/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 (a) Consider the hydrogen molecu... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) Consider the hydrogen molecule \(\left(\mathrm{H}_{2}\right)\) to be a simple harmonic oscillator with an equilibrium spacing of 0.074 \(\mathrm{nm}\) , and estimate the vibrational energy-level spacing for \(\mathrm{H}_{2}\) . The mass of a hydrogen atom is \(1.67 \times 10^{-27} \mathrm{kg}\) . (Hint: Estimate the force constant by equating the change in Coulomb repulsion of the protons, when the atoms move slightly closer together than \(r_{0},\) to the "spring" force. That is, assume that the chemical binding force remains approximately constant as \(r\) is decreased slightly from \(r_{0} .\) ) (b) Use the results of part (a) to calculate the vibrational energy-level spacing for the deuterium molecule, \(\mathrm{D}_{2}\) . Assume that the spring constant is the same for \(\mathrm{D}_{2}\) as for \(\mathrm{H}_{2}\) . The mass of a deuterium atom is \(3.34 \times 10^{-27} \mathrm{kg}\) .

Short Answer

Expert verified
The vibrational energy-level spacing for H2 is higher than for D2 due to the larger reduced mass of D2.

Step by step solution

01

Calculate the Coulomb repulsion force

Initially, consider the repulsion force between the protons in the hydrogen molecule when they are at the equilibrium distance \(r_0 = 0.074 \, \text{nm} = 0.074 \times 10^{-9} \text{m} \). The Coulomb force is given by:\[F = \frac{k \cdot e^2}{r_0^2}\]where \( k = 8.99 \times 10^9 \text{Nm}^{2}/\text{C}^{2} \) is Coulomb's constant and \( e = 1.602 \times 10^{-19} \text{C} \) is the charge of a proton. Substituting these values provides the force.
02

Calculate the force constant (k)

Assume the harmonic potential energy change is comparable to the Coulomb repulsion force, thus \( F = k \cdot r_0 \). Solving for the force constant:\[k = \frac{F}{r_0} = \frac{k \cdot e^2}{r_0^3}\]Substitute the calculated \( F \) from Step 1 into this equation to find \( k \).
03

Calculate the vibrational energy-level spacing for H2

The vibrational energy-level spacing is given by:\[\Delta E = \hbar \sqrt{\frac{k}{\mu}}\]Where \( \mu \) is the reduced mass of the hydrogen molecule:\[\mu = \frac{m_1 m_2}{m_1 + m_2} = \frac{1.67 \times 10^{-27} \times 1.67 \times 10^{-27}}{1.67 \times 10^{-27} + 1.67 \times 10^{-27}} = \frac{1.67 \times 10^{-27}}{2}\]Thus calculate \( \Delta E \) using the known values and previously found \( k \).
04

Calculate the vibrational energy-level spacing for D2

Using the same force constant \( k \) found for \( \text{H}_2 \), determine the vibrational energy-level spacing for \( \text{D}_2 \). The reduced mass \( \mu \) for \( \text{D}_2 \) (deuterium molecule) is:\[\mu = \frac{3.34 \times 10^{-27} \times 3.34 \times 10^{-27}}{3.34 \times 10^{-27} + 3.34 \times 10^{-27}} = \frac{3.34 \times 10^{-27}}{2}\]Substitute into:\[\Delta E = \hbar \sqrt{\frac{k}{\mu}}\]Use previously calculated \( k \) to get \( \Delta E \) for \( \text{D}_2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vibrational Energy Levels
In molecular physics, understanding the vibrational energy levels of molecules like hydrogen is crucial. These energy levels arise due to the vibration of atoms within a molecule, much like a mass on a spring.
For a simple harmonic oscillator model, which is often used to describe molecular vibrations, the vibrational energy levels are quantized. This means the energy can only take on specific, discrete values. These are typically expressed as \(E_n = \hbar \omega (n + \frac{1}{2})\), where \(\omega\) is the angular frequency and \(n\) is the vibrational quantum number.
  • Each level corresponds to different vibrational states.
  • Energy spacing between levels can influence molecular behavior.
The energy spacing is also known as the vibrational energy-level spacing \(\Delta E\), which can be deduced using the formula \(\Delta E = \hbar \sqrt{\frac{k}{\mu}}\). Here, \(k\) is the force constant and \(\mu\) the reduced mass of the molecule. This expression shows that spacing depends on both the "springiness" of the bond and the effective mass of the oscillating system. Understanding these energy levels helps in spectroscopy and other fields, where molecular vibration is a significant factor.
Molecular Physics
At the heart of molecular physics lies the detailed study of molecules, their bonds, and interactions. One key model in this field is the quantum harmonic oscillator, used to represent the vibration of atoms within a molecule.
Molecular physics seeks to understand how these small systems behave under various forces and conditions. It considers forces such as the Coulomb force, which acts between charged particles within a molecule like hydrogen \( \text{H}_2 \). This force is critical in maintaining the molecule's structure and affects how it vibrates.
  • Electrostatic interactions: primary forces in molecules based on charge.
  • Bonding and antibonding states: influence how molecules hold together.
When hydrogen atoms move closer or farther apart from their optimal distance (measured at the equilibrium separation \(r_0\)), they experience changes in these Coulomb forces. To predict these interactions accurately, molecular physicists employ mathematical models that consider these changes, ensuring predictions align closely with experimental data.
In exploring molecular physics, one gains insights into molecular behavior's fundamental principles. Despite its complexity, this field holds vast applications, from material science to chemistry.
Reduced Mass
Reduced mass is a crucial concept in analyzing how two-body systems vibrate, and it simplifies the calculations of their motion. In essence, it allows us to model the complex interaction of two particles as if it were a single particle system. This simplification is vital when looking at molecular vibrational models.
For a diatomic molecule with two masses \(m_1\) and \(m_2\), the reduced mass \(\mu\) is given by: \[\mu = \frac{m_1 m_2}{m_1 + m_2}\]
  • It effectively "averages" the motion between two particles.
  • Considered in the context of vibrational energy levels, it helps determine the spacing \(\Delta E\).
In the hydrogen molecule \( \text{H}_2 \), where both atoms are identical, the reduced mass simplifies to half the mass of a single atom. The concept of reduced mass becomes particularly intriguing in isotopic variations, such as between hydrogen \( \text{H}_2 \) and deuterium \( \text{D}_2 \), where the individual atomic masses differ, thus altering \(\mu\). This affects how vibrational energies are spaced and the overall vibrational dynamics.
Understanding reduced mass is essential for anyone delving into molecular physics and quantum chemistry as it provides clarity and simplicity to otherwise complex molecular interactions.

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Most popular questions from this chapter

The gap between valence and conduction bands in diamond is 5.47 eV. (a) What is the maximum wavelength of a photon that can excite an electron from the top of the valence band into the conduction band? In what region of the electromagnetic spectrum does this photon lie? (b) Explain why pure diamond is transparent and colorless. (c) Most gem diamonds have a yellow color. Explain how impurities in the diamond can cause this color.

Silver has a Fermi energy of 5.48 eV. Calculate the electron contribution to the molar heat capacity at constant volume of silver, \(C_{V},\) at 300 \(\mathrm{K}\) . Express your result \((\mathrm{a})\) as a multiple of \(R\) and (b) as a fraction of the actual value for silver, \(C_{V}=25.3 \mathrm{J} / \mathrm{mol} \cdot \mathrm{K}\) . (c) Is the value of \(C_{V}\) due principally to the electrons? If not, to what is it due? (Hint: See Section \(18.4 . )\)

When an OH molecule undergoes a transition from the \(n=0\) to the \(n=1\) vibrational level, its internal vibrational energy increases by 0.463 eV. Calculate the frequency of vibration and the force constant for the interatomic force. (The mass of an oxygen atom is \(2.66 \times 10^{-26} \mathrm{kg}\) , and the mass of a hydrogen atom is \(1.67 \times 10^{-27} \mathrm{kg} . )\)

Hydrogen is found in two naturally occurring isotopes; normal hydrogen (containing a single proton in its nucleus) and deuterium (having a proton and a neutron). Assuming that both molecules are the same size and that the proton and neutron have the same mass (which is almost the case), find the ratio of (a) the energy of any given rotational state in a diatomic hydrogen molecule to the energy of the same state in a diatomic deuterium molecule and (b) the energy of any given vibrational state in hydrogen to the same state in deuterium (assuming that the force constant is the same for both molecules). Why is it physically reasonable that the force constant would be the same for hydrogen and deuterium molecules?

The gap between valence and conduction bands in sillicon is 1.12 eV. A nickel nucleus in an excited state emits a gamma-ray photon with wavelength \(9.31 \times 10^{-4} \mathrm{nm}\) . How many electrons can be excited from the top of the valence band to the bottom of the conduction band by the absorption of this gamma ray?

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