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Two particles in a high-energy accelerator experiment are approaching each other head-on, each with a speed of 0.9520\(c\) as measured in the laboratory. What is the magnitude of the velocity of one particle relative to the other?

Short Answer

Expert verified
The relative velocity is approximately 0.99868c.

Step by step solution

01

Understand the Scenario

Two particles are moving toward each other, each with a speed of 0.9520\(c\), where \(c\) is the speed of light, in the laboratory frame. We seek the velocity of one particle as seen from the frame of the other particle.
02

Use the Relativistic Velocity Addition Formula

In relativistic physics, velocities are not combined simply by addition. We use the relativistic velocity addition formula: \[ v_{rel} = \frac{v_1 + v_2}{1 + \frac{v_1 v_2}{c^2}} \] where \(v_1 = 0.9520c\) and \(v_2 = -0.9520c\) because they are moving towards each other.
03

Substitute the Values into the Formula

Substitute \(v_1 = 0.9520c\) and \(v_2 = -0.9520c\) into the formula: \[ v_{rel} = \frac{0.9520c + (-0.9520c)}{1 + \frac{0.9520c \times (-0.9520c)}{c^2}} \].
04

Simplify the Expression

Simplify the expression: \[ v_{rel} = \frac{0.9520c - 0.9520c}{1 - \frac{(0.9520c)^2}{c^2}} = \frac{0}{1 - \frac{0.906304}{1}} = \frac{0}{0.093696} = 0\].
05

Correct Calculation Rearrangement

Notice the calculation mistake in simplification. Calculate using: \[ v_{rel} = \frac{0.9520c + 0.9520c}{1 + \frac{(0.9520c)^2}{c^2}} \].
06

Correct Final Calculation

Recalculate correctly: \[ v_{rel} = \frac{0.9520c + 0.9520c}{1 + \frac{(0.9520c imes 0.9520c)}{c^2}} = \frac{1.9040c}{1 + 0.906304} \approx \frac{1.9040c}{1.906304} \approx 0.99868c \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding High-Energy Physics
High-energy physics, often known as particle physics, explores the fundamental particles of the universe and the forces governing them. In this realm, experiments such as particle collisions at accelerators allow scientists to study conditions similar to those just after the Big Bang. These experiments necessitate speeds approaching the speed of light.
To handle these extreme conditions, classical physics cannot suffice. Newtonian mechanics, which deals with everyday speeds, does not account for the changes in measurements like mass, time, or velocity that occur at these high energies.
Physicists hence rely on theories like Einstein's theory of relativity to describe and predict outcomes at these scales. Key factors include:
  • Increased mass of particles as their speed approaches that of light.
  • Time dilation, where time appears to slow down for fast-moving particles.
  • Relativistic effects that alter velocity calculations, making them non-intuitive.
Understanding these principles is vital when analyzing high-speed particles in environments like accelerators.
Relativistic Physics and its Implications
Relativistic physics comes into play when particles move at speeds comparable to the speed of light. In this domain, Einstein's special theory of relativity redefines core concepts of motion and measurement. This theoretical framework allows us not only to expand our understanding beyond classical mechanics but also empowers us to accurately predict phenomena at high velocities.
A central idea in relativistic physics is that the laws of physics are the same for all observers, regardless of their relative motion. This principle leads to surprising conclusions such as:
  • The constancy of the speed of light, which remains the same in all inertial frames irrespective of the observer's motion.
  • Mass-energy equivalence, embodied in the iconic equation \(E=mc^2\), which states that mass can be converted into energy and vice versa.
  • Altered perceptions of space and time where measurements such as length and duration can vary with speed.
These principles enable us to predict the effects observed in high-energy experiments and are pivotal to the design and operation of modern particle accelerators.
Concept of Velocity Transformation
The concept of velocity transformation is crucial in understanding how velocities are measured in different reference frames, especially in relativistic contexts. Unlike Newtonian physics where velocities add up linearly, relativistic physics offers a correction through the relativistic velocity addition formula.
Here's how it works: when dealing with particles moving at relativistic speeds (close to the speed of light), the relative velocity \(v_{rel}\) is given by the formula:\[v_{rel} = \frac{v_1 + v_2}{1 + \frac{v_1 v_2}{c^2}}.\]This equation accounts for the fact that no physical object can exceed the speed of light when measured in any inertial frame.
For example, in the exercise involving particles moving towards each other at 0.9520\(c\), the velocity transformation ensures that their relative speed doesn't simply add up to 1.9040\(c\), as one might initially think. Instead, it results in a more accurate value of approximately 0.99868\(c\), reflecting the constraints of light-speed limits.
This understanding is imperative for accurately determining relative velocities in high-energy physics experiments, ensuring precise measurements and interpretations.

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Most popular questions from this chapter

A cube of metal with sides of length \(a\) sits at rest in a frame \(S\) with one edge parallel to the \(x\) -axis. Therefore, in \(S\) the cube has volume \(a^{3} .\) Frame \(S^{\prime}\) moves along the \(x\) -axis with a speed \(u\) . As measured by an observer in frame \(S^{\prime},\) what is the volume of the metal cube?

A particle with mass \(m\) accelerated from rest by a constant force \(F\) will, according to Newtonian mechanics, continue to accelerate without bound; that is, as \(t \rightarrow \infty, v \rightarrow \infty .\) Show that according to relativistic mechanics, the particle's speed approaches \(c\) as \(t \rightarrow \infty\) . I Note: Auseful integralis \(\int\left(1-x^{2}\right)^{-3 / 2} d x=x / \sqrt{1-x^{2}} \cdot 1\)

Frame \(S^{\prime}\) has an \(x\) -component of velocity \(u\) relative to frame S, and at \(t=t^{\prime}=0\) the two frames coincide (see Fig. 37.3\()\) . A light pulse with a spherical wave front is emitted at the origin of \(S^{\prime}\) at time \(t^{\prime}=0 .\) Its distance \(x^{\prime}\) from the origin after a time \(t^{\prime}\) is given by \(x^{\prime 2}=c^{2} t^{\prime 2} .\) Use the Lorentz coordinate ransformation to S, and at \(t=t^{\prime}=0\) the two frames coincide (see Fig. 37.3\()\) . A light pulse with a spherical wave front is emitted at the origin of \(S^{\prime}\) at time \(t^{\prime}=0 .\) Its distance \(x^{\prime}\) from the origin after a time \(t^{\prime}\) is given by \(x^{\prime 2}=c^{2} t^{\prime 2} .\) Use the Lorentz coordinate ransformation to be spherical in both frames.

In proton-antiproton annihilation a proton and an antiproton (a negatively charged proton) collide and disappear, producing electromagnetic radiation. If cach particle has a mass of \(1.67 \times 10^{-27} \mathrm{kg}\) and they are at rest just before the annihilation, find the total energy of the radiation. Give your answers in joules and in electron volts.

How fast must a rocket travel relative to the earth so that time in the rocket "slows down" to half its rate as measured by earth-based observers? Do present-day jet planes approach such speeds?

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