/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 The microwaves in a certain micr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The microwaves in a certain microwave oven have a wavelength of \(12.2 \mathrm{cm} .\) (a) How wide must this oven be so that it will contain five antinodal planes of the electric field along its width in the standing wave pattern? (b) What is the frequency of these microwaves? (c) Suppose a manufacturing error occurred and the oven was made 5.0 \(\mathrm{cm}\) longer than specificd in part (a). In this case, what would have to be the frequency of the microwaves for there still to be five antinodal planes of the electric field along the width of the oven?

Short Answer

Expert verified
(a) 48.8 cm (b) 2.46 GHz (c) 2.23 GHz

Step by step solution

01

Understanding Antinodal Planes

Antinodal planes occur where the amplitude of the standing wave is maximum. For a given width of the oven, five antinodal planes require four complete wavelengths across the width of the oven.
02

Calculate Required Width of the Oven

Since five antinodal planes correspond to four complete cycles of the wave, the width of the oven must be four times the wavelength of the microwaves. Given the wavelength as \(12.2\, \text{cm}\), the required oven width is: \[ \text{Width} = 4 \times 12.2\, \text{cm} = 48.8\, \text{cm} \]
03

Calculate the Frequency of Microwaves

The frequency \(f\) of a wave is given by the formula \(f = \frac{c}{\lambda}\), where \(c\) is the speed of light \((3 \times 10^8\, \text{m/s})\) and \(\lambda\) is the wavelength \((12.2\, \text{cm} = 0.122\, \text{m})\). Thus, \[ f = \frac{3 \times 10^8\, \text{m/s}}{0.122\, \text{m}} = 2.46 \times 10^9\, \text{Hz} \]
04

Adjust Oven Width Due to Manufacturing Error

The oven width was made 5.0 cm longer than calculated in Step 2. Therefore, the new width of the oven is: \[ \text{New Width} = 48.8\, \text{cm} + 5.0\, \text{cm} = 53.8\, \text{cm} \]
05

Calculate New Frequency for Modified Oven

To maintain five antinodal planes, with the new width of 53.8 cm, the microwave wavelength must be such that four wavelengths fit in this width. Letting \(\lambda'\) be the new wavelength, \[ 4\lambda' = 53.8\, \text{cm} \Rightarrow \lambda' = \frac{53.8}{4} = 13.45\, \text{cm} \]Converting to meters, \(\lambda' = 0.1345\, \text{m}\). The new frequency \(f'\) is then: \[ f' = \frac{3 \times 10^8\, \text{m/s}}{0.1345\, \text{m}} = 2.23 \times 10^9\, \text{Hz} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standing Wave
Standing waves are quite fascinating. They form when two waves of the same frequency and amplitude travel in opposite directions and interfere with each other. This results in the creation of fixed points, called nodes and antinodes.
A node is where the wave has zero amplitude, while an antinode is where the wave reaches its maximum amplitude.
Standing waves can occur in a variety of physical contexts, such as strings, air columns, and microwave ovens.
  • In a microwave oven, the microwaves reflect off the walls, setting up standing wave patterns inside the oven.
  • This allows for certain predictable points in space where the energy concentration, or intensity, is strongest.
When cooking food, it's these antinodal regions where energy is intensely focused, allowing food to cook evenly if placed correctly. Understanding this helps in designing the oven dimensions to match specific standing wave patterns.
Wavelength
The wavelength of a wave is the distance between consecutive crests or troughs. It's a core concept in understanding wave behavior and is crucial in applications like microwaves.
The wavelength is symbolized by the Greek letter \( \lambda \) and typically measured in meters.
  • In the context of a microwave, shorter wavelengths mean more waves fit in the same space, leading to different standing wave patterns.
  • In our exercise, with microwaves having a wavelength of \(12.2\, \text{cm}\), the aim is to fit complete wavelengths—as many as needed—across the width of the oven.
For practical purposes like designing a microwave oven, knowing the number of wavelengths required for certain antinodal configurations helps determine the ideal size of the cavity that will efficiently heat the food.
Frequency Calculation
Frequency is another essential property of waves, indicating how many wave cycles pass a point per second. It is measured in hertz (Hz). The equation \( f = \frac{c}{\lambda} \) links frequency \( f \) with the speed of light \( c \) (approximately \(3 \times 10^8\, \text{m/s}\) for microwaves) and wavelength \( \lambda \).

To calculate frequency:
  • First, identify the wavelength of the microwaves, which will be in meters for calculations.
  • With \( c \) and \( \lambda \) known, use the formula to find \( f \).
In the exercise solution, the given wavelength is \(0.122\, \text{m}\), so the frequency becomes \( f = \frac{3 \times 10^8\, \text{m/s}}{0.122\, \text{m}} = 2.46 \times 10^9\, \text{Hz} \).
This frequency determines how much energy the microwaves carry and consequently how effective they are at heating food in the oven. Understanding this principle is crucial for designing equipment that relies on microwave technology.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) How much time does it take light to travel from the moon to the earth, a distance of \(384,000 \mathrm{km}\) ? (b) Light from the star Sirius takes 8.61 years to reach the earth. What is the distance from earth to Sirius in kilometers?

A sinusoidal electromagnetic wave of frequency \(6.10 \times 10^{14} \mathrm{Hz}\) travels in vacuum in the \(+z\) -direction. The \(\overrightarrow{\boldsymbol{B}}\) -field is parallel to the \(y\) -axis and has amplitude \(5.80 \times 10^{-4}\) T. Write the vector equations for \(\overrightarrow{\boldsymbol{E}}(z, t)\) and \(\overrightarrow{\boldsymbol{B}}(z, t) .\)

If the intensity of direct sunlight at a point on the earth's surface is \(0.78 \mathrm{kW} / \mathrm{m}^{2},\) find \((\mathrm{a})\) the average momentum density (momentum per unit volume) in the sunlight and (b) the average momentum flow rate in the sunlight.

A satellite 575 \(\mathrm{km}\) above the earth's surface transmits sinusoidal electromagnetic waves of frequency 92.4 \(\mathrm{MHz}\) uniformly in all directions, with a power of 25.0 \(\mathrm{kW}\) . (a) What is the intensity of these waves as they reach a receiver at the surface of the earth directly below the satellite? (b) What are the amplitudes of the electric and magnetic fields at the receiver? (c) If the receiver has a totally absorbing panel measuring 15.0 \(\mathrm{cm}\) by 40.0 \(\mathrm{cm}\) oriented with its plane perpendicular to the direction the waves travel, what average force do these waves exert on the panel? Is this force large enough to cause significant effects?

An electromagnetic standing wave in air has frequency 75.0 MHz. (a) What is the distance between nodal planes of the \(\overrightarrow{\boldsymbol{E}} \) field? (b) What is the distance between a nodal plane of \(\vec{E}\) and the closest nodal plane of \(\overrightarrow{\boldsymbol{B}} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.