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Protons are accelerated from rest by a potential difference of 4.00 \(\mathrm{kV}\) and strike a metal target. If a proton produces one photon on impact, what is the minimum wavelength of the resulting x rays? How does your answer compare to the minimum wave-length if \(4.00-\mathrm{keV}\) electrons are used instead? Why do x-ray tubes use electrons rather than protons to produce x rays? use electrons rather than protons to produce x rays?

Short Answer

Expert verified
Both protons and 4.00 keV electrons produce x-rays with a wavelength of \(3.11 \times 10^{-10} \text{m}\). Electrons are preferred due to easier acceleration and practicality.

Step by step solution

01

Understanding the Problem

We need to find the minimum wavelength of x-rays produced when protons are accelerated by a 4.00 kV potential difference and compare it with that produced by electrons with the same energy. We then need to consider why electrons are preferred for x-ray production.
02

Calculate Energy Acquired by Protons

When a proton is accelerated from rest by a potential difference of 4.00 kV, it gains kinetic energy equal to the energy given by the potential difference: \( E_p = e \times V = 1.6 \times 10^{-19} \text{C} \times 4.00 \times 10^3 \text{V} = 6.4 \times 10^{-16} \text{J} \).
03

Convert Energy to Minimum Wavelength

The energy of the photon produced is equal to the kinetic energy of the proton. Use the energy-wavelength relation: \( E = \frac{hc}{\lambda} \). Solve for \( \lambda \): \( \lambda = \frac{hc}{E} \). \( h = 6.626 \times 10^{-34} \text{Js}, \ c = 3.00 \times 10^8 \text{m/s} \). The calculated wavelength is \( \lambda_p = \frac{6.626 \times 10^{-34} \times 3.00 \times 10^8}{6.4 \times 10^{-16}} = 3.11 \times 10^{-10} \text{m} \).
04

Calculate Wavelength for Electrons

For electrons with 4.00 keV energy, convert to joules: \( E_e = 4.00 \times 1.6 \times 10^{-19} \times 10^3 \text{J} = 6.4 \times 10^{-16} \text{J} \). Use the same energy-wavelength relation: \( \lambda_e = \frac{hc}{E_e} = \frac{6.626 \times 10^{-34} \times 3.00 \times 10^8}{6.4 \times 10^{-16}} = 3.11 \times 10^{-10} \text{m} \).
05

Compare Differences in Context of Production

While the minimum wavelengths are the same, electrons are used instead of protons because they are easier to accelerate to high speeds, allowing for practical and efficient x-ray production. Electrons also have a smaller mass, reducing the machinery's size and cost compared to what would be needed to use protons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy an object has due to its motion. In the context of x-ray production, both protons and electrons gain kinetic energy when they are accelerated by a potential difference. This energy is crucial because it is converted into electromagnetic radiation, such as x-rays, when the particles strike a metal target.
For a proton or electron initially at rest and accelerated through a potential difference of 4,000 volts (4 kV), the kinetic energy acquired can be calculated using the formula:
  • \( E = e \times V \)
  • Where \( e \) is the charge of the particle (about \( 1.6 \times 10^{-19} \text{C} \)), and \( V \) is the potential difference.
This relationship allows us to calculate that both the proton and electron gain the same amount of kinetic energy, allowing their different masses to impact later processes differently.
Photon Wavelength
When a proton or electron hits a metal target, the particle's kinetic energy is transformed into a photon. The wavelength of this photon is inversely related to its energy. This is described by the equation:
  • \( E_{photon} = \frac{hc}{\lambda} \)
  • Where \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \text{Js} \)) and \( c \) is the speed of light (\( 3.00 \times 10^8 \text{m/s} \)).
By rearranging the equation, we find the wavelength \( \lambda \) of the photon:
  • \( \lambda = \frac{hc}{E} \)
Applying the same kinetic energy value for both protons and electrons yields the same minimum wavelength. However, the efficiency and practicality of using either for x-ray production differ.
Electron Acceleration
Electrons are negatively charged particles and are relatively easy to accelerate. With their much smaller mass compared to protons, electrons reach higher velocities under the same potential difference. This makes them highly effective in x-ray tubes.
Due to being lighter, electrons require less energy to reach sufficient speeds to produce x-rays. This means:
  • The machinery used is smaller and less costly.
  • The electrons can be controlled more efficiently, improving x-ray production.
  • Both Ease of acceleration and smaller size make electrons the preferred choice for x-ray generation.
Overall, these advantages make electron-accelerated machines more common in medical and scientific settings.
Proton Acceleration
Protons, in contrast to electrons, are heavier and positively charged. When accelerated by the same potential difference, protons gain the same amount of kinetic energy as electrons. However, because they are heavier, they do not achieve the high velocities that electrons do.
This difference manifests in several practical challenges:
  • Proton acceleration requires larger and more advanced equipment, leading to higher costs.
  • Protons are harder to handle and control efficiently.
  • The increased mass means it is more difficult to produce focused and efficient x-ray beams.
These limitations are why protons are not typically used for x-ray production, despite having comparable kinetic energy to electrons.

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