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Two forces, \(\overrightarrow{\boldsymbol{K}}_{1}\) and \(\overrightarrow{\boldsymbol{F}}_{2}\) act at a point. The magnitude of \(\overrightarrow{\boldsymbol{F}}_{1}\) is \(9.00 \mathrm{N},\) and its direction is \(60.0^{\circ}\) above the \(x\) -axis in the second quadrant. The magnitude of \(\overrightarrow{\boldsymbol{F}}_{2}\) is \(6.00 \mathrm{N},\) and its direction is \(53.1^{\circ}\) below the \(x\) -axis in the third quadrant. (a) What are the \(x\) - and \(y-\) components of the resultant force? (b) What is the magnitude of the resultant force?

Short Answer

Expert verified
(a) Resultant components: \( F_{Rx} = -8.10 \text{ N}, F_{Ry} = 2.99 \text{ N} \). (b) Magnitude of resultant force: \( 8.63 \text{ N} \).

Step by step solution

01

Given Information

Identify the magnitudes and directions provided in the problem. We know that \( \vec{F}_1 \) has a magnitude of 9.00 N and is directed at 60.0° above the x-axis in the second quadrant. \( \vec{F}_2 \) has a magnitude of 6.00 N and is directed at 53.1° below the x-axis in the third quadrant.
02

Break Down Each Force into Components

For \( \vec{F}_1 \):- \( F_{1x} = -9.00 \cos(60.0^{\circ}) \) since it's in the second quadrant.- \( F_{1y} = 9.00 \sin(60.0^{\circ}) \).For \( \vec{F}_2 \):- \( F_{2x} = -6.00 \cos(53.1^{\circ}) \) since it's in the third quadrant.- \( F_{2y} = -6.00 \sin(53.1^{\circ}) \) since it is below the x-axis.
03

Calculate the Components

Calculate the x- and y-components for each force:- \( F_{1x} = -9.00 \times 0.5 = -4.50 \text{ N} \)- \( F_{1y} = 9.00 \times 0.866 = 7.79 \text{ N} \)- \( F_{2x} = -6.00 \times 0.6 = -3.60 \text{ N} \)- \( F_{2y} = -6.00 \times 0.8 = -4.80 \text{ N} \)
04

Find the Resultant Components

Add the individual components of the forces to find the resultant force components:- Resultant \( x \)-component: \( F_{Rx} = F_{1x} + F_{2x} = -4.50 + (-3.60) = -8.10 \text{ N} \)- Resultant \( y \)-component: \( F_{Ry} = F_{1y} + F_{2y} = 7.79 + (-4.80) = 2.99 \text{ N} \)
05

Calculate the Magnitude of the Resultant Force

Use the Pythagorean theorem to find the magnitude of the resultant force:\[ F_R = \sqrt{F_{Rx}^2 + F_{Ry}^2} = \sqrt{(-8.10)^2 + (2.99)^2} = \sqrt{65.61 + 8.94} = \sqrt{74.55} \approx 8.63 \text{ N} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force Components
To understand vector addition in the context of forces, it's crucial to break down each force into its components. A force vector like \( \overrightarrow{\boldsymbol{F}}_1 \) or \( \overrightarrow{\boldsymbol{F}}_2 \) can be separated into two components: one along the x-axis and one along the y-axis. This process allows us to analyze the impact of each force in each direction, which is essential for finding the resultant force.
When given the magnitude of a force and its angle with respect to an axis, you can use trigonometry to find its components:
  • The x-component is found using \( F_x = |F| \cos(\theta) \), where \(|F|\) is the magnitude of the force and \(\theta\) is the angle from the x-axis.
  • The y-component is determined by \( F_y = |F| \sin(\theta) \).
It's important to consider the quadrant where the force is acting, as this will affect the signs of the components. For example, a force in the second quadrant will have a negative x-component, while a force below the x-axis means the y-component will be negative.
Understanding how to break down forces into components is a foundational skill in physics that simplifies the complexity of multiple interacting forces.
Resultant Force
Once you have the components of all the individual forces, the next step is to find the resultant force. This is the combined effect of all forces acting at a point.
The resultant force can be calculated by adding together all the x-components to find the total x-component and all the y-components to find the total y-component:
  • Resultant x-component: \( F_{Rx} = F_{1x} + F_{2x} + \ldots \)
  • Resultant y-component: \( F_{Ry} = F_{1y} + F_{2y} + \ldots \)
These resultant components represent the net force acting in each direction.

Having the resultant components allows us to determine the overall effect of multiple forces acting together, giving a comprehensive view of the force at the point where they meet.
In practical terms, knowing the resultant force helps predict how an object will move when influenced by various forces. This principle is applicable in numerous fields, from mechanical engineering to everyday problem-solving, like determining whether a stationary object will start moving.
Pythagorean Theorem
After finding the resultant x- and y-components, you'll often need to calculate the magnitude of the resultant force. This is where the Pythagorean theorem is instrumental.
According to the Pythagorean theorem, the magnitude of the resultant force can be found using the equation:
\[ F_R = \sqrt{F_{Rx}^2 + F_{Ry}^2} \]
This formula comes from the geometric relationship in a right triangle, where the legs are the x- and y-components, and the hypotenuse is the resultant force.
The Pythagorean theorem is a powerful tool because it simplifies the process of finding the overall effect of perpendicular components (such as the force components along the x and y axes). It's essential when calculating the net effect of forces, ensuring a straightforward method to arrive at the magnitude of a vector.
Understanding and applying the Pythagorean theorem strengthens your ability to resolve and combine forces, providing clearer insights into the physical phenomena described by vectors.

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Most popular questions from this chapter

A parachutist relies on air resistance (mainly on her parachute) to decrease her downward velocity. She and her parachute have a mass of \(55.0 \mathrm{kg},\) and air resistance exerts a total upward force of 620 \(\mathrm{N}\) on her and her parachute. (a) What is the weight of the parachutist? (b) Draw a free-body diagram for the parachutist (see Section 4.6 ). Use that diagram to calculate the net force on the parachutist. Is the net force upward or downward? (c) What is the acceleration (magnitude and direction) of the parachutist?

A chair of mass 12.0 \(\mathrm{kg}\) is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force \(F=40.0 \mathrm{N}\) that is directed at an angle of \(37.0^{\circ}\) below the horizontal and the chair slides along the floor. (a) Draw a clearly labeled free-body diagram for the chair. (b) Use your diagram and Newton's laws to calculate the normal force that the floor exerts on the chair.

An astronaut's pack weighs 17.5 \(\mathrm{N}\) when she is on earth but only 3.24 \(\mathrm{N}\) when she is at the surface of an asteroid. (a) What is the acceleration due to gravity on this asteroid? (b) What is the mass of the pack on the asteroid?

You have just landed on Planet \(X\) . You take out a 100 -g ball, release it from rest from a height of \(10.0 \mathrm{m},\) and measure that it takes 2.2 \(\mathrm{s}\) to reach the ground. You can ignore any force on the ball from the atmosphere of the planet. How much does the \(100-\mathrm{g}\) ball weigh on the surface of Planet \(\mathrm{X}\) ?

To study damage to aircraft that collide with large birds, you design a test gun that will accelerate chicken-sized objects so that their displacement along the gun barrel is given by \(x=\) \(\left(9.0 \times 10^{3} \mathrm{m} / \mathrm{s}^{2}\right) t^{2}-\left(8.0 \times 10^{4} \mathrm{m} / \mathrm{s}^{3}\right) t^{3} .\) The object leaves the end of the barrel at \(t=0.025 \mathrm{s}\) (a) How long must the gun barrel be? \((b)\) What will be the speed of the objects as they leave the end of the barrel? (c) What net force must be exerted on a \(1.50-k g\) object at \((\mathrm{i}) t=0\) and (ii) \(t=0.025 \mathrm{s} ?\)

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