/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Consider the complex-valued func... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the complex-valued function \(f(x, y)=(x-i y) l\) \((x+i y) .\) Calculate \(|f|^{2}\)

Short Answer

Expert verified
\(|f|^2\) results in a real combination product.

Step by step solution

01

Understanding the Problem

The function given is a complex function: \( f(x, y) = (x - i y) \ln(x + i y) \). We are tasked with finding \(|f|^2\), which is the modulus squared of this complex function.
02

Definition of Modulus Squared

The modulus (or magnitude) squared of a complex number \( z \) is defined as \(|z|^2 = z \overline{z}\), where \(\overline{z}\) is the complex conjugate of \(z\). The complex conjugate is formed by changing the sign of the imaginary part.
03

Find the Complex Conjugate of \(f\)

Given \( f(x, y) = (x - i y) \ln(x + i y) \), its complex conjugate is \( \overline{f}(x, y) = (x + i y) \overline{\ln(x + i y)} \). However, here we need to consider the specific operations through \(x - i y\) and \(x + i y\) factors.
04

Multiply by the Complex Conjugate

Compute \( f \cdot \overline{f} \). When \( f(x, y) = (x - i y) \ln(x + i y) \), its magnitude, when squared, directly results in combining the real and imaginary components to fully amplify the magnitude details.
05

Simplification (acknowledgment/adjustment)

Note that \(|f|^2\) is intended to yield the square of real contributions from both real and imaginary components of \(x - i y\) and \(x + i y\). The problem requires shifting the lens to the original targets: real representation dynamics energetically enforcing to recognize modulus operations kinetics.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Conjugate
In complex analysis, the complex conjugate of a complex number plays a crucial role in various calculations and simplifications. For a complex number expressed as \(z = a + bi\), where \(a\) and \(b\) are real numbers, the complex conjugate, denoted as \(\overline{z}\), is given by \(a - bi\). This means you simply change the sign of the imaginary part.
This concept is essential when working with complex numbers because it helps in calculating the modulus or magnitude and in simplifying mathematical expressions involving complex numbers. When you multiply a complex number by its conjugate, you effectively neutralize the imaginary part, which comes in handy during modulus calculations.
For example, in the context of our function \(f(x, y) = (x - i y) \ln(x + i y)\), the complex conjugate involves reversing the sign of the imaginary component in \((x + i y)\). This alters the expression to something which can be directly computed for modulus applications.
Modulus Squared
The modulus squared of a complex number is basically the square of its magnitude. For a complex number \(z = a + bi\), its modulus \(|z|\) is defined as \(\sqrt{a^2 + b^2}\). Therefore, the modulus squared \(|z|^2\) becomes \(a^2 + b^2\).
The modulus squared is widely used because it provides a simple way to express the power and direction of a complex number without worrying about the square root. Mathematically, it is calculated by multiplying the complex number by its conjugate:
  • \(|z|^2 = z \overline{z} = (a + bi)(a - bi) = a^2 + b^2\)
In reference to the function \(f(x, y) = (x - i y) \ln(x + i y)\), calculating \(|f|^2\) involves considering both the real and imaginary components and multiplying them appropriately by their conjugates to discover the full magnitude of the function without imaginary interference.
Complex-Valued Function
A complex-valued function is a function that takes real inputs and returns complex outputs. This type of function is integral in many fields of mathematics, especially in complex analysis and engineering. Complex-valued functions often involve calculations that deal with both the real and imaginary components jointly rather than separately.
The function \(f(x, y) = (x - i y) \ln(x + i y)\) is an example of a complex-valued function that involves complex numbers both within its structure and in its output.
When analyzing such functions, the challenge lies in dealing with the imaginary unit \(i\), which adds depth and dimension to the calculations. These functions yield complex results by mapping two real inputs, \(x\) and \(y\), to a complex plane, showing the unity of real and imaginary elements. Understanding how to work with these functions is essential for tackling complex problems involving oscillation and wave dynamics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) A particle with mass \(m\) has kinetic energy equal to three times its rest encrgy. What is the de Broglic wavelength of this particle? (Hint: You must use the relativistic expressions for momentum and kinetic energy: \(E^{2}=(p c)^{2}+\left(m c^{2}\right)^{2}\) and \(K=E-\) \(m c^{2} \cdot(b)\) Determine the numerical value of the kinetic energy (in Mev) and the wavelength (in meters) if the particle in part (a) is (i) an electron and (i) a proton.

Imagine another universe in which the value of Planck's constant is \(0.0663 \mathrm{J} \cdot \mathrm{s},\) but in which the physical laws and all other physical constants are the same as in our universe. In this universe, two physics students are playing catch. They are 12 \(\mathrm{m}\) apart, and one throws a \(0.25-\mathrm{kg}\) ball directly toward the other with a speed of 6.0 \(\mathrm{m} / \mathrm{s}\) (a) What is the uncertainty in the ball's horizontal momentum, in a direction perpendicular to that in which it is being thrown, if the student throwing the ball knows that it is located within a cube with volume 125 \(\mathrm{cm}^{3}\) at the time she throws it? (b) By what horizontal distance could the ball miss the second student?

An electron has a de Broglie wavelength of \(2.80 \times 10^{-10} \mathrm{m}\) . Determine (a) the magnitude of its momentum and \((b)\) its kinetic energy (in joules and in electron volts).

(a) What is the energy of a photon that has wavelength 0.10\(\mu \mathrm{m} ?\) (b) Through approximately what potential difference must electrons be accelerated so that they will exhibit wave nature in passing through a pinhole 0.10\(\mu \mathrm{m}\) in diameter? What is the speed of these electruns? (c) If protons rather than electrons were used, through what potential difference would protons have to be accelerated so they would exhibit wave nature in passing through this pinhole? What would be the speed of these protons?

You want to study a biological spocimen by mcans of a wavelength of \(10.0 \mathrm{nm},\) and you have a choice of using electromagnetic waves or an electron microscope. (a) Calculate the ratio of the energy of a 10.0 -nm- wavelength photon to the kinetic energy of a 10.0 -nm-wavelength electron. (b) In view of your answer to part (a), which would be less damaging to the specimen you are studying; photons or electrons?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.