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Estimate the minimum and maximum wavelengths of the characteristic \(x\) rays emitted by (a) vanadium \((Z=23)\) and \((b)\) rhenium \((Z=45)\) . Discuss any approximations that you make.

Short Answer

Expert verified
Use Moseley's law for vanadium and rhenium to estimate wavelengths from the K-series.

Step by step solution

01

Understanding the Problem

We need to estimate the minimum and maximum wavelengths of characteristic \(x\) rays emitted by two elements: vanadium (\(Z=23\)) and rhenium (\(Z=45\)). We will use Moseley's law, which relates the frequency of \(x\) rays emitted by an element to its atomic number \(Z\).
02

Moseley's Law Application

Moseley's law is given by the formula \( \sqrt{u} = a(Z - b) \), where \( u \) is the frequency of the \(x\) ray, \( a \) and \( b \) are constants. The speed of light \( c \) and the wavelength \( \lambda \) are related by \( c = \lambda u \). So, we can find \( \lambda \) by modifying Moseley's law.
03

Minimum Wavelength Calculation

The minimum wavelength, \( \lambda_{min} \), corresponds to the highest frequency of \(x\) rays. For the K-series \(x\) rays, where the values of \( a \) and \( b \) are constants specific to the K-series, calculate the minimum wavelengths for vanadium and rhenium using the relation: \[ c = a^2 (Z - b)^2 \lambda_{min} \]. Solve for \( \lambda_{min} \).
04

Maximum Wavelength Explanation

The maximum wavelength relates to the lowest energy transition. In practice, precise calculations require quantum mechanics, but estimates can assume it occurs near the L-series or M-series. Due to the complexity, we'll only focus on the most common K-series for simplicity.
05

Approximations and Discussion

An approximation is made assuming all calculations focus on K-series \(x\) rays as they are the most common. The model doesn't account for electron shielding or relativistic effects, but gives a reasonable estimation for typical calculations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moseley's Law
Moseley's Law is a fundamental principle in physics that relates the frequency of X-rays emitted by an atom to its atomic number. The law is articulated through the famous formula \( \sqrt{u} = a(Z - b) \), where \( u \) symbolizes the frequency of the X-ray, \( a \) and \( b \) are empirical constants specific to particular X-ray series, and \( Z \) is the atomic number. This groundbreaking discovery allowed scientists to realize that the properties of an element are more related to its atomic number rather than its atomic mass.

This law was revolutionary because it provided a straightforward method of understanding the arrangement of the periodic table based on atomic numbers rather than weights. It paved the way for more accurate predictions about an element’s behavior in chemical reactions and their physical properties. Moseley's experiments demonstrated a clear and systematic ordering of elements, emphasizing the importance of the atomic number in explaining the identity and properties of elements.
Atomic Number
The atomic number, denoted as \( Z \), is one of the most critical identifiers of an element in chemistry and physics. It represents the number of protons found in the nucleus of an atom. Each element on the periodic table has a unique atomic number, which definitively determines its position and identity.

The atomic number is pivotal in understanding an element's electronic structure. Since atoms are electrically neutral, the number of electrons in an atom is equal to the atomic number, which in turn determines how an element will bond with others, influencing its chemical behavior.

It also plays a central role in the emission of X-rays as described by Moseley’s Law. The concept illustrates that higher atomic numbers result in higher frequency X-rays, thus affecting the wavelengths of the emitted radiation. When elements emit characteristic X-rays, the transitions are linked directly to their atomic numbers, making \(Z\) vital for calculation and prediction in X-ray spectroscopy.
Characteristic X-rays
Characteristic X-rays are photons emitted from an atom when outer-shell electrons fill an inner-shell vacancy, resulting in a release of energy. This process occurs after the atom has been ionized, or a vacancy has been created, typically by bombardment with high-energy particles or photons. The energy of these X-rays is characteristic of the difference in the energy levels of the atom, hence the name "characteristic".

There are different series of characteristic X-rays, the most significant being the K, L, and M series. Each series corresponds to different electron transitions filling vacancies in specific shells of the atom. The K-series involves transitions to the innermost shell, resulting in higher energy and frequency X-rays, while L and M series involve outer shells.

Characteristic X-rays are highly useful in analytical techniques such as X-ray fluorescence (XRF) spectroscopy, as they provide insightful details about elemental composition and chemical states. Each element emits its unique X-ray spectral lines, allowing them to serve as "fingerprints" for identifying and analyzing materials.
Wavelength Calculation
Wavelength calculation of X-rays is an essential aspect of understanding the properties of the radiation emitted by various elements. The relationship between the wavelength \( \lambda \), frequency \( u \), and speed of light \( c \) is given by the equation \( c = \lambda u \). Within the context of X-ray emission, determining the wavelength involves using the information provided by Moseley’s Law.

To find the wavelength of characteristic X-rays, we start by calculating the frequency \( u \) utilizing the modified version of Moseley's Law for a specific series (like the K-series). Once we have the frequency, the wavelength can be determined by rearranging the equation for the speed of light to \( \lambda = \frac{c}{u} \). This straightforward calculation is instrumental in fields like crystallography and material sciences where understanding the interaction of X-rays with matter is critical.

Minimal wavelengths correspond to maximum energy transitions (like in the K-series), while maximal wavelengths relate to lower energy transitions. Although precise calculations can become quite complex involving quantum mechanics and consideration of electron interactions, these basic relationships provide a useful framework for making reasonable estimations in strategic scientific explorations.

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Most popular questions from this chapter

A hydrogen atom in a particular orbital angular momentum state is found to have \(j\) quantum numbers \(\frac{7}{2}\) and \(\frac{9}{2} .\) What is the letter that labels the value of \(l\) for the state?

A hydrogen atom in the 5 g state is placed in a magnetic field of 0.600 T that is in the \(z\) -direction. (a) Into how many levels is this state split by the interaction of the atom's orbital magnetic dipole moment with the magnetic field? (b) What is the energy separation between adjacent levels?(c) What is the energy separation between the level of lowest energy and the level of highest energy?

The orbital angular momentum of an electron has a magnitude of \(4.716 \times 10^{-34} \mathrm{kg} \cdot \mathrm{m}^{2} / \mathrm{s}\) . What is the angular- momentum quantum number \(I\) for this electron?

Effective Magnetic Field. An electron in a hydrogen atom is in the 2\(p\) state. In a simple model of the atom, assume that the electron circles the proton in an orbit with radius \(r\) equal to the Bohr-model radius for \(n=2 .\) Assume that the speed \(v\) of the orbiting electron can be calculated by setting \(L=m v r\) and taking \(L\) to have the quantum-mechanical value for a 2\(p\) state. In the frame of the electron, the proton orbits with radius \(r\) and speed \(v\) . Model the orbiting proton as a circular current loop, and calculate the magnetic field it produces at the location of the electron.

(a) What is the lowest possible energy (in electron volts) of an electron in hydrogen if its orbital angular momentum is \(\sqrt{12} \mathrm{k}\) ? (b) What are the largest and smallest values of the \(z\) -component of the orbital angular momentum (in terms of \(\hbar\) ) for the electron in part (a)? (c) What are the largest and smallest values of the spin angular momentum (in terms of \(\hbar\) ) for the electron in part (a)? (d) What are the largest and smallest values of the orbital angular momentum (in terms of \(\hbar\) ) for an electron in the \(M\) shell of hydrogen?

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