/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Two crates, \(A\) and \(B,\) sit... [FREE SOLUTION] | 91Ó°ÊÓ

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Two crates, \(A\) and \(B,\) sit at rest side by side on a frictionless horizontal surface. The crates have masses \(m_{A}\) and \(m_{B}\) . A horizontal force \(\vec{F}\) is applied to crate \(A\) and the two crates move off to the right. (a) Draw clearly labeled free-body diagrams for crate \(A\) and for crate \(B\) . Indicate which pairs of forces, if any, are third-law action-reaction pairs. (b) If the magnitude of force \(\vec{F}\) is less than the total weight of the two crates, will it cause the crates to move? Explain.

Short Answer

Expert verified
Yes, the crates will move as \( \vec{F} \) is applied on a frictionless surface.

Step by step solution

01

Draw Free-Body Diagram for Crate A

In the free-body diagram for crate A, draw the horizontal force \( \vec{F} \) applied on it directed to the right. It also experiences a contact force \( \vec{F}_{AB} \) from crate B directed to the left. The normal force \( \vec{N}_A \) acts upwards, and gravity \( \vec{W}_A = m_Ag \) acts downwards.
02

Draw Free-Body Diagram for Crate B

In the free-body diagram for crate B, illustrate the contact force \( \vec{F}_{BA} \) directed to the right which is exerted by crate A on B. The normal force \( \vec{N}_B \) acts upwards, while gravity \( \vec{W}_B = m_Bg \) acts downwards.
03

Identify Action-Reaction Pairs

According to Newton's third law, the contact force \( \vec{F}_{AB} \) that crate B exerts on crate A is an action-reaction pair with the force \( \vec{F}_{BA} \) that crate A exerts on crate B. Thus, \( \vec{F}_{AB} = -\vec{F}_{BA} \).
04

Assess the Impact of Force Magnitude

Since the surface is frictionless, a net horizontal force will cause acceleration, regardless of the weight of the crates. Even if \( \vec{F} \) is less than the total weight, the crates will start moving as \( \vec{F} \) overcomes zero static horizontal force due to friction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free-Body Diagrams
Free-body diagrams are visual tools used to illustrate the relative magnitude and direction of all forces acting upon a single object. These diagrams make it easier to understand the dynamics of how objects interact. In our scenario, the focus is on crates A and B, positioned side by side on a frictionless surface. Each crate is influenced by several forces, including the applied horizontal force and gravitational force.

For crate A, the free-body diagram consists of:
  • The applied force \( \vec{F} \) to the right, moving the system.
  • A contact force \( \vec{F}_{AB} \) exerted by crate B to the left.
  • The normal force \( \vec{N}_A \) directed upwards balancing the gravitational pull.
  • The weight force \( \vec{W}_A = m_Ag \) acting downwards due to gravity.
For crate B, the main components are:
  • A contact force \( \vec{F}_{BA} \) exerted by crate A, pointing rightward.
  • Its own normal force \( \vec{N}_B \) pushing upwards against gravity.
  • The weight force \( \vec{W}_B = m_Bg \), which also acts downward.
Such diagrams help determine net forces, predicting acceleration, and understanding interactions, making them a cornerstone in physics problem-solving.
Newton's Third Law
Newton's Third Law of Motion is famously summarized as "For every action, there is an equal and opposite reaction." This principle explains how forces operate in pairs. In our example with crates A and B, the contact forces between them form an action-reaction pair.

When crate A pushes on crate B with the force \( \vec{F}_{BA} \), crate B pushes back equally and oppositely with force \( \vec{F}_{AB} \). These forces are equal in magnitude but opposite in direction (\( \vec{F}_{AB} = -\vec{F}_{BA} \)).

This action-reaction pair exhibits how forces between interacting bodies are mutual, leading to every pushed or pulled object reciprocating the force. This insight helps us understand why both crates will indeed accelerate in the same direction when a force is applied. They move as a single system because the internal forces between them balance each other out, allowing the external force \( \vec{F} \) to dictate their motion.
Frictionless Surfaces
A frictionless surface is an idealized concept where there is no friction acting against an object's motion. In real-world scenarios, frictional forces would oppose motion, but on a frictionless surface, objects can move unimpeded. This concept simplifies calculations as the absence of friction means we only consider external forces, like applied or normal forces.

In our example with the crates, because the surface is frictionless, there is no resistance to the applied horizontal force \( \vec{F} \). This results in any net horizontal force, no matter how small, causing the crates to accelerate. It underscores an important point: even if the applied force \( \vec{F} \) is less than the combined weight of the crates, it can still cause them to move, as long as it overcomes any other horizontal forces—in this ideal case, there are none.

This scenario reinforces Newton's first law, the principle of inertia, where objects in motion remain in motion unless acted on by an external force—in this case, since there's nothing to stop them, any applied force results in movement.

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Most popular questions from this chapter

A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude 48.0 \(\mathrm{N}\) to the box and produces an acceleration of magnitude \(3.00 \mathrm{m} / \mathrm{s}^{2},\) what is the mass of the box?

You have just landed on Planet \(X\) . You take out a 100 -g ball, release it from rest from a height of \(10.0 \mathrm{m},\) and measure that it takes 2.2 \(\mathrm{s}\) to reach the ground. You can ignore any force on the ball from the atmosphere of the planet. How much does the \(100-\mathrm{g}\) ball weigh on the surface of Planet \(\mathrm{X}\) ?

An astronaut is tethered by a strong cable to a spacecraft. The astronaut and her spacesuit have a total mass of 105 \(\mathrm{kg}\) , while the mass of the cable is negligible. The mass of the spacecraft is \(9.05 \times 10^{4} \mathrm{kg}\) . The spacecraft is from any large astronomical bodies, so we can ignore the gravitational forces on it and the astronaut. We also assume that both the spacecraft and the astronaut are initially at rest in an inertial reference frame. The astronaut then pulls on the cable with a force of 80.0 \(\mathrm{N}\) . (a) What force bodies, so we can ignore the gravitational forces on it and the astronaut. We also assume that both the spacecraft and the astronaut are initially at rest in an inertial reference frame. The astronaut then pulls on the cable with a force of 80.0 \(\mathrm{N}\) . (a) What force does the cable exert on the astronaut? (b) Since \(\Sigma \overrightarrow{\boldsymbol{F}}=m \overrightarrow{\mathbf{a}},\) how can a "massless" \((m=0)\) cable exert a force? (c) What is the astronaut's acceleration? (d) What force does the cable exert on the spacecraft? (e) What is the acceleration of the spacecraft?

An astronaut's pack weighs 17.5 \(\mathrm{N}\) when she is on earth but only 3.24 \(\mathrm{N}\) when she is at the surface of an asteroid. (a) What is the acceleration due to gravity on this asteroid? (b) What is the mass of the pack on the asteroid?

A dockworker applies a constant horizontal force of 80.0 \(\mathrm{N}\) to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 \(\mathrm{m}\) in 5.00 \(\mathrm{s}\) . (a) What is the mass of the block of ice? (b) If the worker stops pushing at the end of 5.00 \(\mathrm{s}\) s, how far does the block move in the next 5.00 \(\mathrm{s?}\)

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