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X rays with initial wavelength 0.0665 nm undergo Compton scattering. What is the longest wavelength found in the scattered x rays? At which scattering angle is this wavelength observed?

Short Answer

Expert verified
The longest wavelength is 0.07136 nm, observed at a scattering angle of 180°.

Step by step solution

01

Identify the Problem

This is a physics problem involving Compton scattering. We need to find the longest wavelength of the scattered X-rays and the corresponding scattering angle.
02

Compton Effect Equation Formulation

The shift in wavelength (\(\Delta \lambda\)) due to Compton scattering is given by the equation: \[\Delta \lambda = \lambda' - \lambda = \frac{h}{mc} (1 - \cos \theta)\] where \(\lambda'\) is the scattered wavelength, \(\lambda\) is the initial wavelength, \(h\) is Planck's constant (\(6.626 \times 10^{-34} \text{ Js}\)), \(m\) is the electron rest mass (\(9.11 \times 10^{-31} \text{ kg}\)), \(c\) is the speed of light (\(3 \times 10^{8} \text{ m/s}\)), and \(\theta\) is the scattering angle.
03

Calculate Maximum Wavelength Shift

To find the longest wavelength, \(\lambda'\), we need the maximum value of \(1-\cos\theta\). The maximum value is 2, achieved when \(\theta = 180^\circ\).
04

Substitute Known Values

Substitute the known values into the equation for maximum wavelength shift:\[\Delta \lambda = \frac{6.626 \times 10^{-34}}{9.11 \times 10^{-31} \times 3 \times 10^{8}} \times 2 \approx 4.86 \times 10^{-12} \text{ m}\]
05

Calculate Longest Wavelength

Add the initial wavelength and the maximum wavelength shift to find the longest wavelength in the scattered X-rays:\[\lambda' = 0.0665 \text{ nm} + 0.00486 \text{ nm} = 0.07136 \text{ nm}\]
06

Determine Scattering Angle

Since the maximum wavelength shift occurs at \(\theta = 180^\circ\), the scattering angle for the longest wavelength is \(180^\circ\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

X-ray Wavelength
X-rays are a form of electromagnetic radiation with very short wavelengths. They sit between ultraviolet light and gamma rays on the electromagnetic spectrum, often ranging from about 0.01 to 10 nanometers (nm). In the exercise, we've encountered an X-ray with an initial wavelength of 0.0665 nm. This incredibly small wavelength allows X-rays to pass through most materials and makes them especially useful in medical imaging and materials science for detecting structural details.
X-rays differ from light waves we see with our eyes, not just in their wavelengths, but also in their energies and penetrative abilities. The shorter the wavelength, the higher the energy of the X-ray and the greater its potential to penetrate materials. To fully understand the implications of their interactions with matter, it's essential to be aware of changes they undergo like scattering.
Wavelength Shift
Wavelength shift in context with Compton scattering refers to the change in the wavelength of X-rays after they collide with electrons. This shift occurs because the X-ray photons lose some of their energy to the electrons, which alters their wavelengths. The key factor is the shift formula from the original wavelength to the scattered wavelength:
  • Initial wavelength: \( \lambda \)
  • Scattered wavelength: \( \lambda' \)
  • Wavelength shift: \( \Delta \lambda \)
The equation for the Compton wavelength shift is:\[\Delta \lambda = \lambda' - \lambda = \frac{h}{mc}(1 - \cos \theta)\]Here each variable represents:
  • \(h\) is Planck's constant (\( 6.626 \times 10^{-34} \) Js)
  • \(m\) is the electron rest mass (\( 9.11 \times 10^{-31} \) kg)
  • \(c\) is the speed of light (\( 3 \times 10^{8} \) m/s)
  • \(\theta\) is the scattering angle
This subtle change in wavelength plays a significant role in material analysis and provides insights into particle interactions on a quantum scale.
Scattering Angle
The scattering angle \( \theta \) is a critical factor in determining the extent of the wavelength shift in Compton scattering. This angle is the measure of deviation in the direction of the X-ray after it collides with an electron. As \( \theta \) changes, so does the value of \(1 - \cos \theta\), directly influencing the wavelength shift.
For the longest possible wavelength, the maximum value of \(1 - \cos \theta\), which is 2, occurs when \( \theta \) is 180°. At this angle, the X-ray is scattered back in the exact opposite direction, resulting in the greatest energy loss and hence the largest increase in wavelength. This phenomenon is central in exploring how particles like X-rays behave when interacting with matter.
Planck's Constant
Planck's constant \(h\) is a fundamental constant in quantum mechanics, and it plays a vital role in the study of electromagnetic radiation. Its value is approximately \( 6.626 \times 10^{-34} \) Joule-seconds. This small, crucial constant bridges the gap between the macroscopic and quantum worlds, offering insight into photon behaviors and energies.
In the Compton effect, Planck's constant helps relate the energy of the X-ray photons to their wavelength changes. Together with the speed of light \(c\) and the electron rest mass \(m\), it allows us to calculate how much an X-ray's wavelength will shift during scattering. Recognizing the role of Planck's constant is key to understanding broader principles in physics, including the quantization of electromagnetic radiation.

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Most popular questions from this chapter

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