome a force of 165 \(\mathrm{N}\) to maintain a speed of 9.00 \(\mathrm{m} / \mathrm{s}\) . Find the power required your per rider, assuming that each contributes equally. Express your answer in watts and in horsepower.

Short Answer

Expert verified
Each rider needs 742.5 watts or approximately 0.995 horsepower.

Step by step solution

01

Calculate Total Power Required

Power is defined as the product of force and velocity. Therefore, the total power for the tandem bicycle can be calculated using the formula \( P = F \times v \). Here, \( F = 165 \, \mathrm{N} \) and \( v = 9.00 \, \mathrm{m/s} \). \[ P = 165 \, \mathrm{N} \times 9.00 \, \mathrm{m/s} = 1485 \, \mathrm{W} \] The total power required to maintain the speed is 1485 watts.
02

Calculate Power Per Rider

Since the tandem bicycle is ridden by two people and each contributes equally, we divide the total power by 2. Hence, the power per rider is \[ P_{\text{per rider}} = \frac{1485 \, \mathrm{W}}{2} = 742.5 \, \mathrm{W} \]. Each rider requires 742.5 watts.
03

Convert Watts to Horsepower

To convert the power from watts to horsepower, we use the conversion factor: 1 horsepower = 746 watts. Thus, the power per rider in horsepower is \[ \frac{742.5 \, \mathrm{W}}{746 \, \mathrm{W/horsepower}} \approx 0.995 \text{ horsepower} \]. Therefore, each rider requires roughly 0.995 horsepower.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Velocity
The concepts of force and velocity are fundamental in physics, particularly in understanding motion and energy. **Force** is a push or pull on an object, measured in newtons (N). **Velocity** is the speed of an object in a particular direction, typically measured in meters per second (m/s). Both are vector quantities, meaning they have both magnitude and direction. When an object moves under force, it is said to be in motion, and this motion can be described by its velocity.

The connection between force and velocity is evident when calculating **power**. Power is the rate at which work is done or energy is transferred. In the context of motion, it is the product of force applied to an object and its velocity. Mathematically, this is given by the formula:

\[ P = F \times v \]

where \(P\) is power, \(F\) is force, and \(v\) is velocity. This equation shows that the power needed to keep an object moving, such as a tandem bicycle, is directly proportional to both the force required to overcome resistance and the velocity of the object. If the force or velocity increases, the power required also increases.
Unit Conversion
Unit conversion is an essential skill in physics to ensure that quantities are grouped in consistent units for accurate calculations. Here, power needs to be expressed in both watts and horsepower, which are two different units of power.

**Watts (W)** are the standard unit of power in the International System of Units (SI). One watt is equivalent to one joule per second, and reflects the rate of energy transfer. In this exercise, power calculated was in watts.
  • To express power in horsepower (hp), a non-SI unit commonly used in automotive and mechanical systems, a conversion factor is used. One horsepower is equivalent to 746 watts.
  • To convert from watts to horsepower, divide the power value in watts by 746:
    \[ P_{ ext{hp}} = \frac{P_{ ext{W}}}{746} \]
  • This gives the equivalent power in horsepower.
Applying this conversion ensures that the answer is accessible and understandable in contexts like mechanical systems, where horsepower is often the preferred unit.
Tandem Bicycle Physics
Tandem bicycles, designed for two riders, present unique considerations in physics, particularly around the sharing and distribution of effort and energy. Unlike a single bicycle, where one person provides all the power, a tandem bicycle benefits from the combined effort of two cyclists.
  • Both riders contribute equally to overcoming forces such as friction and air resistance. For riders to move at a steady speed, they must each provide a portion of the total required power. This total power is calculated and then divided by two to find out each rider's individual contribution.
  • In this case, the tandem bicycle riders had to maintain a speed of 9 m/s while overcoming a force of 165 N.
  • Each rider needs to exert power to help the bicycle maintain this speed against the force. By dividing the total power by two, we determine the required individual power output of each rider.
  • This effectively means that the exercise of cycling on a tandem bicycle is an excellent demonstration of teamwork, synchronization, and shared physical effort to achieve a common goal.
Understanding these dynamics emphasizes the importance of coordination and balance between the riders, making the tandem bicycle not just a means of transport but also a lesson in collaborative physics.

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Most popular questions from this chapter

Automotive Power II. (a) If 8.00 hp are required to drive a \(1800-\mathrm{kg}\) automobile at 60.0 \(\mathrm{km} / \mathrm{h}\) on a level road, what is the total retarding force due to friction, air resistance, and so on? (b) What power is necessary to drive the car at 60.0 \(\mathrm{km} / \mathrm{h}\) up a 10.0\(\%\) grade (a hill rising 10.0 \(\mathrm{m}\) vertically in 100.0 \(\mathrm{m}\) horizontally)? (c) What power is necessary to drive the car at 60.0 \(\mathrm{km} / \mathrm{h}\) down a 1.00\(\%\) grade? (d) Down what percent grade would the car coast at 60.0 \(\mathrm{km} / \mathrm{h} ?\)

A \(2.50-\mathrm{kg}\) textbook is forced against a horizontal spring of negligible mass and force constant \(250 \mathrm{N} / \mathrm{m},\) compressing the spring a distance of 0.250 \(\mathrm{m}\) . When released, the textbook slides on a horizontal tabletop with coefficient of kinetic friction \(\mu_{k}=\) \(0.30 .\) Use the work-energy theorem to find how far the textbook moves from its initial position before coming to rest.

A small glider is placed against a compressed spring at the bottom of an air track that slopes upward at an angle of \(40.0^{\circ}\) above the horizontal. The glider has mass 0.0900 \(\mathrm{kg}\) . The spring has \(k=640 \mathrm{N} / \mathrm{m}\) and negligible mass. When the spring is released, the glider travels a maximum distance of 1.80 \(\mathrm{m}\) m along the air track before sliding back down. Before reaching this maximum distance, the glider loses contact with the spring. (a) What distance was the spring originally compressed? (b) When the glider has traveled along the air track 0.80 \(\mathrm{m}\) from its initial position against the compressed spring, is it still in contact with the spring? What is the kinetic energy of the glider at this point?

How many joules of energy does a 100 -watt light bulb use per hour? How fast would a \(70-\mathrm{kg}\) person have to run to have that amount of kinetic energy?

Chin-Ups. While doing a chin-up, a man lifts his body 0.40 \(\mathrm{m}\) . (a) How much work must the man do per kilogram of body mass? (b) The muscles involved in doing a chin-up can generate about 70 \(\mathrm{J}\) of work per kilogram of muscle mass. If the man can just barely do a \(0.40-\mathrm{m}\) chin-up, what percentage of his body's mass do these muscles constitute? (For comparison, the total percentage of muscle in a typical \(70-k g\) man with 14\(\%\) body fat is about 43\(\%\) . (c) Repeat part (b) for the man's young son, who has arms half as long as his father's but whose muscles can also generate 70 \(\mathrm{J}\) of work per kilogram of muscle mass. (d) Adults and children have about the same percentage of muscle in their bodies. Explain why children can commonly do chin-ups more easily than their fathers.

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