/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 The \(\psi\) (psin) particle has... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The \(\psi\) (psin) particle has a rest energy of 3097 MeV \(\left(1 \mathrm{MeV}=10^{6} \mathrm{eV}\right) .\) The \(\psi\) particle is unstable with a lifetime of \(7.6 \times 10^{-21} \mathrm{s}\) . Estimate the uncertainty in rest energy of the \(\psi\) particle. Express your answer in MeV and as a fraction of the rest energy of the particle.

Short Answer

Expert verified
Uncertainty is 4.33 MeV, which is 0.14% of the rest energy.

Step by step solution

01

Identify the Formula

We need to use the Heisenberg Uncertainty Principle for energy and time: \ \( \Delta E \times \Delta t \geq \frac{\hbar}{2} \) \ where \( \Delta E \) is the uncertainty in energy, \( \Delta t \) is the uncertainty in time (lifetime of the particle), and \( \hbar \) is the reduced Planck's constant \( \hbar = 1.05457 \times 10^{-34} \text{ J}\cdot\text{s} \).
02

Convert Units

Convert the Planck's constant \( \hbar \) to MeV\cdot\text{s} using \( 1 \text{ J} = 6.242 \times 10^{12} \text{ MeV} \). \[ \hbar = 1.05457 \times 10^{-34} \text{ J}\cdot\text{s} \times 6.242 \times 10^{12} \text{ MeV/J} \approx 6.5821 \times 10^{-22} \text{ MeV}\cdot\text{s} \]
03

Solve for Uncertainty in Energy

Using the Heisenberg Uncertainty Principle equation: \[ \Delta E \geq \frac{\hbar}{2 \Delta t} \]Substitute the given values: \[ \Delta t = 7.6 \times 10^{-21} \text{ s} \] \[ \Delta E \geq \frac{6.5821 \times 10^{-22}}{2 \times 7.6 \times 10^{-21}} \approx 4.33 \text{ MeV} \]
04

Calculate Fraction of Rest Energy

The rest energy \( E_0 \) of the particle is 3097 MeV. Calculate the fraction: \[ \text{Fraction} = \frac{\Delta E}{E_0} = \frac{4.33}{3097} \approx 0.0014 \] or 0.14%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy-Time Uncertainty
The principle of energy-time uncertainty is a fundamental concept derived from the Heisenberg Uncertainty Principle. This principle relates the uncertainty in energy (\( \Delta E \) ) to the uncertainty in time (\( \Delta t \)). It describes how these uncertainties are inversely related. That means if one is more precise, the other becomes less so. This relation is given by the equation:
\[ \Delta E \times \Delta t \geq \frac{\hbar}{2} \]
Here, \( \hbar \) is the reduced Planck's constant, a very small number indicating the tiny scales of quantum mechanics.
In practical terms, this principle tells us that a particle with a shorter lifetime will have a higher uncertainty in its energy. This is particularly important in
  • nuclear physics,
  • particle physics,
  • and quantum mechanics.
The instability of particles such as the \( \psi \) particle, with a very short lifetime, results in a significant energy uncertainty. Understanding this helps in predicting and explaining the behavior of subatomic particles.
Particle Physics
Particle physics is a branch of physics that studies the smallest components of matter and radiation and how they interact. It's often called "high-energy physics" because it involves interactions at extremely high energy levels. Subatomic particles, the primary subjects of study in this field, include:
  • Electrons
  • Protons
  • Neutrons
  • Quarks
  • Gluons
The \(\psi\) particle mentioned here is an example of a meson, specifically a type of quark-antiquark combination.
In particle physics experiments, scientists use huge particle accelerators to collide particles at velocities near the speed of light. These collisions can inform us about the fundamental forces of nature and the constitution of matter. This field of physics relies heavily on the concepts of quantum mechanics, such as energy-time uncertainty, to analyze and make sense of experimental results.
The study of unstable particles like the \(\psi\) particle helps physicists gain deeper insights into the forces that govern the universe.
Reduced Planck's Constant
The reduced Planck's constant, denoted as \(\hbar\), is obtained by dividing the Planck constant \(h\) by \(2\pi\) (hence sometimes called the "h-bar"). It embodies the quantum scale in many physics equations. Its value is approximately \[ \hbar = 1.05457 \times 10^{-34} \text{ J}\cdot\text{s} \]
This constant is pivotal in quantum mechanics, serving as a bridge between macroscopic and quantum worlds. It allows us to link the realm of classical physics with quantum phenomena.
  • In the context of the Heisenberg Uncertainty Principle, \(\hbar\) establishes a minimum limit on the product of uncertainties—in position and momentum, or in energy and time.
  • It's central to the principle that certain pairs of physical properties cannot be simultaneously known to arbitrary precision.
Without \(\hbar\), understanding the precise scale at which quantum effects become significant would be difficult. It's a fundamental constant in equations predicting how subatomic particles behave, like in Schrödinger's equation and in our energy-time uncertainty scenario for the \(\psi\) particle.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Imagine another universe in which the value of Planck's constant is \(0.0663 \mathrm{J} \cdot \mathrm{s},\) but in which the physical laws and all other physical constants are the same as in our universe. In this universe, two physics students are playing catch. They are 12 \(\mathrm{m}\) apart, and one throws a \(0.25-\mathrm{kg}\) ball directly toward the other with a speed of 6.0 \(\mathrm{m} / \mathrm{s}\) (a) What is the uncertainty in the ball's horizontal momentum, in a direction perpendicular to that in which it is being thrown, if the student throwing the ball knows that it is located within a cube with volume 125 \(\mathrm{cm}^{3}\) at the time she throws it? (b) By what horizontal distance could the ball miss the second student?

A 10.0 -g marble is gently placed on a horizontal tabletop that is 1.75 \(\mathrm{m}\) wide. (a) What is the maximum uncertainty in the horizontal position of the marble? (b) According to the Heisenberg uncertainty principle. what is the minimum uncertainty in the horizontal velocity of the marble? (c) In light of your answer to part (b), what is the longest time the marble could remain on the table? Compare this time to the age of the universe, which is approximately 14 billion years. (Hint Can you know that the horizontal velocity of the marble is exactly zero?)

Atomic Spectra Uncertainties. A certain atom has an energy level \(2.58 \mathrm{cV}\) above the ground level. Once excited to this Ievel, the atom remains in this level for \(1.04 \times 10^{-7} \mathrm{~s}\) (on average) before emitting a photon and returning to the ground level. (a) What is the energy of the photon (in electron volts)? What is its wavelength (in nanomcters)? (b) What is the smallest possible uncertainty in energy of the photon? Give your answer in electron volts. (c) Show that \(|\Delta E| E|=| \Delta \lambda / \lambda \mid\) if \(|\Delta \lambda / \lambda|<1 .\) Use this to calculate the magnitude of the smallest possible uncertainty in the wavelength of the photon. Give your answer in nanometers.

A particle moving in one dimension (the \(x\) -axis) is described by the wave function $$ \psi(x)=\left\\{\begin{array}{ll} A e^{-b x}, & \text { for } x \geq 0 \\ A e^{k x}, & \text { for } x<0 \end{array}\right. $$ where \(b=2.00 \mathrm{~m}^{-1}, A>0,\) and the \(+x\) -axis points toward the right. (a) Determine \(A\) so that the wave function is normalized. (b) Sketch the graph of the wave function. (c) Find the probability of finding this particle in cach of the following regions: (i) within \(50.0 \mathrm{~cm}\) of the origin, (ii) on the left side of the origin (can you first guess the answer by looking at the graph of the wave function?), (iit) betwcen \(x=0.500 \mathrm{mand} x=1.00 \mathrm{~m}\)

You want to study a biological spocimen by mcans of a wavelength of \(10.0 \mathrm{nm},\) and you have a choice of using electromagnetic waves or an electron microscope. (a) Calculate the ratio of the energy of a 10.0 -nm- wavelength photon to the kinetic energy of a 10.0 -nm-wavelength electron. (b) In view of your answer to part (a), which would be less damaging to the specimen you are studying; photons or electrons?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.