/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Certain streets in San Francisco... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Certain streets in San Francisco make an angle of \(17.5^{\circ}\) with the horizontal. What force parallel to the street surface is required to keep a loaded 1967 Corvette of mass 1390 \(\mathrm{kg}\) from rolling down such a street?

Short Answer

Expert verified
The parallel force required is approximately 4101.8 N.

Step by step solution

01

Identify the Known Values

We know the mass of the Corvette is \( m = 1390 \) kg and the angle of the incline is \( \theta = 17.5^{\circ} \).
02

Understand the Concept of Inclined Plane

On an inclined plane, the weight of the object can be broken into two components: one parallel and one perpendicular to the incline. The force required to keep the object from rolling down is equal to the component of gravitational force along the incline.
03

Calculate the Gravitational Force

The weight of the Corvette is calculated by the formula \( F_{\text{gravity}} = m \cdot g \), where \( g = 9.81 \) \( \text{m/s}^2 \) is the acceleration due to gravity. Thus, \( F_{\text{gravity}} = 1390 \cdot 9.81 \).
04

Calculate the Parallel Component of the Force

The force parallel to the incline is given by \( F_{\text{parallel}} = F_{\text{gravity}} \cdot \sin(\theta) \). Substitute the values: \( F_{\text{parallel}} = (1390 \cdot 9.81) \cdot \sin(17.5^{\circ}) \).
05

Complete the Calculation

Calculate \( F_{\text{parallel}} = 13641.9 \cdot \sin(17.5^{\circ}) \). This results in \( F_{\text{parallel}} \approx 4101.8 \) newtons after computing using the sine value.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force Calculation
Calculating gravitational force is a fundamental task when dealing with physics problems such as objects on an inclined plane. Gravitational force refers to the weight of an object, which is the force exerted on it due to gravity. To find this force, we use the formula: \[ F_{\text{gravity}} = m \cdot g \]where:
  • \( m \) is the mass of the object.
  • \( g \) is the acceleration due to gravity, approximately \( 9.81 \, \mathrm{m/s^2} \) on Earth.
For example, in the case of a 1967 Corvette with a mass of 1390 kilograms, the gravitational force can be calculated by multiplying the mass by the acceleration due to gravity:\[ F_{\text{gravity}} = 1390 \times 9.81 \approx 13641.9 \, \mathrm{N} \]This value represents how much the Corvette weighs due to Earth's gravitational pull. It's important to use the correct units and method to ensure accuracy, especially when these calculations serve as a basis for further problem-solving.
Force Components
When dealing with inclined planes, understanding force components is crucial. The weight of an object on an incline can be split into two components:
  • Parallel Component: This is the force responsible for causing the object to slide down the incline. It acts along the surface of the incline.
  • Perpendicular Component: This force acts perpendicular to the surface of the incline and is typically balanced by the normal force, preventing the object from sinking into the surface.
The parallel component of the gravitational force can be found using the equation:\[ F_{\text{parallel}} = F_{\text{gravity}} \cdot \sin(\theta) \]where:
  • \( F_{\text{gravity}} \) is the total gravitational force (weight) of the object.
  • \( \theta \) is the angle of the incline.
In our example, the parallel component of a Corvette's weight on a \( 17.5^{\circ} \) incline is:\[ F_{\text{parallel}} = 13641.9 \times \sin(17.5^{\circ}) \approx 4101.8 \, \mathrm{N} \]This breaking of the force into components is essential in predicting how real-world objects move on slopes.
Physics Problem Solving
Solving physics problems, especially those involving inclined planes, involves a systematic approach. By analyzing each component of a scenario, you can predict outcomes or find necessary measures, like the force needed to prevent motion.With an inclined plane problem:1. **Understand the Problem**: Identify known values such as mass and the angle of incline.2. **Break Down Forces**: Divide gravitational force into its parallel and perpendicular components. Determine which component is relevant for the problem.3. **Use Relevant Formulas**: Apply appropriate physics equations. For inclined planes, this involves calculating the parallel force component with \[ F_{\text{parallel}} = F_{\text{gravity}} \cdot \sin(\theta) \]4. **Complete the Calculations**: Plug in the values you've gathered to find your answer.In essence, breaking down the problem step by step helps in understanding the underlying physics. Practicing this process enhances proficiency in tackling diverse and complex physics challenges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(30.0-\mathrm{kg}\) packing case is initially at rest on the floor of a \(1500-\mathrm{kg}\) pickup truck. The coefficient of static friction between the case and the truck floor is \(0.30,\) and the coefficient of kinetic friction is \(0.20 .\) Before each acceleration given below, the truck is traveling due north at constant speed. Find the magnitude and direction of the friction force acting on the case (a) when the truck accelerates at 2.20 \(\mathrm{m} / \mathrm{s}^{2}\) northward and (b) when it accelerates at 3.40 \(\mathrm{m} / \mathrm{s}^{2}\) southward.

An airplane flies in a loop (a circular path in a vertical plane) of radius 150 \(\mathrm{m}\) . The pilot's head always points toward the center of the loop. The speed of the airplane is not constant; the airplane goes slowest at the top of the loop and fastest at the bottom. (a) At the top of the loop, the pilot feels weightless. What is the speed of the airplane at this point? (b) At the bottom of the loop, the speed of the airplane is 280 \(\mathrm{km} / \mathrm{h}\) . What is the apparent weight of the pilot at this point? His true weight is 700 \(\mathrm{N}\) .

A machine part consists of a thin 40.0 -cm-long bar with small \(1.15-\mathrm{kg}\) masses fastened by screws to its ends. The screws can support a maximum force of 75.0 \(\mathrm{N}\) without pulling out. This bar rotates about an axis perpendicular to it at its center. (a) As the bar is turning at a constant rate on a horizontal frictionless surface, what is the maximum speed the masses can have without pulling out the screws? (b) Suppose the machine is redesigned so that the bar turns at a constant rate in a vertical circle. Will one of the screws be more likely to pull out when the mass is at the top of the circle or at the bottom? Use a free-body diagram to see why. (c) Using the result of part (b), what is the greatest speed the masses can have without pulling a screw?

A box of bananas weighing 40.0 \(\mathrm{N}\) rests on a horizontal surface. The coefficient of static friction between the box and the sur- face is \(0.40,\) and the coefficient of kinetic friction is 0.20 . (a) If no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on the box? (b) What is the magnitude of the friction force if a monkey applies a horizontal force of 6.0 \(\mathrm{N}\) to the box and the box is initially at rest? (c) What minimum horizontal force must the monkey apply to start the box in motion? (d) What minimum horizontal force must the monkey apply to keep the box moving at constant velocity once it has been started? (e) If the monkey applies a horizontal force of \(18.0 \mathrm{N},\) what is the magnitude of the friction force and what is the box's acceleration?

The Cosmoclock 21 Ferris wheel in Yokohama City, Japan, has a diameter of 100 \(\mathrm{m}\) . Its name comes from its 60 arms, each of which can function as a second hand (so that it makes one revolution every 60.0 \(\mathrm{s}\) ). (a) Find the speed of the passengers when the Ferris wheel is rotating at this rate. (b) A passenger weighs 882 \(\mathrm{N}\) at the weight-guessing booth on the ground. What is his apparent weight at the highest and at the lowest point on the Ferris wheel? (c) What would be the time for one revolution if the passenger's apparent weight at the highest point were zero? (d) What then would be the passenger's apparent weight at the lowest point?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.